Test: Simple Parallel Circuits - Electrical Engineering (EE) MCQ

 In the given circuit, the voltage across the resistor is the same as the source voltage as they are connected in parallel. The current in the resistor is IR hence IR=V/R.

 In the following circuit IR and V are in phase because IR is the current in the resistor and the current in the resistor is always in phase with the voltage across it.

In the given circuit, the voltage across the inductor is the same as the source voltage as they are connected in parallel. The current in the inductor is IL hence IL=V/XL.

 IL is the current across the inductor and we know that the current across the inductor always lags the voltage across it. Hence IL lags V.

 I is the total current in the circuit. Since this is a parallel connection, the total current in the circuit is equal to the sum of the currents in each branch of the circuit. Hence I=IR+IL.

We know that I=IR+IL.
Substituting the values from the question, we get I=7A.

We know that I=IR+IL.
Substituting the values from the question, we get IR=2A.

We know that I=IR+IL.
Substituting the values from the question, we get IL=4A.

In the given circuit, the voltage across the capacitor is the same as the source voltage as they are connected in parallel. The current in the capacitor is IC hence IC=V/XC.

 IC is the current across the capacitor and we know that the current across the capacitor always leads the voltage across it. Hence IC leads V.