Test: Ratio and Proportion- 2 - CLAT MCQ

To find the total amount of money divided between P, Q, and R in the ratio of 3:7:12:
Given:

• Let k be the common multiplier.
• P's share = 3k
• Q's share = 7k
• R's share = 12k

Equations:

1. Difference between Q and P:
   7k - 3k = 4k = X
2. Difference between Q and R:
   12k - 7k = 5k = 3000

Solve for k:
k = 3000 / 5 = 600

Calculate Shares:

• P's share = 3k = 1800
• Q's share = 7k = 4200
• R's share = 12k = 7200

Total Amount:
Total = 1800 + 4200 + 7200 = 13200

• A= (2/3) x B; B= (1/3) x C;
• Therefore , A/B = 2/3 and B/C = 1/3
• A:B = 2:3 ; B:C = 1:3;
• A:B:C = 2:3:9
• C = 9/14 x 1638 = 1053
•  

• Ans– C 
• For solving this question we need to use a hit and trial method 
• As we approached option c, X = 40; Z = 75
•  Number of increased seats are (140% of 5x), (150% of 7x) and (175% of 8x)
• i.e., (140/100 * 5x), (150/100 * 7x) and (175/100 * 8x)
• i.e., 7x, 21x/2 and 14x
• Required ratio = 7x : 21x/2 : 14x
• = 14x : 21x : 28x
• = 2 : 3 : 4

The given ratio is:
A : B : C = 3 : 5 : 7
Let the common factor be x. Thus, the production units will be:
A = 3x
B = 5x
C = 7x
We are also given that the total production is 30,000 units. So:
3x + 5x + 7x = 30,000
15x = 30,000
x = 2,000
Now, substitute x = 2,000 into the expressions for each product:
A's production = 3 × 2,000 = 6,000 units
B's production = 5 × 2,000 = 10,000 units
C's production = 7 × 2,000 = 14,000 units
So, the production for A, B, and C is:
A = 6,000 units
B = 10,000 units
C = 14,000 units

Final Answer:
Initial production:
A = 6,000 units, B = 10,000 units, C = 14,000 units

Answer – C.A = 1767; X = 2945
Explanation : 4/15 * A = 2/5 * B
A= 3/2 B;
A:B = 3:2;
check which option have 3:5 with X
A = 3/5 X
A = 3/5 x 2945
A = 1767
 

Answer – C.40
Explanation : x+y=100 ————– (i)
44.50x + 55.25y = 4880 ————– (ii)
Solving (i) and (ii) Y = 40

4x – 2y = 5000 and 5x – 3y = 5000.
X = 2500, so income = 10000 and 12500.

Answer – D.Sum = 98; B = 30 Explanation : A:B:C = 10:15:24
If sum = 98, B = 15/49 * 98 = 30

Answer – C.X = 840; Y = 280 Explanation : Value is given in the ratio 8:4:2. (8x/0.25) + (4x/0.5) + (2x/1) = 840.
X = 20. Total amount, Y = 14*20 = 280

Answer – c) 100:161 Explanation : Boys = 4x and girls = 7x Ratio = 4x*125/100 : 7x*115/100 = 100:161

Answer – b) 1:2 Explanation : (40/100)*a + b = (120/100)*b a:b = 1:2

Answer – d) data inadequate Explanation : Total sum not given

Let height of both candles is ‘h’ and let after t times ratio between the height be h – t*(h/6) : h – t*(h/4) = 2:1

t = 3 hour

Answer – b) decreases 21:20 Explanation : Let initial employees be 7x and then 4x similarly initial wages be 3y and then 5y so total wage = 21xy initially and then 20xy so wages decreases and ratio = 21:20

Answer – b) 32 Explanation : milk = 4x and water = 3x milk = 4x – 14*4/7 and water = 3x – 14*3/7 + 14 4x – 8: 3x + 8 = 3:4 X = 8, so milk = 8*4 = 32 litres

Answer – b) 10.5 Explanation : (3x – 3)/(4x – 3) = ½ x = 1.5 sum of the numbers = 7*1.5 = 10.5

Answer – c) 42 Explanation : a: b = 2:3 and b:c = 4:5 a:b:c = 8:12:15 Difference between first and third number  = (7/35)*210 = 42

Value is given in the ratio 8:4:2

(8x/0.25) + (4x/0.5) + (2x/1)

= 840.

X = 20.

Total amount = 14*20 = 280

Answer – b) 4000, 5000 Explanation : 4x – 2y = 2000 and 5x – 3y = 2000.
X = 1000, so income = 4000 and 5000