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Sinusoidal Steady-State Analysis - 1 - Free MCQ Practice Test with solutions,


MCQ Practice Test & Solutions: Test: Sinusoidal Steady-State Analysis - 1 (10 Questions)

You can prepare effectively for Electrical Engineering (EE) Topicwise Question Bank for Electrical Engineering with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Test: Sinusoidal Steady-State Analysis - 1". These 10 questions have been designed by the experts with the latest curriculum of Electrical Engineering (EE) 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 30 minutes
  • - Number of Questions: 10

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Test: Sinusoidal Steady-State Analysis - 1 - Question 1

The phasor diagram shown in figure below is for a two-element series circuit having

Detailed Solution: Question 1

It is clear that i leads v by 53.2° (< 90°).
Hence the two series elements must be R and C.
∴ tan θ = tan 53.3°
tan 45° < tan 53.3° < tan 60° or,  
 1 < tan 53.3° <1.732
Hence, tan 53.3° = 1.3367

Test: Sinusoidal Steady-State Analysis - 1 - Question 2

 For the circuit shown below, the voltage across the 3 Ω resistor V3 is

Detailed Solution: Question 2

Using voltage division rule, we have

Test: Sinusoidal Steady-State Analysis - 1 - Question 3

A part of a circuit shown below consists of a resistor, a capacitor and an inductor. At steady state, iR(t) = 10 sin t and vL{t) = 5 cost. The rms value of the current through the capacitor is

Detailed Solution: Question 3

Using KCL at the given node, 

Test: Sinusoidal Steady-State Analysis - 1 - Question 4

 In the circuit shown below, currents I and I1 are respectively

Detailed Solution: Question 4

From given figure

Using phasor diagram shown below, the currents I and I1 are respectively

Test: Sinusoidal Steady-State Analysis - 1 - Question 5

What should be the value of C for the circuit shown below such that the input power factor is unity for any frequency f of the source?

Detailed Solution: Question 5

The input impedance Z of given circuit is 

For p.f. to be unity,

Test: Sinusoidal Steady-State Analysis - 1 - Question 6

 In a series R-L circuit, the current and voltages are given by
i = cos (314t-20°) , v = 10 cos ( 314 t + 10°). The values of R and L are respectively

Detailed Solution: Question 6

Here, i lags v by 30°

also

Test: Sinusoidal Steady-State Analysis - 1 - Question 7

A series R-L circuit has resistance and reactance of 15 Ω and 10 Ω respectively. What should be the value of capacitor which when connected across the series combination in parallel, the system attains unity p.f.? (use f= 50 Hz)

Detailed Solution: Question 7

The situation is shown in figure below with it's phasor diagram.

For unity p.f. operation,


 

Test: Sinusoidal Steady-State Analysis - 1 - Question 8

The input p.f. of the circuit shown below is

Detailed Solution: Question 8

or, Zin = 2.828∠-45°Ω
Hence, input p.f. = cos45° = 0.707 (lead)

Test: Sinusoidal Steady-State Analysis - 1 - Question 9

The input admittance of the circuit shown below is

Detailed Solution: Question 9

Hence

Test: Sinusoidal Steady-State Analysis - 1 - Question 10

 The driving point impedance

does not represents a passive one port network because

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