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CDS Exam  >  CDS Tests  >  Elementary Mathematics for CDS  >  Test: Problems on Ages - 5 - CDS MCQ

Test: Problems on Ages - 5 - CDS MCQ


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5 Questions MCQ Test Elementary Mathematics for CDS - Test: Problems on Ages - 5

Test: Problems on Ages - 5 for CDS 2024 is part of Elementary Mathematics for CDS preparation. The Test: Problems on Ages - 5 questions and answers have been prepared according to the CDS exam syllabus.The Test: Problems on Ages - 5 MCQs are made for CDS 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Problems on Ages - 5 below.
Solutions of Test: Problems on Ages - 5 questions in English are available as part of our Elementary Mathematics for CDS for CDS & Test: Problems on Ages - 5 solutions in Hindi for Elementary Mathematics for CDS course. Download more important topics, notes, lectures and mock test series for CDS Exam by signing up for free. Attempt Test: Problems on Ages - 5 | 5 questions in 10 minutes | Mock test for CDS preparation | Free important questions MCQ to study Elementary Mathematics for CDS for CDS Exam | Download free PDF with solutions
Test: Problems on Ages - 5 - Question 1
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Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?

Detailed Solution for Test: Problems on Ages - 5 - Question 1

Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.

Test: Problems on Ages - 5 - Question 2
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The sum of ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child?

Detailed Solution for Test: Problems on Ages - 5 - Question 2

Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.

Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50

 5x = 20

 x = 4.

 Age of the youngest child = x = 4 years.

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Test: Problems on Ages - 5 - Question 3
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A father said to his son, "I was as old as you now at the time of your birth". If the father's age is 38 years now, the son's age five years back was:

Detailed Solution for Test: Problems on Ages - 5 - Question 3

Let the son's present age be x years. Then, (38 - x) = x

 2x = 38.

 x = 19.

 Son's age 5 years back (19 - 5) = 14 years.

Test: Problems on Ages - 5 - Question 4
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A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, the how old is B?
Detailed Solution for Test: Problems on Ages - 5 - Question 4

Let C's age be x years. Then, B's age = 2x years. A's age = (2x + 2) years.

 (2x + 2) + 2x + x = 27

 5x = 25

 x = 5.

Hence, B's age = 2x = 10 years.

Test: Problems on Ages - 5 - Question 5
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Present ages of Sameer and Anand are in the ratio of 5 : 4 respectively. Three years hence, the ratio of their ages will become 11 : 9 respectively. What is Anand's present age in years?
Detailed Solution for Test: Problems on Ages - 5 - Question 5

Let the present ages of Sameer and Anand be 5x years and 4x years respectively.

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