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Test: General Properties of Group-16 (Oxygen, Ozone & Sulphur) - NEET MCQ


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25 Questions MCQ Test Chemistry Class 12 - Test: General Properties of Group-16 (Oxygen, Ozone & Sulphur)

Test: General Properties of Group-16 (Oxygen, Ozone & Sulphur) for NEET 2024 is part of Chemistry Class 12 preparation. The Test: General Properties of Group-16 (Oxygen, Ozone & Sulphur) questions and answers have been prepared according to the NEET exam syllabus.The Test: General Properties of Group-16 (Oxygen, Ozone & Sulphur) MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: General Properties of Group-16 (Oxygen, Ozone & Sulphur) below.
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Test: General Properties of Group-16 (Oxygen, Ozone & Sulphur) - Question 1

Direction (Q. Nos. 1-10) This section contains 10 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONLY ONE is correct.

Q. 

Which is incorrect statement?

Detailed Solution for Test: General Properties of Group-16 (Oxygen, Ozone & Sulphur) - Question 1

In tellurium, differentiating electron enters in to 5p subshell. Its valence shell configuration is 5s25p4.

Test: General Properties of Group-16 (Oxygen, Ozone & Sulphur) - Question 2

In earth’s crust, sulphur exists as

Detailed Solution for Test: General Properties of Group-16 (Oxygen, Ozone & Sulphur) - Question 2

Sulphur exists in elemental form which is extracted by Frasch process.
Sulphide ores are zinc blende (ZnS), galena (PbS), copper pyrites (CuFeS2), cinnabar (HgS),
Sulphate ores are gypsum (CaSO4. 2H2O), epsom (MgSO4 .7 H2O) .

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Test: General Properties of Group-16 (Oxygen, Ozone & Sulphur) - Question 3

The element used in the production of photocells and solar cells and also used in xerox machines is

Detailed Solution for Test: General Properties of Group-16 (Oxygen, Ozone & Sulphur) - Question 3

Se is non-conductor in dark but acts as conductor when exposed to light.

Test: General Properties of Group-16 (Oxygen, Ozone & Sulphur) - Question 4

The number of bond pairs and lone pairs in rhombic sulphur molecule are

Detailed Solution for Test: General Properties of Group-16 (Oxygen, Ozone & Sulphur) - Question 4

Test: General Properties of Group-16 (Oxygen, Ozone & Sulphur) - Question 5

Which has lowest bond energy (single bond)?

Detailed Solution for Test: General Properties of Group-16 (Oxygen, Ozone & Sulphur) - Question 5

Presence of lone pairs on bonded atoms generally lowers the bond energy.
Bond energy order is
O—O (146) < (S—S) (266) < S—H(366) < O—H(464) kJ/mol
 

Test: General Properties of Group-16 (Oxygen, Ozone & Sulphur) - Question 6

Harmful UV radiations emitted from the sun are prevented from reaching the earth by the presence of ozone in the

Detailed Solution for Test: General Properties of Group-16 (Oxygen, Ozone & Sulphur) - Question 6

Stratosphere layer strongly absorb harmful UV-radiations (λ. 255 nm).

Test: General Properties of Group-16 (Oxygen, Ozone & Sulphur) - Question 7

Point out the incorrect statement among the following.

Detailed Solution for Test: General Properties of Group-16 (Oxygen, Ozone & Sulphur) - Question 7

It is 369 K or 96°C. The stable form at room temperature is rhombic sulphur which transforms to monoclinic sulphur when heated about 369 K.

Test: General Properties of Group-16 (Oxygen, Ozone & Sulphur) - Question 8

The correct order of thermal stability of the hydrides of group 16 elements is

Detailed Solution for Test: General Properties of Group-16 (Oxygen, Ozone & Sulphur) - Question 8



Thermal stability ∝ bond dissociation energy 
(where, E = group 16 elements)
On moving down the group, bond dissociation energy decreases due to increase in bond length. Thus, the order of bond dissociation energy or thermal stability is 
H2O > H2S > H2Se > H2Te > H2PO

Test: General Properties of Group-16 (Oxygen, Ozone & Sulphur) - Question 9

When O2 changes to 

Detailed Solution for Test: General Properties of Group-16 (Oxygen, Ozone & Sulphur) - Question 9


Test: General Properties of Group-16 (Oxygen, Ozone & Sulphur) - Question 10

Increasing order of oxidation number of oxygen is found in

Detailed Solution for Test: General Properties of Group-16 (Oxygen, Ozone & Sulphur) - Question 10


*Multiple options can be correct
Test: General Properties of Group-16 (Oxygen, Ozone & Sulphur) - Question 11

Direction (Q. Nos. 11-15) This section contains 5 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONE or MORE THAN ONE are correct.

Q.  Which of the following property do not increase down the group from oxygen to polonium?

Detailed Solution for Test: General Properties of Group-16 (Oxygen, Ozone & Sulphur) - Question 11

Electron affinity and ionisation energy decreases down the group due to increase in size.

*Multiple options can be correct
Test: General Properties of Group-16 (Oxygen, Ozone & Sulphur) - Question 12

The correct statements among the following are

Detailed Solution for Test: General Properties of Group-16 (Oxygen, Ozone & Sulphur) - Question 12

In S8 molecule, sulphur has oxidation state is +2, +4, +6.

*Multiple options can be correct
Test: General Properties of Group-16 (Oxygen, Ozone & Sulphur) - Question 13

Which of the following statements regarding ozone are correct?

Detailed Solution for Test: General Properties of Group-16 (Oxygen, Ozone & Sulphur) - Question 13

Ozone is thermodynamically unstable w.r.t oxygen since, its decomposition into oxygen results in liberation of heat.

*Multiple options can be correct
Test: General Properties of Group-16 (Oxygen, Ozone & Sulphur) - Question 14

The correct statements among the following are

Detailed Solution for Test: General Properties of Group-16 (Oxygen, Ozone & Sulphur) - Question 14

The correct option is Option A, B and C.

Bond length is inversely proportional to bond order. O2+ has the highest bond order among these three, so it should have the shortest bond length.

Ozone is a powerful oxidizing agent as compared to oxygen. This is due to the unstable nature of ozone and the nascent oxygen that is released during the reaction.

O2 when gas makes others like H2 gas to lose electrons, therefore, O2 gas is an oxidizing agent and H2 when gas loses electrons in redox reaction, therefore H2 gas is a reducing agent.

Oxygen is more stable than ozone. On heating, ozone readily dissociates and forms oxygen and free radicals of oxygen known as nascent oxygen which take part in reaction, thus ozone is more reactive than oxygen

*Multiple options can be correct
Test: General Properties of Group-16 (Oxygen, Ozone & Sulphur) - Question 15

Which of the following do not stick to the poles of a magnet?

Detailed Solution for Test: General Properties of Group-16 (Oxygen, Ozone & Sulphur) - Question 15

Liquid oxygen is attracted to and actually sticks to the poles of the magnet. It is due to electron distribution as unpaired electrons are present while other do not stick to the poles of magnet.

Test: General Properties of Group-16 (Oxygen, Ozone & Sulphur) - Question 16

Direction (Q. Nos. 16 and 17) This section contains a paragraph, each describing theory, experiments, data, etc. Two questions related to the paragraphs have been given. Each question has only one correct answer among the four given options (a), (b), (c) and (d).

Passage

Sulphur and the rest of the elements of 16th group are less electronegative than oxygen. They can acquire ns2np6 by sharing two electrons with the atoms of other elements and thus, exhibit +2 oxidation state in their compounds, in addition to this, atoms have vacant d-orbitals in their valence shell due to which electrons I can be promoted from the s- and p-orbitals of the same shell. As a result, they can show +4 and +6 oxidation states. The oxidation states of elements never exceed +6.

Q.

Oxidation states of sulphur in H2S2O7 and H2S2O8 respectively are

Detailed Solution for Test: General Properties of Group-16 (Oxygen, Ozone & Sulphur) - Question 16

H2S2O7 has no peroxy bond while H2S2O8 has one peroxy bond.

 

Test: General Properties of Group-16 (Oxygen, Ozone & Sulphur) - Question 17

Passage

Sulphur and the rest of the elements of 16th group are less electronegative than oxygen. They can acquire ns2np6 by sharing two electrons with the atoms of other elements and thus, exhibit +2 oxidation state in their compounds, in addition to this, atoms have vacant d-orbitals in their valence shell due to which electrons I can be promoted from the s- and p-orbitals of the same shell. As a result, they can show +4 and +6 oxidation states. The oxidation states of elements never exceed +6.

Q. 

Like sulphur, oxygen does not show +4 and +6 oxidation states .The reason is

Detailed Solution for Test: General Properties of Group-16 (Oxygen, Ozone & Sulphur) - Question 17

Oxygen does not show +4 and +6 oxidation states because oxygen has no cf-orbitals in its valence shell.

Test: General Properties of Group-16 (Oxygen, Ozone & Sulphur) - Question 18

Direction (Q. Nos. 18-20) Choices for the correct combination of elements from Column I and Column II are given as options (a), (b), (c) and (d), out of which one is correct.

Q. 

Match the Column I with Column II and mark the correct option from the codes given below.

Detailed Solution for Test: General Properties of Group-16 (Oxygen, Ozone & Sulphur) - Question 18

Test: General Properties of Group-16 (Oxygen, Ozone & Sulphur) - Question 19

Match the Column I with Column II and mark the correct option from the codes given below.

Detailed Solution for Test: General Properties of Group-16 (Oxygen, Ozone & Sulphur) - Question 19

Test: General Properties of Group-16 (Oxygen, Ozone & Sulphur) - Question 20

Match the Column i with Column II and mark the correct option from the codes given below.

Detailed Solution for Test: General Properties of Group-16 (Oxygen, Ozone & Sulphur) - Question 20

*Answer can only contain numeric values
Test: General Properties of Group-16 (Oxygen, Ozone & Sulphur) - Question 21

Direction (Q. Nos. 21-24) This section contains 4 questions. When worked out will result in an integer from 0 to 9 (both inclusive).

Q. 

Number of chemicals that produce dioxygen on heating

KCIO3, (NH4)2 Cr2O7, NH4NO3, NaNO3, KMnO4, K2Cr2O7, H2O2, Pb3O4, NH4NO2


Detailed Solution for Test: General Properties of Group-16 (Oxygen, Ozone & Sulphur) - Question 21

(NH4)2 Cr2O7, NH4NO2 gives dinitrogen while NH4NO3 gives N2O.

*Answer can only contain numeric values
Test: General Properties of Group-16 (Oxygen, Ozone & Sulphur) - Question 22

In the fully excited state, number of unpaired electrons in tellurium are


Detailed Solution for Test: General Properties of Group-16 (Oxygen, Ozone & Sulphur) - Question 22


*Answer can only contain numeric values
Test: General Properties of Group-16 (Oxygen, Ozone & Sulphur) - Question 23

Number of chemical species having bent shape in 


Detailed Solution for Test: General Properties of Group-16 (Oxygen, Ozone & Sulphur) - Question 23

O3, NO2, SO2 and H2S show bent shape.

*Answer can only contain numeric values
Test: General Properties of Group-16 (Oxygen, Ozone & Sulphur) - Question 24

Among the following compounds, the number of compounds which have oxidation states of S is +4 ?

PbS, SO2, SF6, Na2S2O3, H2SO3


Detailed Solution for Test: General Properties of Group-16 (Oxygen, Ozone & Sulphur) - Question 24

The correct answer is 2.
Let S is in x oxidation state
In PbS, 2 + x = 0 =>  x = -2
In SO2 , x + 2 × (-2) = 0 => x= +4
In SF6 , x + 1 × (-6) = 0 => x = +6
In Na2S2O3, 2 ×(+1) + 2 × x + 3 × (-2) = 0 => x= +2

Test: General Properties of Group-16 (Oxygen, Ozone & Sulphur) - Question 25

Direction (Q. No. 25) This section is based on Statement I and Statement II. Select the correct answer from the codes given below.

Q. 

Statement I : Oxygen is more electronegative than sulphur, yet H2S is acidic, while H2O is neutral.

Statement II : H— S bond is weaker than O—H bond.

Detailed Solution for Test: General Properties of Group-16 (Oxygen, Ozone & Sulphur) - Question 25

H—S bond is weaker than H—O bond hence, H2S is more acidic than H2O.

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