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Electronics and Communication Engineering (ECE) Exam  >  Electronics and Communication Engineering (ECE) Tests  >  Electromagnetics  >  Test: Inductances - Electronics and Communication Engineering (ECE) MCQ

Test: Inductances - Electronics and Communication Engineering (ECE) MCQ


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10 Questions MCQ Test Electromagnetics - Test: Inductances

Test: Inductances for Electronics and Communication Engineering (ECE) 2024 is part of Electromagnetics preparation. The Test: Inductances questions and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus.The Test: Inductances MCQs are made for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Inductances below.
Solutions of Test: Inductances questions in English are available as part of our Electromagnetics for Electronics and Communication Engineering (ECE) & Test: Inductances solutions in Hindi for Electromagnetics course. Download more important topics, notes, lectures and mock test series for Electronics and Communication Engineering (ECE) Exam by signing up for free. Attempt Test: Inductances | 10 questions in 10 minutes | Mock test for Electronics and Communication Engineering (ECE) preparation | Free important questions MCQ to study Electromagnetics for Electronics and Communication Engineering (ECE) Exam | Download free PDF with solutions
Test: Inductances - Question 1
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Calculate the emf of a coil with turns 100 and flux rate 5 units.

Detailed Solution for Test: Inductances - Question 1

Answer: d
Explanation: The emf is the product of the turns of the coil and the flux rate. Thus e = -N dφ/dt, where the negative sign indicates that the emf induced is opposing the flux. Thus e = -100 x 5 = -500 units.

Test: Inductances - Question 2
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The equivalent inductances of two coils 2H and 5H in series aiding flux with mutual inductance of 3H is

Detailed Solution for Test: Inductances - Question 2

Answer: d
Explanation: The equivalent inductance of two coils in series is given by L = L1 + L2 + 2M, where L1 and L2 are the self inductances and M is the mutual inductance. Thus L = 2 + 5 + 2(3) = 13H.

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Test: Inductances - Question 3
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The expression for the inductance in terms of turns, flux and current is given by

Detailed Solution for Test: Inductances - Question 3

Answer: a
Explanation: We know that e = -N dφ/dt and also e = -L di/dt. On equating both we get, L = Ndφ/di is the expression for inductance.

Test: Inductances - Question 4
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The equivalent inductance of two coils with series opposing flux having inductances 7H and 2H with a mutual inductance of 1H.
Detailed Solution for Test: Inductances - Question 4

Answer: b
Explanation: The equivalent inductance of two coils in series with opposing flux is L = L1 + L2 – 2M, where L1 and L2 are the self inductances and M is the mutual inductance. Thus L = 7 + 2 – 2(1) = 7H.

Test: Inductances - Question 5
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A coil is said to be loosely coupled with which of the following conditions?
Detailed Solution for Test: Inductances - Question 5

Answer: d
Explanation: k is the coefficient of coupling. It lies between 0 and 1. For loosely coupled coil, the coefficient of coupling will be very less. Thus the condition K<0.5 is true.

Test: Inductances - Question 6
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With unity coupling, the mutual inductance will be
Detailed Solution for Test: Inductances - Question 6

Answer: c
Explanation: The expression for mutual inductance is given by M = k √(L1 x L2), where k is the coefficient of coupling. For unity coupling, k = 1, then M = √(L1 x L2).

Test: Inductances - Question 7
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The inductance is proportional to the ratio of flux to current. State True/False. 
Detailed Solution for Test: Inductances - Question 7

Answer: a
Explanation: The expression is given by L = Ndφ/di. It can be seen that L is proportional to the ratio of flux to current. Thus the statement is true.

Test: Inductances - Question 8
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Calculate the mutual inductance of two tightly coupled coils with inductances 49H and 9H.
Detailed Solution for Test: Inductances - Question 8

Answer: a
Explanation: For tightly coupled coils, the coefficient of coupling is unity. Then the mutual inductance will be M = √(L1 x L2)= √(49 x 9) = 21 units.

Test: Inductances - Question 9
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Find the inductance of a coil with turns 50, flux 3 units and a current of 0.5A
Detailed Solution for Test: Inductances - Question 9

Answer: b
Explanation: The self inductance of a coil is given by L = Nφ/I, where N = 50, φ = 3 and I = 0.5. Thus L = 50 x 3/0.5 = 300 units.

Test: Inductances - Question 10
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The inductance of a coaxial cable with inner radius a and outer radius b, from a distance d, is given by
Detailed Solution for Test: Inductances - Question 10

Answer: a
Explanation: The inductance of a coaxial cable with inner radius a and outer radius b, from a distance d, is a standard formula derived from the definition of the inductance. This is given by L = μd ln(b/a)/2π.

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Important Questions for Inductances

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