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Test: JEE Previous Year Questions- Alcohols - JEE MCQ


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10 Questions MCQ Test Chemistry for JEE Main & Advanced - Test: JEE Previous Year Questions- Alcohols

Test: JEE Previous Year Questions- Alcohols for JEE 2025 is part of Chemistry for JEE Main & Advanced preparation. The Test: JEE Previous Year Questions- Alcohols questions and answers have been prepared according to the JEE exam syllabus.The Test: JEE Previous Year Questions- Alcohols MCQs are made for JEE 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: JEE Previous Year Questions- Alcohols below.
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Test: JEE Previous Year Questions- Alcohols - Question 1

Which of the following compounds undergoes maximum dehydration?

Detailed Solution for Test: JEE Previous Year Questions- Alcohols - Question 1
  • Dehydration of Alcohols: Dehydration involves removing a water molecule from an alcohol to form an alkene. The ease of dehydration follows the order: tertiary > secondary > primary alcohols due to carbocation stability.
  • Carbocation Stability: Option B forms a carbocation stabilized by resonance with a carbonyl group (C=O), enhancing stability and promoting dehydration.
  • Conjugation with (C=O): The resultant alkene in option B is conjugated with a carbonyl group, increasing its stability, thus promoting dehydration further compared to other options.

Test: JEE Previous Year Questions- Alcohols - Question 2

When CH2=CHCOOH is reduced with LiAlH4, the compound obtained will be  

Detailed Solution for Test: JEE Previous Year Questions- Alcohols - Question 2

The correct answer is option D

When CH2=CH−COOH is reduced with LiAlH4:

CH2=CH−CH2OH compound is formed because LiAlH4 reduces −COOH to CH2OH without affecting C=C bond. 

Test: JEE Previous Year Questions- Alcohols - Question 3

Among the following compounds which can be dehydrated very easily?

Detailed Solution for Test: JEE Previous Year Questions- Alcohols - Question 3

The ease of dehydration of alcohols is tertiary > secondary > primary according to the order of stability of the carbocations.

The more stable carbocation is generated, thus more easily it will be dehydrated.

Test: JEE Previous Year Questions- Alcohols - Question 4

For which of the following parameters the structural isomers C2H5OH and CH3OCH3 would be expected to have the same values ? (Assume ideal behaviour)  

Detailed Solution for Test: JEE Previous Year Questions- Alcohols - Question 4

Density of gas = (Mol. wt. × P) / (RT)

Since both isomers have same molecular mass and hence their densities will be same at same temperature and pressure.

Test: JEE Previous Year Questions- Alcohols - Question 5

HBr reacts with CH2 = CH – OCH3 under anhydrous conditions at room temperature to give 

Detailed Solution for Test: JEE Previous Year Questions- Alcohols - Question 5

Methyl vinyl ether is a very reactive gas. It is hydrolysed rapidly by dilute acids at room temperature to give methanol and aldehyde. However, under anhydrous conditions at room temperature, it undergoes many addition reactions at the double bond.

Electrophilic addition reaction more favourable.

Test: JEE Previous Year Questions- Alcohols - Question 6

In the following sequence of reactions, , what is compound D? 

Detailed Solution for Test: JEE Previous Year Questions- Alcohols - Question 6

Correct Answer is option C

  • When ethanol is treated with a mixture of phosphorus and iodine, ethyl iodide CH3​CH2​I is obtained. 
  • Compound A on reaction with Mg metal in ether forms ethyl magnesium iodide CH3​CH2​ MgI. 
  • The compound B reacts with formaldehyde to form compound C; CH3​CH2​−CH2​−OMgX which on hydrolysis gives n propyl alcohol CH3​CH2​CH2​−OH.
  • The compound D is n-propyl alcohol. 


 
Hence, option C is correct.

Test: JEE Previous Year Questions- Alcohols - Question 7

A liquid was mixed with ethanol and a drop of concentrated H2SO4 was added. A compound with a fruity smell was formed. The liquid was  

Detailed Solution for Test: JEE Previous Year Questions- Alcohols - Question 7

The fruity smell is evolved due to the formation of ester when ethanol and acid are treated in the presence of concentrated H2​SO4​.
The reaction is
CH3​COOH + CH3​CH2​OH → CH3​COOC2​H5​

Test: JEE Previous Year Questions- Alcohols - Question 8

From amongst the following alcohols the one that would react fastest with conc HCl and anhydrous ZnCl2 is

Detailed Solution for Test: JEE Previous Year Questions- Alcohols - Question 8

A mixture of conc.HCl and anhydrous ZnClis called Lucas reagent.

Primary alcohols react with Lucas reagent very slowly on heating to give alkyl chlorides.
Secondary alcohols react with Lucas reagent much faster.
Tertiary alcohols instantaneously react with HCl at room temperature.
 Note: Lucas reagent is required for primary and secondary alcohol only.

Test: JEE Previous Year Questions- Alcohols - Question 9

The main product of the following reaction is

   

Detailed Solution for Test: JEE Previous Year Questions- Alcohols - Question 9
  • Whenever dehydration can form two different alkenes major product is formed according to sides of rule that is more substituted alkene or alkene having lesson number of hydrogen atoms on the to double bonded carbon atoms is the major product. 
  • Such reactions which can produce two or more structural isomers but one of them in Greater amount than the others are called ratio selective encasa reaction is hundred percent regioselective it is termed as reduce specific
  • In addition to being reduced selective alcohol dehydration are stereoselective reaction in which a single starting material can yield two or more stereoisomeric products but give one of them in Greater amount than any other

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Test: JEE Previous Year Questions- Alcohols - Question 10

Consider the following reaction :

C2H5OH + H2SO4 → Product 

Among the following which one cannot be formed as a product under any conditions ?

Detailed Solution for Test: JEE Previous Year Questions- Alcohols - Question 10

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