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Test: Mendeleev's periodic table, Modern periodic table - JEE MCQ


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20 Questions MCQ Test Chemistry for JEE Main & Advanced - Test: Mendeleev's periodic table, Modern periodic table

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Test: Mendeleev's periodic table, Modern periodic table - Question 1

Arrange the following in increasing order of ionic radii?

Detailed Solution for Test: Mendeleev's periodic table, Modern periodic table - Question 1
All the given species are isoelectronic. In case of isoelectronic species ionic radii increases with increase in negative charge on anions.
Test: Mendeleev's periodic table, Modern periodic table - Question 2

The cause of periodicity of properties of elements is due to the repetition of similar:

Detailed Solution for Test: Mendeleev's periodic table, Modern periodic table - Question 2

The cause of periodicity of properties of elements is due to the repetition of similar electronic configuration of their atoms in the outermost energy shell after certain regular interval.

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Test: Mendeleev's periodic table, Modern periodic table - Question 3

Tendency of an atom in a molecule to attract the shared pair of electron towards itself is called:

Detailed Solution for Test: Mendeleev's periodic table, Modern periodic table - Question 3

The tendency of an atom in a molecule to attract the shared pair of electrons towards itself is called its electronegativity.
Electronegativity is a dimensionless property since it is only a tendency. It only indicates the net result of the tendencies of different elements to attract the bond forming electron pair.

Test: Mendeleev's periodic table, Modern periodic table - Question 4
Let electronegativity, ionisation energy and electron affinity be represented as EN, IP and EA respectively. Which one of the following equation is correct according to Mulliken?
Detailed Solution for Test: Mendeleev's periodic table, Modern periodic table - Question 4
Mulliken suggested that EN of an element is the average of its IP and EA.
Test: Mendeleev's periodic table, Modern periodic table - Question 5
(X), (Y), (Z) are elements of the third period. Oxide of (X) is ionic, that of (Y) is amphoteric and of (Z) a giant molecule. (X), (Y) and (Z) will have atomic numbers in the order
Detailed Solution for Test: Mendeleev's periodic table, Modern periodic table - Question 5
For third period, "s" block will form ionic oxide, 13th group forms amphoteric oxide, and 14th group element will form giant oxide .
(X) < (Y) < (Z)
Test: Mendeleev's periodic table, Modern periodic table - Question 6

Which one of the following is correct order of second ionisation potential of   and ?

Detailed Solution for Test: Mendeleev's periodic table, Modern periodic table - Question 6

The electronic configuration of Na,Ne,Mg and Al after the removal of an electron is as

The ionisation energy decreases as the size of the atom/ion increases. Further ionisation energy increases with increase in nuclear charge.
Since, Na+ gives a stable electronic configuration hence its IE2 is highest among the given species and therefore the correct order of their IE2 is
Mg < Al < Ne < Na

Test: Mendeleev's periodic table, Modern periodic table - Question 7
Which one of the following arrangements represents the correct order of least negative to most negative electron gain enthalpy for and
Detailed Solution for Test: Mendeleev's periodic table, Modern periodic table - Question 7
As the nuclear charge increases, the force of attraction between the nucleus and the incoming electron increases and hence the elecron gain enthalpy becomes more negative, hence the correct order is
Test: Mendeleev's periodic table, Modern periodic table - Question 8

The maximum covalency and highest oxidation state possible for an element with Z = 13 are respectively.

Detailed Solution for Test: Mendeleev's periodic table, Modern periodic table - Question 8

Electronic configuration of 
The maximum covalency of any element is found by counting the number of covalent and coordinate bonds that it can form.
So, the maximum covalency of element having is 6.
Since, it has 3 electrons in the valence shell, its highest oxidation state is +3.

Test: Mendeleev's periodic table, Modern periodic table - Question 9
Sum of first three ionization energies of is atom and the sum of first two ionization energies of is atom . Out of Al(III) and
Detailed Solution for Test: Mendeleev's periodic table, Modern periodic table - Question 9
Ionization energy is not the only the criteria for the stability of an oxidation state.
Test: Mendeleev's periodic table, Modern periodic table - Question 10

The correct order of decreasing electronegatıvity values among the elements I-beryllium, II-oxygen, III-nitrogen and IV-magnesium is

Detailed Solution for Test: Mendeleev's periodic table, Modern periodic table - Question 10

Electronegativity values of given elements are as follows:

Test: Mendeleev's periodic table, Modern periodic table - Question 11
Which of the following sequence correctly represents the decreasing acidic nature of oxides?
Detailed Solution for Test: Mendeleev's periodic table, Modern periodic table - Question 11
On passing from left to right in a period, acidic character of the normal oxides of the elements increases with increase in electronegativity.
Test: Mendeleev's periodic table, Modern periodic table - Question 12

Correct order of first IP among following elements Be,B,C,N,O is

Detailed Solution for Test: Mendeleev's periodic table, Modern periodic table - Question 12



IP increases along the period. But IP of . Further IP of because atoms with fully or partly filled orbitals are most stable and hence have high ionisation energy.

Test: Mendeleev's periodic table, Modern periodic table - Question 13
Aqueous solutions of two compounds and are prepared in two different beakers. If, the electronegativity of , and then the nature of two solutions will be respectively :
Detailed Solution for Test: Mendeleev's periodic table, Modern periodic table - Question 13
The electronegativity difference between and is , which indicates bond will be covalent, since bond having more ionic character thus bond will break and ions gets release and acidic solution is formed and whereas difference between electronegativity of is , thus, bond will break. Hence, solution will be basic in nature.
Test: Mendeleev's periodic table, Modern periodic table - Question 14
An element having electronic configuration forms
Detailed Solution for Test: Mendeleev's periodic table, Modern periodic table - Question 14
It is electronic configuration of alkali metal. Hence it will form basic oxide.
Test: Mendeleev's periodic table, Modern periodic table - Question 15

The correct order of first ionisation enthalpy of group-13 elements is

Detailed Solution for Test: Mendeleev's periodic table, Modern periodic table - Question 15

The first ionization enthalpy generally decreases down the group in Group 13 of the periodic table due to the increasing atomic size, which leads to easier removal of the outermost electron. So, the order B > Ga > Tl follows this trend.

Test: Mendeleev's periodic table, Modern periodic table - Question 16
Which one of the following statements is incorrect in relation to ionisation enthalpy?
Detailed Solution for Test: Mendeleev's periodic table, Modern periodic table - Question 16
As the value of increases, the nuclear attraction over the outermost shell decreases, therefore removal of an electron will be easier.
Test: Mendeleev's periodic table, Modern periodic table - Question 17

If the ionization enthalpy and electron gain enthalpy of an element are 275 and respectively, then the electronegativity of the elementon the Pauling scale is:

Detailed Solution for Test: Mendeleev's periodic table, Modern periodic table - Question 17

I.E. E.A.

Electronegativity

Test: Mendeleev's periodic table, Modern periodic table - Question 18
The electronegativity order of the following elements is
Detailed Solution for Test: Mendeleev's periodic table, Modern periodic table - Question 18
Electronegativity is inversely proportional to the atomic size. Smaller the size, greater is the electronegativity. Nitrogen is placed in second period, so it has smallest size and highest electronegativity. Then, iodine belongs to halogen family which are electronegative elements. For, S and Te, on moving top to bottom, atomic size increases so electronegative character decreases. So, the correct order is .
Test: Mendeleev's periodic table, Modern periodic table - Question 19
The successive ionization energy values of an element are and respectively. The element is likely to be:
Detailed Solution for Test: Mendeleev's periodic table, Modern periodic table - Question 19

The and of an element are and respectively. Therefore, We can see that there is a regular very close increment of ionization energy till the fourth ionization energy. After the fourth ionization energy, there is a sudden high jump in energy. It confirms that after losing four electrons, that element will achieve the noble gas configuration or stable configuration.

We can see the configuration of the elements and can identify that silicon has this tendency to lose the four electrons and gets the noble gas configuration.

the valency of the element is and it is most likely to be silicon.

Test: Mendeleev's periodic table, Modern periodic table - Question 20
Under normal condition which of the following electronic configuration is able to form dipositive ion
Detailed Solution for Test: Mendeleev's periodic table, Modern periodic table - Question 20
has only two electrons in the 3 s-orbital and hence its . is lowest, i.e. it has the maximum tendency to from di-positive ions.
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