Test: Transients in LR Networks - Electrical Engineering (EE) MCQ

An R-L network is a network which consists of a resistor which is connected in series to an inductor.

At DC, the inductor acts as short circuit because the inductive resistance is zero. The frequency of a DC circuit is 0. The inductive resistance=(2*pi*f*L). Therefore, if the frequency is 0, the inductive resistance is zero and it acts as an short circuit.

In an RL series circuit, the response decays with time because according to the equation, there is an exponential decrease in the response.

Initially, when the switch is open, the current in the circuit is 0. As soon as the switch is closes at t=0+, the inductor acts as an open circuit, hence the current in the circuit is zero.

Initially, when the switch is open, the current in the circuit is 0. As soon as the switch is closes at t=0+, the inductor acts as an open circuit, hence the current in the circuit is zero. Since the current in the circuit is zero, there is no voltage drop across the resistor and the voltage across the inductor is equal to the supply voltage, which is equal to 60V.

At t = 0+ the current in the circuit is zero. Therefore at t = 0+, i = 0, 0 = c + 2, c = -2. Substituting the value of c in the current equation, we have i = 2(1-e^-2t)A.

At steady state, inductor acts as a short circuit because at steady state maximum current flows across the inductor. Hence it acts as a zero resistance source or an open circuit.

At steady state maximum current flows in the inductor because it acts as an open circuit.

Initially, when the switch in a series RL circuit is closed, the inductor acts as an open circuit. This is because the current gradually increases as the time increases. At t=0, the current in the inductor is zero, hence it acts as an open circuit.

Initially, when the switch in a series RL circuit is closed, the inductor acts as an open circuit. Current in an open circuit is zero, hence the inductor current is zero.