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Test: Horizontal & Inclined Plane Surface Submerged in a Liquid - Mechanical Engineering MCQ


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10 Questions MCQ Test Fluid Mechanics for Mechanical Engineering - Test: Horizontal & Inclined Plane Surface Submerged in a Liquid

Test: Horizontal & Inclined Plane Surface Submerged in a Liquid for Mechanical Engineering 2024 is part of Fluid Mechanics for Mechanical Engineering preparation. The Test: Horizontal & Inclined Plane Surface Submerged in a Liquid questions and answers have been prepared according to the Mechanical Engineering exam syllabus.The Test: Horizontal & Inclined Plane Surface Submerged in a Liquid MCQs are made for Mechanical Engineering 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Horizontal & Inclined Plane Surface Submerged in a Liquid below.
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Test: Horizontal & Inclined Plane Surface Submerged in a Liquid - Question 1

Find the total pressure on a rectangular plate of dimensions 2×3 m immersed in a fluid of specific gravity 0.65 at a depth of 6 m from the surface. 

Detailed Solution for Test: Horizontal & Inclined Plane Surface Submerged in a Liquid - Question 1

Explanation: Total pressure, F=w*a*y
=9.81*650*6*2*3
=22.9 N/cm2.

Test: Horizontal & Inclined Plane Surface Submerged in a Liquid - Question 2

Find the total pressure on a circular plate of diameter 3 m immersed in a fluid of specific gravity 0.75 at a depth of 5 m from the surface on a planet having acceleration due to gravity 7 m/s2

Detailed Solution for Test: Horizontal & Inclined Plane Surface Submerged in a Liquid - Question 2

Explanation: Total pressure, F=w*a*y
=7*750*π*1.5*1.5*5
=18.5 N/cm2.

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Test: Horizontal & Inclined Plane Surface Submerged in a Liquid - Question 3

A rectangular plate surface 3m wide and 5m deep lies in fluid of specific gravity .9 such that its plane makes an angle of 45⁰ with water surface, upper edge 3m below free water surface. Determine the total pressure. 

Detailed Solution for Test: Horizontal & Inclined Plane Surface Submerged in a Liquid - Question 3

Explanation: Total pressure, F=w*a*ŷ=w*A*(y+dsinθ)=9.81*900*15*(3+5sin45)
=86.5 N/cm2.

Test: Horizontal & Inclined Plane Surface Submerged in a Liquid - Question 4

A rectangular plan surface 5 m wide and 7 m deep lies in water in such a way that its plane makes an angle 60⁰ with the free surface of water. Determine the total pressure force when the upper edge is 3 m below the free surface. 

Detailed Solution for Test: Horizontal & Inclined Plane Surface Submerged in a Liquid - Question 4

Explanation: Total pressure, F=w*a*ŷ=w*A*(y+dsinθ)=9.81*1000*35*(3+7sin60)=311.15 N/cm2.

Test: Horizontal & Inclined Plane Surface Submerged in a Liquid - Question 5

 A circular plate 5.0 m diameter is immersed in such a way that its greatest and least depth below the free surface are 3 m and 1 m respectively. determine the position of the centre of pressure.

Detailed Solution for Test: Horizontal & Inclined Plane Surface Submerged in a Liquid - Question 5

Explanation: centre of pressure, ŷ=I*sin²θ/Aĥ + ĥ
…….ĥ=(y+dsinθ)
=3.142*2.54*sin²23.58/3.142*2.52*(1+2.5sin23.58)+*(1+2.5sin23.58)
=2.5 m.

Test: Horizontal & Inclined Plane Surface Submerged in a Liquid - Question 6

 For an inclined plate the pressure intensity at every point differs.

Detailed Solution for Test: Horizontal & Inclined Plane Surface Submerged in a Liquid - Question 6

Explanation: Due to inclination the depth of every point is different from the free liquid surface. Hence, the pressure intensity varies with depth.

Test: Horizontal & Inclined Plane Surface Submerged in a Liquid - Question 7

The pressure intensity for a horizontal plate is maximum on the surface of the earth and decreases as we move further away from the surface of the earth either downward or upward.

Detailed Solution for Test: Horizontal & Inclined Plane Surface Submerged in a Liquid - Question 7

Explanation: As we move away from the surface of the earth either downward or upward g decreases, w decreases. Hence pressure intensity decreases.

Test: Horizontal & Inclined Plane Surface Submerged in a Liquid - Question 8

For an inclined plane for which position, maximum total pressure acts on it.

Detailed Solution for Test: Horizontal & Inclined Plane Surface Submerged in a Liquid - Question 8

Explanation: Total pressure, F=w*a*ŷ=w*A*(y+dsinθ)
For vertical plate, θ=90⁰
Hence, total pressure is maximum.

Test: Horizontal & Inclined Plane Surface Submerged in a Liquid - Question 9

The total pressure or pressure intensity is zero for any point on inclined surface in space.

Detailed Solution for Test: Horizontal & Inclined Plane Surface Submerged in a Liquid - Question 9

Explanation: Total pressure, F=w*a*ŷ
In space, w=0 as g=0
Hence, f=0.

Test: Horizontal & Inclined Plane Surface Submerged in a Liquid - Question 10

 In case of spherical bodies with uniform mass distribution, what is the position of center of pressure relative to centre of gravity.

Detailed Solution for Test: Horizontal & Inclined Plane Surface Submerged in a Liquid - Question 10

Explanation: In case of spherical bodies with uniform mass distribution, centre of pressure coincides with centre of gravity.

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