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Test: Second Law of Thermodynamics - 3 - Mechanical Engineering MCQ


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10 Questions MCQ Test Thermodynamics - Test: Second Law of Thermodynamics - 3

Test: Second Law of Thermodynamics - 3 for Mechanical Engineering 2024 is part of Thermodynamics preparation. The Test: Second Law of Thermodynamics - 3 questions and answers have been prepared according to the Mechanical Engineering exam syllabus.The Test: Second Law of Thermodynamics - 3 MCQs are made for Mechanical Engineering 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Second Law of Thermodynamics - 3 below.
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Test: Second Law of Thermodynamics - 3 - Question 1

The Carnot cycle is unpredictable because it

Test: Second Law of Thermodynamics - 3 - Question 2

An engine operates between temperature limits of 900 K and T2 and another between T2 and 400 K for both to be equally efficient T2 will be equal to

Detailed Solution for Test: Second Law of Thermodynamics - 3 - Question 2

For efficiency to be equal

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Test: Second Law of Thermodynamics - 3 - Question 3

An inventor claims that a heat engine has the following specifications:
Developed = 50 kW
Fuel burned per hour = 3 kg
Heating value of fuel = 7500 kJ/kg
Temperature limit = 627°C and 27°C
Cost of fuel = Rs. 30/kg
Power the performance of his engine is

Detailed Solution for Test: Second Law of Thermodynamics - 3 - Question 3


Since actual efficiency of the engine is greater than Carnot hence engine is not possible.

Test: Second Law of Thermodynamics - 3 - Question 4

Three engines A, B and C operating on Carnot cycle respectively use air, steam and Helium as the working fluid. If all the engine operates within the same temperature limit, then which engine will have highest efficiency.

Detailed Solution for Test: Second Law of Thermodynamics - 3 - Question 4

Since efficiency of the engine purely depends upon source and sink temperatures and independent of the working substances. All the engines have same efficiency.

Test: Second Law of Thermodynamics - 3 - Question 5

If a heat engine gives an output of 3 kW.when the input is 10000J/sec then the thermal efficiency of the engine will be

Detailed Solution for Test: Second Law of Thermodynamics - 3 - Question 5

Test: Second Law of Thermodynamics - 3 - Question 6

A Carnot engine operates between 27°C and 327°C. If the engine produces 300 kJ of work, what is the entropy change during heat rejection?

Detailed Solution for Test: Second Law of Thermodynamics - 3 - Question 6



Oin = 600 KJ
Qout = 300K

Test: Second Law of Thermodynamics - 3 - Question 7

The following heat engine produces power of 100,000 kW. The heat engine operates between 800 K and 300 K. It has a thermal efficiency equal to 50% of that of the Carnot engine for the same temperatures. The rate at which heat is absorbed from the hot reservoir is

Detailed Solution for Test: Second Law of Thermodynamics - 3 - Question 7

Power produced by engine = Workdone(W) = 100,000 k
= 50% of Carnot cycle or engine

Also, 

       = 320 MW

Test: Second Law of Thermodynamics - 3 - Question 8

A heat engine operates at 75% of the maximum possible efficiency. The ratio of the heat source temperature (in K) to the heat sink temperature (in K) is 5/3. The fraction of the heat supplied that is converted to work is

Detailed Solution for Test: Second Law of Thermodynamics - 3 - Question 8

Given, 
Efficiency, 

Also η = Work done/Heat supplied
Since the engines uses only 75% of the heat made available to it, therefore


W = 0.3 x H

Test: Second Law of Thermodynamics - 3 - Question 9

Which of the following represents the Carnot cycle (ideal engine)?

Detailed Solution for Test: Second Law of Thermodynamics - 3 - Question 9

Carnot cycle consist of two Isentropics and two isothermals.

Test: Second Law of Thermodynamics - 3 - Question 10

A reversible power cycle is used to drive a reversible heat pump cycle. The power cycle takes in Q1 heat units at T1 and reflects Q2 at T2. The heat pump abstracts Q4 from sink at T4 and discharges Q3 at T3. The ratio of Q4/Q1 (in terms of four temperature) is

Detailed Solution for Test: Second Law of Thermodynamics - 3 - Question 10

The power cycle operating between temperature T1, and T2 and heat pump is operating between temperature T3 and T4




COP of reversible pump


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