Test: Integers - Class 7 MCQ

An integer on the horizontal number line is greater than the number on its left and less than the number on its right.
Therefore, here -1 will be greater than -5.

By Distributive law,
a x (b − c) = a x b - a x c
⇒ a x b - a x c = 8

Alternative method
a x b - a x c = 2 x 10 - 2 x 6
⇒ a x b - a x c = 20 - 12 = 8 [using BODMAS]

Thus, option D is the correct. 

The product of 3 negative integers will always be negative.
a * (-a) = -a²
(-a) * (-a) = a² 
(-a) * (-a) * (-a) = a² * (-a) = -a³

The additive identity property says that if you add an integer to zero or add zero to the integer, then you get the same integer back i.e. a + 0 = 0 + a = a.

Thus, 0 is an additive identity for the integers.

According to Distributive Law of Multiplication over Addition:
a x (b + c) = a x b + a x c 

correct option is A. 100

-20 x -5 = 100 [ when two -ve no multiply sign is +ve ]

The multiplicative identity of any integer p is a number q which when multiplied with p, leaves it unchanged, i.e. p × q = p.

Since, p × 1 = p = 1 × p
Therefore, 1 is the multiplicative identity for integers.

The additive inverse of a number x is the number that, when added to x, gives zero i.e. x + (-x) = 0.
This number is also known as the opposite number.

Thus, -7 is the additive inverse of 7.

The integers between -8 & 2 are: -7 , -6 , -5 , -4 , -3 , -2 , -1 , 0 , 1 

⇒ There are 9 integers between -8 & 2.

Firstly we will solve brackets according to BODMAS rule,
(-4) x (-9) x (-25) = -900
(-2) x (-3) x (-5) = -30

⇒ [(-4) x (-9) x (-25)] ÷ [(-2) x (-3) x (-5)]  = (-900)/(-30) = 30