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Test: Ferromagnetic Core Inductor in a DC Circuit - Electrical Engineering (EE) MCQ


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10 Questions MCQ Test Basic Electrical Technology - Test: Ferromagnetic Core Inductor in a DC Circuit

Test: Ferromagnetic Core Inductor in a DC Circuit for Electrical Engineering (EE) 2024 is part of Basic Electrical Technology preparation. The Test: Ferromagnetic Core Inductor in a DC Circuit questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The Test: Ferromagnetic Core Inductor in a DC Circuit MCQs are made for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Ferromagnetic Core Inductor in a DC Circuit below.
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Test: Ferromagnetic Core Inductor in a DC Circuit - Question 1

When a ferromagnetic core is inserted into an inductor, what happens to the flux linkage?

Detailed Solution for Test: Ferromagnetic Core Inductor in a DC Circuit - Question 1

When a ferromagnetic core is introduced into an inductor, its flux increases because the number of magnetic field lines increase due to the introduction of a magnetic within the coil.

Test: Ferromagnetic Core Inductor in a DC Circuit - Question 2

What happens to the current when a ferromagnetic material is introduced within an inductor?

Detailed Solution for Test: Ferromagnetic Core Inductor in a DC Circuit - Question 2

When a ferromagnetic is introduced within an inductor, the current remains fairly constant. This is because the current does not depend on the magnetic field.

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Test: Ferromagnetic Core Inductor in a DC Circuit - Question 3

What is the relation between the flux and the magnetizing current when a ferromagnetic core is introduced within the inductor?

Detailed Solution for Test: Ferromagnetic Core Inductor in a DC Circuit - Question 3

When a ferromagnetic core is introduced within an inductor the flux changes rapidly, whereas the current changes at the same pace. Hence the two are not proportional.

Test: Ferromagnetic Core Inductor in a DC Circuit - Question 4

What happens to the effective inductance when a ferromagnetic core is introduced?

Detailed Solution for Test: Ferromagnetic Core Inductor in a DC Circuit - Question 4

The effective inductance increases when a ferromagnetic core is introduced within an inductor because the flux increases. Inductance varies directly with the flux hence it increases.

Test: Ferromagnetic Core Inductor in a DC Circuit - Question 5

A laminated steel ring is wound with 200 turns. When the magnetizing current varies between 5 and 7 A, the magnetic flux varies between 760 and 800 ∫Wb. Calculate the incremental inductance of the coil.

Detailed Solution for Test: Ferromagnetic Core Inductor in a DC Circuit - Question 5

From the formula of incremental inductance, we know that:
L=(Change in flux/Change in current)*Number of turns
Substituting the values from the given question, we get L= 0.004H.

Test: Ferromagnetic Core Inductor in a DC Circuit - Question 6

Calculate the number of turns in an inductor with a ferromagnetic core when the inductance is 0.004H, the current changes from 5A to 7A and the flux changes from 760 to 800 ∫Wb.

Detailed Solution for Test: Ferromagnetic Core Inductor in a DC Circuit - Question 6

From the formula of incremental inductance, we know that:
L=(Change in flux/Change in current)*Number of turns
Substituting the values from the given question, we get N=200.

Test: Ferromagnetic Core Inductor in a DC Circuit - Question 7

Calculate the change in current in an inductor having inductance 0.004H, number of turns is 200 and the flux changes from 760 to 800 ∫Wb.

Detailed Solution for Test: Ferromagnetic Core Inductor in a DC Circuit - Question 7

From the formula of incremental inductance, we know that:
L=(Change in flux/Change in current)*Number of turns
Substituting the values from the given question, we get change in current= 2A.

Test: Ferromagnetic Core Inductor in a DC Circuit - Question 8

Calculate the initial current in an inductor having inductance 0.004H, number of turns is 200 and the flux changes from 760 to 800 ∫Wb. Current changes to 7A.

Detailed Solution for Test: Ferromagnetic Core Inductor in a DC Circuit - Question 8

From the formula of incremental inductance, we know that:
L=(Change in flux/Change in current)*Number of turns
Substituting the values from the given question, we get change in current= 2A.
Change in current= final current- initial current.
2=7-initial current.
Initial current= 5A.

Test: Ferromagnetic Core Inductor in a DC Circuit - Question 9

Calculate the chance in flux of an inductor having inductance 0.004H, number of turns is 200 and the current changes from 5A to 7A.

Detailed Solution for Test: Ferromagnetic Core Inductor in a DC Circuit - Question 9

From the formula of incremental inductance, we know that:
L=(Change in flux/Change in current)*Number of turns
Substituting the values from the given question, we get change in flux= 40∫Wb.

Test: Ferromagnetic Core Inductor in a DC Circuit - Question 10

Calculate the final flux in an inductor having inductance 0.004H, number of turns is 200 and the current changes from 5A to 7A. The initial flux is 760∫Wb.

Detailed Solution for Test: Ferromagnetic Core Inductor in a DC Circuit - Question 10

From the formula of incremental inductance, we know that:
L=(Change in flux/Change in current)*Number of turns
Substituting the values from the given question, we get change in flux= 40∫Wb.
Change in flux= final flux- initial flux.
Thus final flux= 800∫Wb.

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