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Test: Factors And Multiples- 2 - GMAT MCQ


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15 Questions MCQ Test Quantitative for GMAT - Test: Factors And Multiples- 2

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Test: Factors And Multiples- 2 - Question 1

Which of the following CANNOT be the greatest common divisor of two positive integers a and b

Detailed Solution for Test: Factors And Multiples- 2 - Question 1

The greatest common divisor (GCD) of two positive integers a and b is the largest positive integer that divides both a and b without leaving a remainder.

Out of the given options, the only number that cannot be the GCD of two positive integers a and b is option 4, a - 2b.

To see why, consider the following example: let a = 10 and b = 4. The factors of 10 are 1, 2, 5, and 10, and the factors of 4 are 1, 2, and 4. The common factors of 10 and 4 are 1 and 2, and the greatest common factor is 2.

Now, if we substitute a = 10 and b = 4 into the expression a - 2b, we get:

a - 2b = 10 - 2(4) = 2

Since 2 is the GCD of 10 and 4, it is possible for a - 2b to be the GCD of two positive integers. However, there are other cases where a - 2b is not the GCD of two positive integers, so it cannot be concluded that a - 2b is always a valid option for the GCD of two positive integers.

Therefore, the correct answer is option 4, a - 2b.

Test: Factors And Multiples- 2 - Question 2

Which of the following CANNOT be the greatest common divisor of two different prime numbers a and b

Detailed Solution for Test: Factors And Multiples- 2 - Question 2

Understanding the GCD of Two Different Primes

  • Definition of Primes: Prime numbers are integers greater than 1 that have no positive divisors other than 1 and themselves.
  • GCD of Two Different Primes: Since a and b are different primes, their only common positive divisor is 1. Therefore, the GCD of a and b is 1.

Evaluating Each Option

Option a) a - b

  • Possible Valuea - b can be 1 when a and b are consecutive primes.
  • Example: Let a = 3 and b = 2.
    • a - b = 1
  • Conclusiona - b can be 1, so it can be the GCD of a and b.

Option b) b - a

  • Possible Valueb - a can be 1 when b and a are consecutive primes.
  • Example: Let a = 2 and b = 3.
    • b - a = 1
  • Conclusionb - a can be 1, so it can be the GCD of a and b.

Option c) 2a - b

  • Possible Value2a - b can be 1 depending on the values of a and b.
  • Example: Let a = 2 and b = 3.
    • 2a - b = 4 - 3 = 1
  • Conclusion2a - b can be 1, so it can be the GCD of a and b.

Option d) a + b

  • Possible Value: Since a and b are primes greater than 1, a + b will be at least 2 + 3 = 5.
  • GCD Analysis: The GCD of a and b is 1, and the GCD cannot be larger than the smallest of the two numbers.
  • Conclusiona + b cannot be 1 and cannot be the GCD of a and b.

Answer

Option d) a + b cannot be the greatest common divisor of two different prime numbers a and b.

Option D: a + b

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Test: Factors And Multiples- 2 - Question 3

Which of the following can be the greatest common divisor of two prime numbers a and b

Detailed Solution for Test: Factors And Multiples- 2 - Question 3

t means any two prime numbers will have only one common factor and that would be '1', as per the definitions of prime number and highest common factor. Hence, any two different prime numbers will have the highest common factor as '1'. It means the H.C.F. of given two prime numbers a and b is 1.

Test: Factors And Multiples- 2 - Question 4

Which of the following CANNOT be the least common multiple of two integers a and b, where a and b are both greater than 1

Test: Factors And Multiples- 2 - Question 5

Which of the following can be the least common multiple of two distinct integers a and b? 

Test: Factors And Multiples- 2 - Question 6

What is the value of integer x?

1)  The lowest common multiple of x and 16 is 48. ?

2)  The greatest common factor of x and 16 is 4. 

Test: Factors And Multiples- 2 - Question 7

What is the value of integer x?

1)  The lowest common multiple of x and 7 is 28. ?

2)  The greatest common factor of x and 7 is 1. 

Detailed Solution for Test: Factors And Multiples- 2 - Question 7


Test: Factors And Multiples- 2 - Question 8

If 375y = x2 and x and y are positive integers, then which of the following must be an integer? 

I. y/15
II. y/30
III. y2/25 

Detailed Solution for Test: Factors And Multiples- 2 - Question 8

375 = (3)(5)(5)(5) = (3)(5)(5²)
In order for 375y to be a perfect square, the prime factorization of y must contain at least one 3 and one 5.
In other words, y must be a multiple of 15.

If y is a multiple of 15, then y/15 must be an integer and y²/25 must be an integer.

Test: Factors And Multiples- 2 - Question 9

If x, y, and z are distinct prime numbers, how many positive factors does (xy)z have?

1)  z = 5 ?

2)  x + y = 10 

Test: Factors And Multiples- 2 - Question 10

If x, y, and z are distinct integers, how many positive factors does (xy)z have? (D)

1)  z = 5 ?

2)  x + y = 10 

Test: Factors And Multiples- 2 - Question 11

If a, b, and c are positive integers and (a/6) + (b/5) = (c/30), is c divisible by 5?

1) b is divisible by 5

2) a is even

Test: Factors And Multiples- 2 - Question 12

If x and y are nonzero integers, is x/y an integer?

1)  x is the product of 2 and another integer. ?

2)  There is only one pair of positive integers whose product equals y. ?

Test: Factors And Multiples- 2 - Question 13

If x and y are nonzero integers, is x/y an integer?

(1) x is the product of 2 and some other integer.
(2) There is only one pair of positive integers whose product equals y.

Detailed Solution for Test: Factors And Multiples- 2 - Question 13

Test: Factors And Multiples- 2 - Question 14

What is the value of x?

1)  x has exactly 3 factors. 

2)  10 < x < 45 

Detailed Solution for Test: Factors And Multiples- 2 - Question 14


Test: Factors And Multiples- 2 - Question 15

Can a batch of identical cookies be split evenly between Laurel and Jean without leftovers and without breaking a cookie?
1) If the batch of cookies were split among Laurel, Jean and Marc, there would be one cookie left over.
2) If Peter eats three of the cookies before they are split, there will be no leftovers when the cookies are split evenly between Laurel and Jean.

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