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ZS Associates Aptitude Questions and Answers - Interview Preparation MCQ


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15 Questions MCQ Test Company Wise Preparation - ZS Associates Aptitude Questions and Answers

ZS Associates Aptitude Questions and Answers for Interview Preparation 2024 is part of Company Wise Preparation preparation. The ZS Associates Aptitude Questions and Answers questions and answers have been prepared according to the Interview Preparation exam syllabus.The ZS Associates Aptitude Questions and Answers MCQs are made for Interview Preparation 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for ZS Associates Aptitude Questions and Answers below.
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ZS Associates Aptitude Questions and Answers - Question 1

A train 300 m long crossed a platform 900 m long in 1 minute 12 seconds. The speed of the train in km/hr was:

Detailed Solution for ZS Associates Aptitude Questions and Answers - Question 1

Distance covered in 72 sec = (300+900)m
Speed = (1200/72)m/sec
=(50/3) m/sec
= (50/3 × 18/5) km/hr = 60 km/hr

ZS Associates Aptitude Questions and Answers - Question 2

If two mixers and one T.V cost Rs. 7000. While two T.V s and one mixer cost Rs. 9800. The value of one T.V is:

Detailed Solution for ZS Associates Aptitude Questions and Answers - Question 2

2X + Y = 7000
 X + 2Y = 9800
 Solving (i) and (ii), we get Y = 4200

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ZS Associates Aptitude Questions and Answers - Question 3

In a 500 m race, the ratio of the speeds of two contestants A and B is 3 : 4. A has a start of 140 m. Then, A wins by:

Detailed Solution for ZS Associates Aptitude Questions and Answers - Question 3

To reach the winning point , A will have to cover a distance of 500 – 140= 360 metre ratio of the speeds of two contestants A and B is 3 : 4
i.e., when A covers 3 metre, B covers 4 metre.
=> When A covers 360 metre, B covers 43×360 = 480 metre.
Remaining distance B have to cover = 500-480= 20 metre
=> A wins by 20 metre

ZS Associates Aptitude Questions and Answers - Question 4

In a bag, there are coins of 25 p, 10 p and 5 p in the ratio of 1:2:3. If there are Rs. 30 in all, how many 5 p coins are there?

Detailed Solution for ZS Associates Aptitude Questions and Answers - Question 4

Let the number of 25 p, 10 p and 5 p coins be x, 2x and 3x respectively.
Then, sum of their values = [25x/100 + (10 * 2x)/100 + (5 * 3x)/100] = Rs.
60x/100
60x/100 = 30 => x = 50.
Hence, the number of 5 p coins = 3 * 50 = 150.

ZS Associates Aptitude Questions and Answers - Question 5

Kruti took a loan at simple interest at 6 % in the first year with an increase of 0.5 % in each subsequent year. She paid Rs. 3375 as interest after 4 years. How much loan did she take?

Detailed Solution for ZS Associates Aptitude Questions and Answers - Question 5

Let the loan taken be Rs. X , then
X × 6/100 × 1 + X × 6.5/100 × 1 + X × 7/100 × 1 + X × 7.5/100 × 1 = 3375
=> (6+ 6.5 +7 +7.5) × X/100 = 3375
=> X = (3375 × 100/27) = 12500

ZS Associates Aptitude Questions and Answers - Question 6

7394 – 1236 – 4652 = ?

ZS Associates Aptitude Questions and Answers - Question 7

Amit starts from a point A and walks to another point B and then returns from B to A by his car and thus takes a total time of 6h and 45 min, if he had driven both ways in his car, then he would have taken 2hless.How long would it take for him to walk both ways?

Detailed Solution for ZS Associates Aptitude Questions and Answers - Question 7

Let w be the time taken in one way by walking and C be the time taken in one way By car.

ZS Associates Aptitude Questions and Answers - Question 8

A and B can do a work in 12 days, B and C in 15 days, C and A in 20 days. If A, B and C work together, they will complete the work in?

Detailed Solution for ZS Associates Aptitude Questions and Answers - Question 8

(A + B)’s 1 day work = 1/12;
(B + C)’s 1 day work = 1/15;
(A + C)’s 1 day work = 1/20
Adding, we get: 2(A + B + C)’s 1 day work = (1/12 + 1/15 + 1/20) = 1/5
(A + B + C)’s 1 day work = 1/10
So, A, B and C together can complete the work in 10 days.

ZS Associates Aptitude Questions and Answers - Question 9

A wooden box of dimensions 8m x 7m x 6m is to carry rectangular boxes of dimensions 8cm x 7cm x 6cm. The maximum number of boxes that can be carried in 1 wooden box is?

Detailed Solution for ZS Associates Aptitude Questions and Answers - Question 9

=Volume of the wooden boxVolume of one rectangular box=800×700×600/8×7×6=1000000

ZS Associates Aptitude Questions and Answers - Question 10

Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:

ZS Associates Aptitude Questions and Answers - Question 11

In how many different ways can the letters of the word ‘LEADING’ be arranged in such a way that the vowels always come together?

Detailed Solution for ZS Associates Aptitude Questions and Answers - Question 11

The word ‘LEADING’ has 7 different letters.
When the vowels EAI are always together, they can be supposed to form one letter.
Then, we have to arrange the letters LNDG (EAI).
Now, 5 (4 + 1 = 5) letters can be arranged in 5! = 120 ways.
The vowels (EAI) can be arranged among themselves in 3! = 6 ways.
 Required number of ways = (120 x 6) = 720

ZS Associates Aptitude Questions and Answers - Question 12

Pipes A and B can fill a tank in 5 and 6 hours respectively. Pipe C can empty it in 12 hours. If all the three pipes are opened together, then the tank will be filled in:

Detailed Solution for ZS Associates Aptitude Questions and Answers - Question 12

Therefore, correct option is C.

ZS Associates Aptitude Questions and Answers - Question 13

A bag contains 2 red, 3 green and 2 blue balls. Two balls are drawn at random. What is the probability that none of the balls drawn is blue?

ZS Associates Aptitude Questions and Answers - Question 14

The H.C.F. of two numbers is 23 and the other two factors of their L.C.M. are 13 and 14. The larger of the two numbers is:

Detailed Solution for ZS Associates Aptitude Questions and Answers - Question 14

Clearly, the numbers are (23 x 13) and (23 x 14).
 Larger number = (23 x 14) = 322.

ZS Associates Aptitude Questions and Answers - Question 15

What least number must be added to 1056, so that the sum is completely divisible by 23?

Detailed Solution for ZS Associates Aptitude Questions and Answers - Question 15

 Required number = (23 – 21)= 2.

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