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Triangles - Olympiad Level MCQ, Class 9 Mathematics - Class 9 MCQ


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15 Questions MCQ Test - Triangles - Olympiad Level MCQ, Class 9 Mathematics

Triangles - Olympiad Level MCQ, Class 9 Mathematics for Class 9 2025 is part of Class 9 preparation. The Triangles - Olympiad Level MCQ, Class 9 Mathematics questions and answers have been prepared according to the Class 9 exam syllabus.The Triangles - Olympiad Level MCQ, Class 9 Mathematics MCQs are made for Class 9 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Triangles - Olympiad Level MCQ, Class 9 Mathematics below.
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Triangles - Olympiad Level MCQ, Class 9 Mathematics - Question 1

Q. In the given figure AD is the bisector of ∠A and AB = AC. Then ΔACD, ΔADB are congruent by which criterion?

Triangles - Olympiad Level MCQ, Class 9 Mathematics - Question 2

In ΔABC if  ∠B = ∠ C = 45°, which of the following is the longest side ?

Detailed Solution for Triangles - Olympiad Level MCQ, Class 9 Mathematics - Question 2
BC because the angles B and C are smaller than angle A which makes the side B and AC smaller than BC.
Triangles - Olympiad Level MCQ, Class 9 Mathematics - Question 3

In a ΔABC if ∠ A = 45° and ∠B = 70° then the shortest and the largest sides of the triangle are :-

Detailed Solution for Triangles - Olympiad Level MCQ, Class 9 Mathematics - Question 3

In triangle ABC, we know that the sum of angles in a triangle is 180°. Therefore, we can express the angle ∠C as follows:

  • ∠C = 180° - (∠A + ∠B) = 65°

Using the Law of Sines, the sides are proportional to the sines of their opposite angles. Given the angles:

  • ∠A = 45°
  • ∠B = 70°
  • ∠C = 65°

We can determine the relationships between the sides:

  • Since ∠A (45°) < ∠C (65°) < ∠B (70°),
  • the shortest side is BC (opposite ∠A).
  • The largest side is AC (opposite ∠B).

Thus, the correct answer is option B: BC, AC.

Triangles - Olympiad Level MCQ, Class 9 Mathematics - Question 4

In Δ ABC if  ∠B = 45°, ∠ C = 65°, and the bisector of ∠BAC meets BC at P. Then the ascending order

of sides is :-

 

Triangles - Olympiad Level MCQ, Class 9 Mathematics - Question 5

In a ΔABC if 2∠ A = 3 ∠ B = 6 ∠ C then ∠ A ∠ B ∠ C are :

Detailed Solution for Triangles - Olympiad Level MCQ, Class 9 Mathematics - Question 5

Let’s denote the common value as k. Therefore, we have:

  • 2
  • 3
  • 6

Since the sum of angles in a triangle is 180°:

k/2 + k/3 + k/6 = 180.

Finding a common denominator (6):

  • (3k/6) + (2k/6) + (k/6) = 180.

Simplifying:

  • 6k/6 = 180 implies k = 180.

Thus, the angles are:

  • °,
  • °,
  • °.

Therefore, the measures of the angles are 90°, 60°, and 30°, corresponding to option B.

Triangles - Olympiad Level MCQ, Class 9 Mathematics - Question 6

By which congruency property, the two triangles connected by the following figure are congruent :-

 

Detailed Solution for Triangles - Olympiad Level MCQ, Class 9 Mathematics - Question 6
By SSS rule...they r congruent CB=DB (given)AC=AD (given)AB =AB(common)
Triangles - Olympiad Level MCQ, Class 9 Mathematics - Question 7

In ΔABC, AB = AC and AD is perpendicular to BC. State the property by which ΔADB ≌ADC :-

Detailed Solution for Triangles - Olympiad Level MCQ, Class 9 Mathematics - Question 7

Triangles ADB and ADC are right-angled at D, sharing equal hypotenuses:

  • AB = AC

This equality makes them congruent by the RHS property:

  • R - Right angle at D
  • H - Equal hypotenuses (AB = AC)
  • S - One side (AD) is the same in both triangles
Triangles - Olympiad Level MCQ, Class 9 Mathematics - Question 8

State the property by which ΔADB ≌ADC in the following figure :-

 

Triangles - Olympiad Level MCQ, Class 9 Mathematics - Question 9

In the given figure if AD = BC and AD || BC, then :

 

Detailed Solution for Triangles - Olympiad Level MCQ, Class 9 Mathematics - Question 9
The given figure is a parallelogram because AD=AB. Since,opposite sides of parallelogram are equal and also parallel. Therefore,AB will be equal to DC.
Triangles - Olympiad Level MCQ, Class 9 Mathematics - Question 10

In the figure given below, find the measure of the angles denoted by x,y, z,p,q and r.

Detailed Solution for Triangles - Olympiad Level MCQ, Class 9 Mathematics - Question 10

x = 180 - 100 [L.P. of angles] = 80°

Triangles - Olympiad Level MCQ, Class 9 Mathematics - Question 11

An exterior angle of a triangle is equal to the sum of two _________ angles :-

Detailed Solution for Triangles - Olympiad Level MCQ, Class 9 Mathematics - Question 11
A related theorem. Because an exterior angle is equal to the sum of the opposite interior angles, it follows that it must be larger than either one of them. Stated more formally: Theorem: An exterior angle of a triangle is always larger then either opposite interior angle.
Triangles - Olympiad Level MCQ, Class 9 Mathematics - Question 12

In the following, the set of measures which can form a triangle :-

Detailed Solution for Triangles - Olympiad Level MCQ, Class 9 Mathematics - Question 12

To determine which set of angles can form a triangle, we check if the sum of each set equals 180°.

  • Option A: 70 + 90 + 25 = 185° (Exceeds 180°)
  • Option B: 65 + 85 + 40 = 190° (Exceeds 180°)
  • Option C: 65 + 85 + 30 = 180° (Valid triangle)
  • Option D: 45 + 45 + 80 = 170° (Less than 180°)

Only Option C adds up to exactly 180°, making it the correct answer.

Triangles - Olympiad Level MCQ, Class 9 Mathematics - Question 13

Sum of any two sides of a triangle is always __________ third side in a triangle :-

Detailed Solution for Triangles - Olympiad Level MCQ, Class 9 Mathematics - Question 13

In a triangle, according to the triangle inequality theorem, the sum of the lengths of any two sides must be greater than the length of the remaining side. This ensures that the three sides can form a valid triangle.

Therefore, the correct answer is 'Greater than.'

Triangles - Olympiad Level MCQ, Class 9 Mathematics - Question 14

Can 90°, 90° and 20° form a triangle ?

Detailed Solution for Triangles - Olympiad Level MCQ, Class 9 Mathematics - Question 14

The sum of the angles in any triangle must be exactly 180°. Adding the given angles:

  • 90°
  • 90°
  • 20°

This results in:

90° + 90° + 20° = 200°, which exceeds 180°. Therefore, they cannot form a valid triangle.

Triangles - Olympiad Level MCQ, Class 9 Mathematics - Question 15

In the given figure it is given that AB = CF, EF = BD and Ð AFE = Ð DBC. Then DAFE congruent to DCBD by which criterion ?

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