JEE Exam  >  JEE Tests  >  Mathematics (Maths) for JEE Main & Advanced  >  Test: Properties Of Definite Integrals - JEE MCQ

Test: Properties Of Definite Integrals - JEE MCQ


Test Description

5 Questions MCQ Test Mathematics (Maths) for JEE Main & Advanced - Test: Properties Of Definite Integrals

Test: Properties Of Definite Integrals for JEE 2024 is part of Mathematics (Maths) for JEE Main & Advanced preparation. The Test: Properties Of Definite Integrals questions and answers have been prepared according to the JEE exam syllabus.The Test: Properties Of Definite Integrals MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Properties Of Definite Integrals below.
Solutions of Test: Properties Of Definite Integrals questions in English are available as part of our Mathematics (Maths) for JEE Main & Advanced for JEE & Test: Properties Of Definite Integrals solutions in Hindi for Mathematics (Maths) for JEE Main & Advanced course. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free. Attempt Test: Properties Of Definite Integrals | 5 questions in 10 minutes | Mock test for JEE preparation | Free important questions MCQ to study Mathematics (Maths) for JEE Main & Advanced for JEE Exam | Download free PDF with solutions
Test: Properties Of Definite Integrals - Question 1

The value of the integral is:

Detailed Solution for Test: Properties Of Definite Integrals - Question 1

Correct Answer : d

Explanation :  ∫(-1 to 1) e|x| dx

∫(-1 to 0) e|x|dx + ∫(0 to 1) e|x|dx

 e1 -1 + e1 - 1

=> 2(e - 1)

Test: Properties Of Definite Integrals - Question 2

Detailed Solution for Test: Properties Of Definite Integrals - Question 2

 ∫(-a to a)f(x)dx
= ∫(0 to a) [f(x) + f(-x)] if f(x) is an odd function
⇒ f(-x) = -f(x)

1 Crore+ students have signed up on EduRev. Have you? Download the App
Test: Properties Of Definite Integrals - Question 3

The value of   is: 

Test: Properties Of Definite Integrals - Question 4

The value of the integral   is:

Test: Properties Of Definite Integrals - Question 5

Detailed Solution for Test: Properties Of Definite Integrals - Question 5

∫(0 to 4)(x)1/2 - x2 dx
= [[(x)3/2]/(3/2) - x2](0 to 4)
= [[2x3/2]/3 - x2](0 to 4)
= [[2(0)3/2]/3 - (0)2]] -  [[2(4)3/2]/3 - (4)2]]
= 0-0
= 0

209 videos|443 docs|143 tests
Information about Test: Properties Of Definite Integrals Page
In this test you can find the Exam questions for Test: Properties Of Definite Integrals solved & explained in the simplest way possible. Besides giving Questions and answers for Test: Properties Of Definite Integrals, EduRev gives you an ample number of Online tests for practice

Top Courses for JEE

Download as PDF

Top Courses for JEE