Test: Electrostatic Potential and Capacitance - 1 - CUET Humanities MCQ

The electron is moving from low potential to high potential, using conservation of energy.
Increase in the kinetic energy = Decreases in the potential energy
(1/2) mv² = eV
⇒ v = = 
= 2.65 x 10⁶ m/s

The last three capacitors on the right, each of capacitance C = 9 μF, are in series and are equivalent to a capacitance C' given by 
Since C' is parallel to C₁, the equivalent capacitance of the last part of the network is C'' = C' + C₁ = 3 + 6 = 9μF.Continuing this process of calculation towards the left, we notice that we are finally left with the combination whose equivalent capacitance is 3 μF. Hence, the correct option is (1).

We may take the plates to be connected as shown in the figure. Let E₂₃ be the electric field between plates 2 and 3.
We have, 

Let the potential difference between plates 1 and 2 be V'.
Between 2 and 3, potential difference is V.
Between 3 and 4, potential difference is V', so V' + V + V' = 0.
So, the total potential difference across the extreme plates is zero.
Hence, we have

As the separation between the plates is the same, i.e. d, then the magnitude of the electric field between plates 1 and 2 is

Similarly, the electric field between plates 3 and 4

E = (1/2) CV²  ...(i)
The energy stored in capacitor is lost in form of heat energy.
H = ms ΔT …(ii)
From Eqs. (i) and (ii), we have

Charge on C₁ is Q₁ = C₁V = CV. This charge is shared by the three capacitors. The equivalent capacitance of the series combination of C₂ and C₃ is 

The common potential of C₁ and C' is 

∴ Charge that will flow through the connecting wires is 

Electrostatic potential energy is inversely proportional to r. Hence, as r decreases, the electrostatic potential energy increases.

Capacity of capacitor, C = q/V
Or V = q/C ⇒ V ∝ (1/C) 
When the dielectric medium is inserted between the plates of capacitor, the capacity of capacitor will increase.
So, the electrostatic potential of capacitor will decrease.

Plate 1 is connected to plate 3, and plate 2 is connected to plate 4. Thus, there are three capacitors in parallel, each of capacitance .
Hence, the equivalent capacitance , which is option 3.

not possible.