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CAT Exam  >  CAT Tests  >  Level-wise Tests for CAT  >  Test Level 1: Mixed Graphs - CAT MCQ

Test Level 1: Mixed Graphs - CAT MCQ


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10 Questions MCQ Test Level-wise Tests for CAT - Test Level 1: Mixed Graphs

Test Level 1: Mixed Graphs for CAT 2024 is part of Level-wise Tests for CAT preparation. The Test Level 1: Mixed Graphs questions and answers have been prepared according to the CAT exam syllabus.The Test Level 1: Mixed Graphs MCQs are made for CAT 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test Level 1: Mixed Graphs below.
Solutions of Test Level 1: Mixed Graphs questions in English are available as part of our Level-wise Tests for CAT for CAT & Test Level 1: Mixed Graphs solutions in Hindi for Level-wise Tests for CAT course. Download more important topics, notes, lectures and mock test series for CAT Exam by signing up for free. Attempt Test Level 1: Mixed Graphs | 10 questions in 20 minutes | Mock test for CAT preparation | Free important questions MCQ to study Level-wise Tests for CAT for CAT Exam | Download free PDF with solutions
Test Level 1: Mixed Graphs - Question 1
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Directions: Study the following stacked bar graph which represents the advertisement expenditure of a trading company from 1995 - 96 to 2000 - 01 on its products P, Q, R and S.

Note: Sales for the given years are as follows:

Profit = Sales - Advertising Expenditure

Q. The advertising expenditure of product S as a percentage of the advertising expenditure of P and R together is least in which of the following years?

Detailed Solution for Test Level 1: Mixed Graphs - Question 1

In 1995 - 96 = 25/100 = 1/4
In 1996 - 97 = 25/75 = 1/3
In 1998 - 99 = 25/100 = 1/4
In 1999 - 2000 = 50/150 = 1/3
From the results, the advertising expenditure of S as a percentage of advertising expenditure of P and R together was least in 1995 - 96 and 1998 - 99.

Test Level 1: Mixed Graphs - Question 2
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Directions: Study the following stacked bar graph which represents the advertisement expenditure of a trading company from 1995 - 96 to 2000 - 01 on its products P, Q, R and S.

Note: Sales for the given years are as follows:

Profit = Sales - Advertising Expenditure

Q. If the ratio of sales of the products P, Q, R and S in the year 2000 - 01 is 2 : 5 : 1 : 2, then the profit of S is what percentage of the profit of Q in the same year?

Detailed Solution for Test Level 1: Mixed Graphs - Question 2

Sale of the products P, Q, R and S in 2000 - 01 are Rs. 200, Rs. 500, Rs. 100 and Rs. 200 crores, respectively.
Profit of Q = 500 - 50 = Rs. 450 crores
Profit of S = 200 - 25 = Rs. 175 crores
∴ Required percentage

= 4 × (5.55)%
= 38.89%

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Test Level 1: Mixed Graphs - Question 3
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Directions: The given table gives information about the number of articles sold by store P, Q and R from August to November and the profit earned by each store by selling each article. Answer the question that follows.

Q. The total articles sold by stores P and Q from August to October is what percent more than total articles sold by store R from August to October?

Detailed Solution for Test Level 1: Mixed Graphs - Question 3

Total number of articles sold by stores P and Q from August to October = 250 + 350 + 350 + 240 + 275 + 380 = 1845
Total number of articles sold by store R from August to October = 280 + 270 + 350 = 900
Required percent = (945 × 100)/900 = 105%

Test Level 1: Mixed Graphs - Question 4
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Directions: The given table gives information about the number of articles sold by store P, Q and R from August to November and the profit earned by each store by selling each article. Answer the question that follows.

Q. What is the difference between the profit of all three stores in the month of September and the profit of stores Q and R in October from the sale of article?
Detailed Solution for Test Level 1: Mixed Graphs - Question 4

Profit of all three stores in the month of September = 270 × 350 + 240 × 278 + 270 × 328
= 94,500 + 66,720 + 88,560 = Rs. 2,49,780
Profit of stores Q and R in October = 278 × 380 + 350 × 328
= 1,05,640 + 1,14,800 = Rs. 2,20,440
Difference = 2,49,780 - 2,20,440 = Rs. 29,340

Test Level 1: Mixed Graphs - Question 5
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Directions: In the recently concluded UP Elections, a total of 2,50,000 e-votes were casted from 8 different cities mentioned below in the pie-chart. The table shows the ratio of e-votes received by BJP to SP.

Q. What is the ratio of e-votes received by BJP in Lucknow to those in Noida?
Detailed Solution for Test Level 1: Mixed Graphs - Question 5

e-Votes received by BJP in Lucknow

e- Votes received by BJP in Noida 

Required ratio = 175 : 100 = 7 : 4

Test Level 1: Mixed Graphs - Question 6
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Directions: In the recently concluded UP Elections, a total of 2,50,000 e-votes were casted from 8 different cities mentioned below in the pie-chart. The table shows the ratio of e-votes received by BJP to SP.

Q. What is the ratio of the total number of e-votes cast to BJP in Kanpur and Varanasi to the total number of e-votes cast to SP in the same two cities?
Detailed Solution for Test Level 1: Mixed Graphs - Question 6

e-Votes cast to BJP in Kanpur and Varanasi

e-Votes cast to SP in Kanpur and Varanasi

Required ratio = 17 : 14

Test Level 1: Mixed Graphs - Question 7
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Directions: The pie chart given below shows the percentage population of seven different states in a particular year. The table shows sex and literacy ratios. Based on the given information, answer the following question:

Total population of the given states = 32,76,000

Q. What is the ratio of the number of females in Tamil Nadu to that in Delhi?
Detailed Solution for Test Level 1: Mixed Graphs - Question 7

Test Level 1: Mixed Graphs - Question 8
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Directions: The pie chart given below shows the percentage population of seven different states in a particular year. The table shows sex and literacy ratios. Based on the given information, answer the following question:

Total population of the given states = 32,76,000

Q. What was the total number of illiterate people in AP and MP?
Detailed Solution for Test Level 1: Mixed Graphs - Question 8

Total number illiterate people in AP and MP = ((7/9) × 27% + (4/5) × 21%) × 32,76,000 = (21 + 16.8) × 32,760 = 12,38,328

Test Level 1: Mixed Graphs - Question 9
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Directions: Read the following information carefully to answer the question that follows.
Cost of different ingredients (in Rs./g) used in making food products:

Ratio of ingredients in each type of food products:

Total cost of food products = Rs. 15 (making charges per food product) + ingredients cost

Q. What is the total cost of 500 g of type A and 600 g of type B food products?
Detailed Solution for Test Level 1: Mixed Graphs - Question 9

Ingredient P used in 500 g of type A and 600 g of type B food products = (500 × 5/20) g + (600 × 3/20) g = (125 + 90) g = 215 g
Ingredient Q used in 500 g of type A and 600 g of type B food products = (500 × 4/20) g + (600 × 4/20) g = 220 g
Ingredient R used in 500 g of type A and 600 g of type B food products = (500 × 6/20) g + (600 × 8/20) g = 390 g
Ingredient S used in 500 g of type A and 600 g of type B food products = (500 × 5/20) g + (600 × 5/20) g = 275 g
Total cost = Rs. (30 + 215 × 8 + 220 × 5 + 390 × 4 + 275 × 7) = Rs. 6335

Test Level 1: Mixed Graphs - Question 10
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Directions: Read the following information carefully to answer the question that follows.
Cost of different ingredients (in Rs./g) used in making food products:

Ratio of ingredients in each type of food products:

Total cost of food products = Rs. 15 (making charges per food product) + ingredients cost

Q. What is the total cost of ingredients in 600 g food products of type B and 1200 g food of type C?
Detailed Solution for Test Level 1: Mixed Graphs - Question 10

Ingredient P used in 600 g food products of type B and 1200 g food of type C = (3 × 600/20 + 5 × 1200/30) g = 290 g
Ingredient Q used in 600 g food products of type B and 1200 g food of type C = (4 × 600/20 + 9 × 1200/30) g = 480 g
Ingredient R used in 600 g food products of type B and 1200 g food of type C = (8 × 600/20 + 7 × 1200/30) g = 520 g
Ingredient S used in 600 g food products of type B and 1200 g food of type C = (5 × 600/20 + 9 × 1200/30) g = 510 g
Total cost = Rs. (290 × 8 + 480 × 5 + 520 × 4 + 510 × 7) = Rs. 10370
Thus, answer option 2 is correct.

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