Test: Tests & Distinction of Alcohols - JEE MCQ

An organic compound X (C₇H₁₆O) on treatm ent with concentrated HCI solution forms immediate turbidity even in the absence of ZnCl₂. Also, X is resolvable into enantiomers. The correct statement concerning X is

Which reagent given below does not produce any visible change when added to ethylene glycol?

Which of the following is least likely to form turbidity with HCI in the presence of ZnCI₂ at room temperature?

The correct statement regarding 3-ethyl-3-hexanol is

An alcohol has molecular formula C₆H₁₂O X and it gives immediate turbidity with cold, concentrated HCI even in the absence of ZnCI₂. X can also be obtained by treatment of an ether with excess of CH₃MgBr followed by acid hydrolysis. Hence, the correct statement regarding X is

One or More than One Options Correct Type

Direction (Q. Nos. 9-12) This section contains 4 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONE or MORE THAN ONE are correct.

Q. 

Which reagent(s) can be used to differentiate between 2-pentanol and 1-pentanol?

Alcohols given below that behaves like 1°-aliphatic alcohol in Lucas test is/are

Consider the following reaction sequence,

R — OH  R — I R—NO₂ Blue

Hence, R—OH could be

Consider the following reaction,

The correct statement(s) concerning X and Y is/are

Comprehension Type

Direction (Q. Nos. 13-15) This section contains a passage describing theory, experiments, data, etc. Two questions related to the paragraph have been given. Each question has only one correct answer out of the given 4 options (a), (b), (c) and (d).

Passage

An organic compound X (C₉H₁₂O) gives the following reactions :
i. Na - Slow gas bubble formation
ii. Acetic anhydride - Pleasent smelling liquid
iii. CrO₃-H₂SO₄ - Blue-green solution
iv. Hot KMnO₄ - Benzoic acid
v. Br₂-CCI₄ - No decolouration
vi. I₂ + NaOH - Yellow solid is formed
vii. X rotates the plane polarised light

Q. 

The structure of X is

An organic compound X (C₉H₁₂O) gives the following reactions :
i. Na - Slow gas bubble formation
ii. Acetic anhydride - Pleasent smelling liquid
iii. CrO₃-H₂SO₄ - Blue-green solution
iv. Hot KMnO₄ - Benzoic acid
v. Br₂-CCI₄ - No decolouration
vi. I₂ + NaOH - Yellow solid is formed
vii. X rotates the plane polarised light

Q. 

If X is treated with HCI in the presence of ZnCI₂, the major product would be

An organic compound X (C₉H₁₂O) gives the following reactions :
i. Na - Slow gas bubble formation
ii. Acetic anhydride - Pleasent smelling liquid
iii. CrO₃-H₂SO₄ - Blue-green solution
iv. Hot KMnO₄ - Benzoic acid
v. Br₂-CCI₄ - No decolouration
vi. I₂ + NaOH - Yellow solid is formed
vii. X rotates the plane polarised light

Q. 

An isomer of X, Y was also found to be optically active. It showed the same reactions as X except (vi). Hence, Y is

One Integer Value Correct Type

Direction (Q. Nos. 16-19) This section contains 4 questions. When worked out will result in an integer from 0 to 9 (both inclusive).

An organic compound X (C₅H₁₂O) is chiral. Also

Q.

How many primary hydrogens are present in X?

An alcohol X (C₇H₁₆O) gives immediate turbidity with HCI/ZnCI₂ and can be resolved into enantiomers. Also X has a tertiary hydrogen. How many CH₃— groups are present in X?

An alcohol X (C₄H₁₀O₃) is chiral and absorbs two moles of HIO₄ per mole of X. How many stereoisomers exist for X?

An organic compound X (C₇H₁₆O) gives effervescence with Na. X has both enantiomers and diastereomers. X gives yellow precipitate with alkaline iodine solution. With CrO₃ - H₂SO₄ , X is converted into C₇H₁₄O (Y) which has enantiom ers but not diastereom ers. X on refluxing with H₂SO₄ isomerises to Z which neither gives yellow precipitate with alkaline iodine nor changes colour of CrO₃ - H₂SO₄ . What is the minim um number of carbons that can be present in the parent chain of X ?