Electrical Engineering (EE) Exam  >  Electrical Engineering (EE) Tests  >  Basic Electrical Technology  >  Test: Kirchhoff’s Laws & Network Solutions - Electrical Engineering (EE) MCQ

Test: Kirchhoff’s Laws & Network Solutions - Electrical Engineering (EE) MCQ


Test Description

15 Questions MCQ Test Basic Electrical Technology - Test: Kirchhoff’s Laws & Network Solutions

Test: Kirchhoff’s Laws & Network Solutions for Electrical Engineering (EE) 2024 is part of Basic Electrical Technology preparation. The Test: Kirchhoff’s Laws & Network Solutions questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The Test: Kirchhoff’s Laws & Network Solutions MCQs are made for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Kirchhoff’s Laws & Network Solutions below.
Solutions of Test: Kirchhoff’s Laws & Network Solutions questions in English are available as part of our Basic Electrical Technology for Electrical Engineering (EE) & Test: Kirchhoff’s Laws & Network Solutions solutions in Hindi for Basic Electrical Technology course. Download more important topics, notes, lectures and mock test series for Electrical Engineering (EE) Exam by signing up for free. Attempt Test: Kirchhoff’s Laws & Network Solutions | 15 questions in 10 minutes | Mock test for Electrical Engineering (EE) preparation | Free important questions MCQ to study Basic Electrical Technology for Electrical Engineering (EE) Exam | Download free PDF with solutions
Test: Kirchhoff’s Laws & Network Solutions - Question 1

​​​The algebraic sum of voltages around any closed loop circuit is equal to:

Detailed Solution for Test: Kirchhoff’s Laws & Network Solutions - Question 1

Sum of voltage drops + Sum of voltage rise = 0

Test: Kirchhoff’s Laws & Network Solutions - Question 2

In circuit below voltage V is:

​​​​​

Detailed Solution for Test: Kirchhoff’s Laws & Network Solutions - Question 2

Σ Voltage rise = Σ Voltage drop

12 V = 5 V + 3 V + V

V = 12 – 5 – 3 = 4 V

1 Crore+ students have signed up on EduRev. Have you? Download the App
Test: Kirchhoff’s Laws & Network Solutions - Question 3

The loop equation for central loop of circuit is:

Detailed Solution for Test: Kirchhoff’s Laws & Network Solutions - Question 3

According to Kirchhoff's Voltage Law:

V3 + V4 - V= 0

Hence,

V3 + V4 = V5

Test: Kirchhoff’s Laws & Network Solutions - Question 4

The value of unknown voltage source V1 in circuit given below is:

Resistor colors: Red Yellow Brown Gray

Detailed Solution for Test: Kirchhoff’s Laws & Network Solutions - Question 4

Resistor color coding: Red Yellow Brown Gray = 240 Ω ±10%

For resistor V = IR = 50 mA * 240 ohms = 12 V

Applying Kirchhoff’s voltage law:

Σ Voltage rise = Σ Voltage drop

V1 + 12 V = 12 V + 3 V + 5 V

V1 = 20 V – 12 V = 8 V

Test: Kirchhoff’s Laws & Network Solutions - Question 5

Which of the following expression correctly represents Kirchhop's Voltage Law (KVL) for the given circuit diagram?

Detailed Solution for Test: Kirchhoff’s Laws & Network Solutions - Question 5

Kirchhoffs Voltage Law (KVL):

  • Kirchhoffs Voltage Law or KVL, states that “in any closed loop network, the total voltage around the loop is equal to the sum of all the voltage drops within the same loop” which is also equal to zero.
  • In other words, the algebraic sum of all voltages within the loop must be equal to zero i.e. ∑V = 0
  • KVL is based on the law of conservation of energy.

Consider the figure shown below:

∴ According to KVL,

V1 + V2 + V3 + V4 + V5 = 0

Calculation:

The circuit diagram given in the question can be modified as:

Now by applying KVL in the above circuit, we get

5 + 7 - Vx = 0

∴ - 5 - 7 + Vx = 0

Test: Kirchhoff’s Laws & Network Solutions - Question 6

Find the value of I1, I2 and I3.

Detailed Solution for Test: Kirchhoff’s Laws & Network Solutions - Question 6

Using the matrix method:
Matrix
Solving this matrix equation, we get

I1 = 1.5A,

I2 = -0.188A

I3 = -1.19A.

Test: Kirchhoff’s Laws & Network Solutions - Question 7

 Find the value of V, if the value of I3= 0A.

Detailed Solution for Test: Kirchhoff’s Laws & Network Solutions - Question 7

5 -3 (I1) + 2 (I2) = 0

9 (I2) - 2(I1) = 0

-4 (I2) + V = 0
On solving,V = 1.739 V.

Test: Kirchhoff’s Laws & Network Solutions - Question 8

Find the value of R if the power in the circuit is 1000W.

Detailed Solution for Test: Kirchhoff’s Laws & Network Solutions - Question 8

To find the value of I:

V*I = P

=> 100*I = 1000

=> I = 10A

  • Voltage across the 2 ohm resistor
    = 20V
  • Voltage across the R resistor
    = 100 - 20 = 80 V

R = V / I

=> R = 80 / 10 = 8 ohm.

Test: Kirchhoff’s Laws & Network Solutions - Question 9

Find the current in the 4 ohm resistor.

Detailed Solution for Test: Kirchhoff’s Laws & Network Solutions - Question 9
  • The 4 ohm resistor gets shorted since current always prefers the low resistance path.
  • All the current flows to the branch which is connected in parallel to the 4 ohm branch, hence no current flows in the 4 ohm resistance.
Test: Kirchhoff’s Laws & Network Solutions - Question 10

Nodal analysis is generally used to determine_______

Detailed Solution for Test: Kirchhoff’s Laws & Network Solutions - Question 10

Nodal analysis uses Kirchhoff’s Current Law to find all the node voltages.

Hence it is a method used to determine voltage.

Test: Kirchhoff’s Laws & Network Solutions - Question 11

Mesh analysis is generally used to determine_________

Detailed Solution for Test: Kirchhoff’s Laws & Network Solutions - Question 11

Mesh analysis uses Kirchhoff’s Voltage Law to find all the mesh currents.

Hence it is a method used to determine current.

Test: Kirchhoff’s Laws & Network Solutions - Question 12

What is the current in the circuit?

Detailed Solution for Test: Kirchhoff’s Laws & Network Solutions - Question 12

If we move in the clockwise direction, we get the total voltage to be equal to:

-10 - 20 + 30 = 0V

Since I = V / R = 0 / 4 = 0

I = 0 A

Test: Kirchhoff’s Laws & Network Solutions - Question 13

 Does the 15A source have any effect on the circuit?

Detailed Solution for Test: Kirchhoff’s Laws & Network Solutions - Question 13

 The 15A current source has a lower resistance path associated with it and hence it keeps moving in that particular loop.

It does not leave that loop and enter the circuit, hence the circuit is not affected by it.

Test: Kirchhoff’s Laws & Network Solutions - Question 14

KVL is associated with____________

Detailed Solution for Test: Kirchhoff’s Laws & Network Solutions - Question 14

KVL employs mesh analysis to find the different mesh currents by finding the I*R products in each mesh.

Test: Kirchhoff’s Laws & Network Solutions - Question 15

Kirchhoff's laws are valid for

Detailed Solution for Test: Kirchhoff’s Laws & Network Solutions - Question 15

Concept of Kirchoff's Laws:

  • Kirchhoff’s laws are used for voltage and current calculations in electrical circuits.
  • These laws can be understood from the results of the Maxwell equations in the low-frequency limit.
  • They are applicable for DC and AC circuits at low frequencies where the electromagnetic radiation wavelengths are very large when we compare with other circuits. So they are only applicable for lumped parameter networks.

Kirchhoff's laws (KCL and KVL) is applicable to networks that are:

  1. Unilateral or bilateral 
  2. Active or passive 
  3. Linear or non-linear
  4. Lumped network
57 docs|62 tests
Information about Test: Kirchhoff’s Laws & Network Solutions Page
In this test you can find the Exam questions for Test: Kirchhoff’s Laws & Network Solutions solved & explained in the simplest way possible. Besides giving Questions and answers for Test: Kirchhoff’s Laws & Network Solutions, EduRev gives you an ample number of Online tests for practice

Top Courses for Electrical Engineering (EE)

Download as PDF

Top Courses for Electrical Engineering (EE)