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Test: Inverse Functions - Grade 12 MCQ


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10 Questions MCQ Test Mathematics for Grade 12 - Test: Inverse Functions

Test: Inverse Functions for Grade 12 2024 is part of Mathematics for Grade 12 preparation. The Test: Inverse Functions questions and answers have been prepared according to the Grade 12 exam syllabus.The Test: Inverse Functions MCQs are made for Grade 12 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Inverse Functions below.
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Test: Inverse Functions - Question 1

The solution to f(x) = f -1(x) are __________

Detailed Solution for Test: Inverse Functions - Question 1

Inverse of a function is the mirror image of function in line y = x.

Test: Inverse Functions - Question 2

For any function fof -1(x) is equal to?

Detailed Solution for Test: Inverse Functions - Question 2

Compostion of a function with its inverse gives x.

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Test: Inverse Functions - Question 3

If f is a function defined from R to R, is given by f(x) = x2 then f -1(x) is given by?

Detailed Solution for Test: Inverse Functions - Question 3

It is not a one one function hence Inverse does not exist.

Test: Inverse Functions - Question 4

If f is a function defined from R to R, is given by f(x) = 3x – 5 then f –1(x) is given by __________

Detailed Solution for Test: Inverse Functions - Question 4

y = 3x-5, x = (y+5)/3, f -1(x) = (x+5)/3.

Test: Inverse Functions - Question 5

A function f(x) is defined from A to B then f -1 is defined __________

Detailed Solution for Test: Inverse Functions - Question 5

Inverse associate each element in B with corresponding element in A.

Test: Inverse Functions - Question 6

If f(x) = y then f-1(y) is equal to __________

Detailed Solution for Test: Inverse Functions - Question 6

On giving inverse, image the function returns preimage thus f-1 (y) = x.

Test: Inverse Functions - Question 7

For an inverse to exist it is necessary that a function should be __________

Detailed Solution for Test: Inverse Functions - Question 7

Inverse exist only for those functions which are one one and onto.

Test: Inverse Functions - Question 8

The value of cot (sin–1 x) is

Detailed Solution for Test: Inverse Functions - Question 8

Let sin−1 x = θ , 
Then sinθ = x
⇒ cscθ = 1/x
⇒ csc2 θ = 1/x2
⇒1+ cot2 θ = 1/x2
⇒ cot = √(1 – x2) /x

Test: Inverse Functions - Question 9

If tan-1 √(1 + x2)-1 /x = 4, then

Detailed Solution for Test: Inverse Functions - Question 9

Substituting x=tanA
tan-1(sec A-1)/tanA = tan-1(1-cosA)/sinA
= tan-1(tan(A/2)).... Using cos A = 1-2sin2 A/2 
4°=A/2
tan −1(x)=8°
⇒ A= 8°
x =tan (8°)

Test: Inverse Functions - Question 10

What will be the value of x + y + z if cos-1 x + cos-1 y + cos-1 z = 3π?

Detailed Solution for Test: Inverse Functions - Question 10

The equation is cos-1 x + cos-1 y + cos-1 z = 3π
This means cos-1 x = π, cos-1 y = π and cos-1 z = π
This will be only possible when it is in maxima.
As, cos-1 x = π so, x = cos-1 π = -1 similarly, y = z = -1
Therefore, x + y + z = -1 -1 -1
So, x + y + z = -3.

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