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Test: Total Pressure & Vertical Plane Surface Submerged in a Liquid - Mechanical Engineering MCQ


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10 Questions MCQ Test Fluid Mechanics for Mechanical Engineering - Test: Total Pressure & Vertical Plane Surface Submerged in a Liquid

Test: Total Pressure & Vertical Plane Surface Submerged in a Liquid for Mechanical Engineering 2024 is part of Fluid Mechanics for Mechanical Engineering preparation. The Test: Total Pressure & Vertical Plane Surface Submerged in a Liquid questions and answers have been prepared according to the Mechanical Engineering exam syllabus.The Test: Total Pressure & Vertical Plane Surface Submerged in a Liquid MCQs are made for Mechanical Engineering 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Total Pressure & Vertical Plane Surface Submerged in a Liquid below.
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Test: Total Pressure & Vertical Plane Surface Submerged in a Liquid - Question 1

Does total pressure takes into the account force exerted by the fluid when it is in the dynamic motion?

Detailed Solution for Test: Total Pressure & Vertical Plane Surface Submerged in a Liquid - Question 1

Explanation: Total pressure is defined only for the static fluid at rest. There is no dynamic component as no motion is involved.

Test: Total Pressure & Vertical Plane Surface Submerged in a Liquid - Question 2

 Can centre of pressure for a vertical plane submerged surface be ever be above centre of Gravity

Detailed Solution for Test: Total Pressure & Vertical Plane Surface Submerged in a Liquid - Question 2

Explanation: Centre of pressure always lies below the centre of gravity. In certain cases it may coincide but it can never be above the centre of gravity.

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Test: Total Pressure & Vertical Plane Surface Submerged in a Liquid - Question 3

Which principle is used for calculating the centre of pressure?

Detailed Solution for Test: Total Pressure & Vertical Plane Surface Submerged in a Liquid - Question 3

Explanation: We balance the moment in order to calculate the position of centre of pressure.

Test: Total Pressure & Vertical Plane Surface Submerged in a Liquid - Question 4

 In a vertically submerged plane surface, pressure at evbery point remains same

Detailed Solution for Test: Total Pressure & Vertical Plane Surface Submerged in a Liquid - Question 4

Explanation: Pressure at every point is different as the depth of different point from is different.

Test: Total Pressure & Vertical Plane Surface Submerged in a Liquid - Question 5

The magnitude of total pressure and centre of pressure is independent on the shape of the submerged plane surface

Detailed Solution for Test: Total Pressure & Vertical Plane Surface Submerged in a Liquid - Question 5

Explanation: For differently shaped surfaces, the area and hence position of centroid will be different. Hence, the magnitude of total pressure and centre of pressure is dependent on the shape of the submerged plane surface.

Test: Total Pressure & Vertical Plane Surface Submerged in a Liquid - Question 6

What is the variation of total pressure with depth for any submerged surface if we neglect variation in the density?

Detailed Solution for Test: Total Pressure & Vertical Plane Surface Submerged in a Liquid - Question 6

Explanation: Total pressure is given by,
F=w*a*y
hence, F ∝ y i.e linear relation.

Test: Total Pressure & Vertical Plane Surface Submerged in a Liquid - Question 7

A pipe line which is 6 m in diameter contains a gate valve. The pressure at the centre of the pipe is 25 N/cm2. If the pipe is filled with specific gravity 0.8, find the force exerted by the oil upon the gate.

Detailed Solution for Test: Total Pressure & Vertical Plane Surface Submerged in a Liquid - Question 7

Explanation: ĥ=p/ρg
=250000/9.81*800
=31.855 m
F=wAĥ
=9.81*800*9*π*31.855
=7.06 MN.

Test: Total Pressure & Vertical Plane Surface Submerged in a Liquid - Question 8

Determine the centre of pressure on an isosceles triangle plate of base 6m and altitude 6m when it is immersed vertically in an oil of specific gravity 0.75. The base of the plate coincides with the free surface of oil.

Detailed Solution for Test: Total Pressure & Vertical Plane Surface Submerged in a Liquid - Question 8

Explanation: ŷ=I/Aĥ + ĥ
I=bh³/36
ŷ=36*2/18 + 2
=3 m.

Test: Total Pressure & Vertical Plane Surface Submerged in a Liquid - Question 9

 A tank contains water upto a height of 0.5 m above the base. An immiscible liquid of specific gravity 0.75 is filled on the top of water upto 1.5 m height. Calculate total pressure on side of the tank.

Detailed Solution for Test: Total Pressure & Vertical Plane Surface Submerged in a Liquid - Question 9

Explanation: F = F1 + F2 + F3
F=w*A*ŷ
F= 8277.18+5518.12+3985.31
= 17780.61 N/m2.

Test: Total Pressure & Vertical Plane Surface Submerged in a Liquid - Question 10

 A circular opening, 6m diameter, in a vertical side of a tank is closed by a disc of 6m diameter which can rotate about a horizontal diameter. Calculate the force on the disc. The centre of circular opening is at the depth of 5 m.

Detailed Solution for Test: Total Pressure & Vertical Plane Surface Submerged in a Liquid - Question 10

Explanation: F=w*A*ŷ
=9.81*1000*3.142*32*5
=1.38 MN.

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