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Test: Ferromagnetic Core Inductor in a DC Circuit - Electrical Engineering (EE) MCQ


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10 Questions MCQ Test Basic Electrical Technology - Test: Ferromagnetic Core Inductor in a DC Circuit

Test: Ferromagnetic Core Inductor in a DC Circuit for Electrical Engineering (EE) 2024 is part of Basic Electrical Technology preparation. The Test: Ferromagnetic Core Inductor in a DC Circuit questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The Test: Ferromagnetic Core Inductor in a DC Circuit MCQs are made for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Ferromagnetic Core Inductor in a DC Circuit below.
Solutions of Test: Ferromagnetic Core Inductor in a DC Circuit questions in English are available as part of our Basic Electrical Technology for Electrical Engineering (EE) & Test: Ferromagnetic Core Inductor in a DC Circuit solutions in Hindi for Basic Electrical Technology course. Download more important topics, notes, lectures and mock test series for Electrical Engineering (EE) Exam by signing up for free. Attempt Test: Ferromagnetic Core Inductor in a DC Circuit | 10 questions in 10 minutes | Mock test for Electrical Engineering (EE) preparation | Free important questions MCQ to study Basic Electrical Technology for Electrical Engineering (EE) Exam | Download free PDF with solutions
Test: Ferromagnetic Core Inductor in a DC Circuit - Question 1
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When a ferromagnetic core is inserted into an inductor, what happens to the flux linkage?

Detailed Solution for Test: Ferromagnetic Core Inductor in a DC Circuit - Question 1

When a ferromagnetic core is introduced into an inductor, its flux increases because the number of magnetic field lines increase due to the introduction of a magnetic within the coil.

Test: Ferromagnetic Core Inductor in a DC Circuit - Question 2
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What happens to the current when a ferromagnetic material is introduced within an inductor?

Detailed Solution for Test: Ferromagnetic Core Inductor in a DC Circuit - Question 2

When a ferromagnetic is introduced within an inductor, the current remains fairly constant. This is because the current does not depend on the magnetic field.

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Test: Ferromagnetic Core Inductor in a DC Circuit - Question 3
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What is the relation between the flux and the magnetizing current when a ferromagnetic core is introduced within the inductor?

Detailed Solution for Test: Ferromagnetic Core Inductor in a DC Circuit - Question 3

When a ferromagnetic core is introduced within an inductor the flux changes rapidly, whereas the current changes at the same pace. Hence the two are not proportional.

Test: Ferromagnetic Core Inductor in a DC Circuit - Question 4
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What happens to the effective inductance when a ferromagnetic core is introduced?
Detailed Solution for Test: Ferromagnetic Core Inductor in a DC Circuit - Question 4

The effective inductance increases when a ferromagnetic core is introduced within an inductor because the flux increases. Inductance varies directly with the flux hence it increases.

Test: Ferromagnetic Core Inductor in a DC Circuit - Question 5
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A laminated steel ring is wound with 200 turns. When the magnetizing current varies between 5 and 7 A, the magnetic flux varies between 760 and 800 ∫Wb. Calculate the incremental inductance of the coil.
Detailed Solution for Test: Ferromagnetic Core Inductor in a DC Circuit - Question 5

From the formula of incremental inductance, we know that:
L=(Change in flux/Change in current)*Number of turns
Substituting the values from the given question, we get L= 0.004H.

Test: Ferromagnetic Core Inductor in a DC Circuit - Question 6
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Calculate the number of turns in an inductor with a ferromagnetic core when the inductance is 0.004H, the current changes from 5A to 7A and the flux changes from 760 to 800 ∫Wb.
Detailed Solution for Test: Ferromagnetic Core Inductor in a DC Circuit - Question 6

From the formula of incremental inductance, we know that:
L=(Change in flux/Change in current)*Number of turns
Substituting the values from the given question, we get N=200.

Test: Ferromagnetic Core Inductor in a DC Circuit - Question 7
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Calculate the change in current in an inductor having inductance 0.004H, number of turns is 200 and the flux changes from 760 to 800 ∫Wb.
Detailed Solution for Test: Ferromagnetic Core Inductor in a DC Circuit - Question 7

From the formula of incremental inductance, we know that:
L=(Change in flux/Change in current)*Number of turns
Substituting the values from the given question, we get change in current= 2A.

Test: Ferromagnetic Core Inductor in a DC Circuit - Question 8
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Calculate the initial current in an inductor having inductance 0.004H, number of turns is 200 and the flux changes from 760 to 800 ∫Wb. Current changes to 7A.
Detailed Solution for Test: Ferromagnetic Core Inductor in a DC Circuit - Question 8

From the formula of incremental inductance, we know that:
L=(Change in flux/Change in current)*Number of turns
Substituting the values from the given question, we get change in current= 2A.
Change in current= final current- initial current.
2=7-initial current.
Initial current= 5A.

Test: Ferromagnetic Core Inductor in a DC Circuit - Question 9
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Calculate the chance in flux of an inductor having inductance 0.004H, number of turns is 200 and the current changes from 5A to 7A.
Detailed Solution for Test: Ferromagnetic Core Inductor in a DC Circuit - Question 9

From the formula of incremental inductance, we know that:
L=(Change in flux/Change in current)*Number of turns
Substituting the values from the given question, we get change in flux= 40∫Wb.

Test: Ferromagnetic Core Inductor in a DC Circuit - Question 10
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Calculate the final flux in an inductor having inductance 0.004H, number of turns is 200 and the current changes from 5A to 7A. The initial flux is 760∫Wb.
Detailed Solution for Test: Ferromagnetic Core Inductor in a DC Circuit - Question 10

From the formula of incremental inductance, we know that:
L=(Change in flux/Change in current)*Number of turns
Substituting the values from the given question, we get change in flux= 40∫Wb.
Change in flux= final flux- initial flux.
Thus final flux= 800∫Wb.

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