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Test: Discrete Time Signals & Useful Signals - Electrical Engineering (EE) MCQ


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20 Questions MCQ Test Signals and Systems - Test: Discrete Time Signals & Useful Signals

Test: Discrete Time Signals & Useful Signals for Electrical Engineering (EE) 2024 is part of Signals and Systems preparation. The Test: Discrete Time Signals & Useful Signals questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The Test: Discrete Time Signals & Useful Signals MCQs are made for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Discrete Time Signals & Useful Signals below.
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Test: Discrete Time Signals & Useful Signals - Question 1

The function y[n] = sin(x[n]) is periodic 

Detailed Solution for Test: Discrete Time Signals & Useful Signals - Question 1

‘y’ will be periodic only if x attains the same value after some time, T. However, if x is a one-one discrete function, it may not be possible for some x[n].

Test: Discrete Time Signals & Useful Signals - Question 2

 What is the time period of the function x[n] = exp(jwn)?

Detailed Solution for Test: Discrete Time Signals & Useful Signals - Question 2

Using Euler’s rule, exp(2pi*n) = 1 for all integer n. Thus, the answer can be derived.

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Test: Discrete Time Signals & Useful Signals - Question 3

A time invariant system is a system whose output

Detailed Solution for Test: Discrete Time Signals & Useful Signals - Question 3

A time invariant system’s output should be directly related to the time of the output. There should be no scaling, i.e. y(t) = f(x(t)).

Test: Discrete Time Signals & Useful Signals - Question 4

 Is the function y[n] = x[n-1] – x[n-4] memoryless?

Detailed Solution for Test: Discrete Time Signals & Useful Signals - Question 4

Since the function needs to store what it was at a time 4 units and 1 unit before the present time, it needs memory.

Test: Discrete Time Signals & Useful Signals - Question 5

Is the function y[n] = y[n-1] + x[n] stable in nature?

Detailed Solution for Test: Discrete Time Signals & Useful Signals - Question 5

It is BIBO stable in nature, i.e. bounded input-bounded output stable.

Test: Discrete Time Signals & Useful Signals - Question 6

We define y[n] = nx[n] – (n-1)x[n]. Now, z[n] = z[n-1] + y[n], is z[n] stable?

Detailed Solution for Test: Discrete Time Signals & Useful Signals - Question 6

As we take the sum of y[n], terms cancel out and deem z[n] to be BIBO stable.

Test: Discrete Time Signals & Useful Signals - Question 7

 We define y[n] = nx[n] – (n-1)x[n]. Now, z[n] = z[n-1] + y[n]. Is z[n] a causal system?

Detailed Solution for Test: Discrete Time Signals & Useful Signals - Question 7

As the value of the function depends solely on the value of the input at a time presently and/or in the past, it is a causal system.

Test: Discrete Time Signals & Useful Signals - Question 8

 What is the value of d[0], such that d[n] is the unit impulse function?

Detailed Solution for Test: Discrete Time Signals & Useful Signals - Question 8

The unit impulse function has value 1 at n = 0 and zero everywhere else.

Test: Discrete Time Signals & Useful Signals - Question 9

What is the value of u[1], where u[n] is the unit step function?

Detailed Solution for Test: Discrete Time Signals & Useful Signals - Question 9

The unit step function u[n] = 1 for all n>=0, hence u[1] = 1.

Test: Discrete Time Signals & Useful Signals - Question 10

Evaluate the following function in terms of t: {sum from -1 to infinity:d[n]}/{Integral from 0 to t: u(t)}

Detailed Solution for Test: Discrete Time Signals & Useful Signals - Question 10

The numerator evaluates to 1, and the denominator is t, hence the answer is 1/t.

Test: Discrete Time Signals & Useful Signals - Question 11

Evaluate the following function in terms of t: {integral from 0 to t}{Integral from -inf to inf}d(t)

Detailed Solution for Test: Discrete Time Signals & Useful Signals - Question 11

The first integral is 1, and the overall integral evaluates to t.

Test: Discrete Time Signals & Useful Signals - Question 12

The fundamental period of exp(jwt) is

Detailed Solution for Test: Discrete Time Signals & Useful Signals - Question 12

The function assumes the same value after t+2pi/w, hence the period would be 2pi/w.

Test: Discrete Time Signals & Useful Signals - Question 13

Find the magnitude of exp(jwt). Find the boundness of sin(t) and cos(t).

Detailed Solution for Test: Discrete Time Signals & Useful Signals - Question 13

The sin(t)and cos(t) can be found using Euler’s rule.

Test: Discrete Time Signals & Useful Signals - Question 14

Find the value of {sum from -inf to inf} exp(jwn)*d[n].

Detailed Solution for Test: Discrete Time Signals & Useful Signals - Question 14

The expression {sum from -inf to inf} exp(jwn)*d[n] is equal to 1, since d[n] is equal to 1 when n = 0 and 0 otherwise. The sum can then be simplified to the form of a geometric series, which has a sum of 2.

The sum will exist only for n = 0, for which the product will be 1.

Test: Discrete Time Signals & Useful Signals - Question 15

Compute d[n]d[n-1] + d[n-1]d[n-2] for n = 0, 1, 2.

Detailed Solution for Test: Discrete Time Signals & Useful Signals - Question 15

Only one of the values can be one at a time, others will be forced to zero, due to the delta function.

Test: Discrete Time Signals & Useful Signals - Question 16

Defining u(t), r(t) and s(t) in their standard ways, are their derivatives defined at t = 0?

Detailed Solution for Test: Discrete Time Signals & Useful Signals - Question 16

 None of the derivatives are defined at t=0.

Test: Discrete Time Signals & Useful Signals - Question 17

Which is the correct Euler expression?

Detailed Solution for Test: Discrete Time Signals & Useful Signals - Question 17

Euler rule: exp(jt) = cos(t) + jsin(t).

Test: Discrete Time Signals & Useful Signals - Question 18

A linear time invariant (LTI) system is said to be stable if ________.

Detailed Solution for Test: Discrete Time Signals & Useful Signals - Question 18

Stability of LTI system:

A linear time-invariant (LTI) system is said to be stable if:

  1. The bounded input sequence always produces a bounded output sequence.
  2. Its natural response approaches zero as time approaches infinity.
  3. All the poles of the system lie on the left-hand side of the jω axis.
  4. The impulse response of an LTI system is absolutely summable i.e. 

The response of a stable LTI system is:

Test: Discrete Time Signals & Useful Signals - Question 19

Exponential signal is an example of _________ signal.

Detailed Solution for Test: Discrete Time Signals & Useful Signals - Question 19

Deterministic signal:

  • A signal is said to be deterministic if there is no uncertainty with respect to its value at any instant of time.
  • The signals which can be defined exactly by a mathematical formula are known as deterministic signals.
  • Example- sin (t), cos (t), eat 

Non-deterministic signal:

  • The behavior of these signals is random i.e. not predictable w.r.t time.
  • There is an uncertainty with respect to its value at any time.
  • These signals can't be expressed mathematically.
  • Example: Thermal Noise generated is a non-deterministic signal.

Periodic signal:

  • A periodic signal is a signal that repeats its values at regular intervals.
  • A periodic is expressed as x(t) = x(t + to)
  • Example- sin (t), cos (t)

Non-Periodic signal:

  • A non-periodic signal is any signal that does not repeat itself after any period of time.
  • Example- speech signal, eat
Test: Discrete Time Signals & Useful Signals - Question 20

If x(t) is a continuous signal and 'A' is a constant, then x(At) = ?

Detailed Solution for Test: Discrete Time Signals & Useful Signals - Question 20

Concept:

Basic linear operations are given below-

  • Multiplication of input signal with a constant value: y(t) = Ax(t)
  • Time-shifting the input signal y(t) = x(t−t1)
  • Scaling of the input signal y(t) = x(At)
  • Combinations of scaling, shifting and multiplication , e.g. y(t) = Ax(b(t−t1))
  • Summations of terms that are linear, e.g. y(t) = Ax(t)+x(t−t1)
  • Convolution of two input signal, eg y(t) = x(t)*h(t)

Some non-linear operations are given below:

  • Multiplication of the signal with itself, i.e. y(t) = x(t)⋅x(t)
  • Applying any non-linear function to the signal, e.g. y(t) = sin(x(t))
  • Adding constant terms, which are independent of the signal, i.e. y(t) = x(t)+A
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