Electrical Engineering (EE) Exam  >  Electrical Engineering (EE) Tests  >  GATE Electrical Engineering (EE) Mock Test Series 2025  >  Test: Network Theorems (A.C.) - 2 - Electrical Engineering (EE) MCQ

Test: Network Theorems (A.C.) - 2 - Electrical Engineering (EE) MCQ


Test Description

10 Questions MCQ Test GATE Electrical Engineering (EE) Mock Test Series 2025 - Test: Network Theorems (A.C.) - 2

Test: Network Theorems (A.C.) - 2 for Electrical Engineering (EE) 2024 is part of GATE Electrical Engineering (EE) Mock Test Series 2025 preparation. The Test: Network Theorems (A.C.) - 2 questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The Test: Network Theorems (A.C.) - 2 MCQs are made for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Network Theorems (A.C.) - 2 below.
Solutions of Test: Network Theorems (A.C.) - 2 questions in English are available as part of our GATE Electrical Engineering (EE) Mock Test Series 2025 for Electrical Engineering (EE) & Test: Network Theorems (A.C.) - 2 solutions in Hindi for GATE Electrical Engineering (EE) Mock Test Series 2025 course. Download more important topics, notes, lectures and mock test series for Electrical Engineering (EE) Exam by signing up for free. Attempt Test: Network Theorems (A.C.) - 2 | 10 questions in 30 minutes | Mock test for Electrical Engineering (EE) preparation | Free important questions MCQ to study GATE Electrical Engineering (EE) Mock Test Series 2025 for Electrical Engineering (EE) Exam | Download free PDF with solutions
Test: Network Theorems (A.C.) - 2 - Question 1

For the circuit given, determine the Thevenin voltage as seen by RL.

Detailed Solution for Test: Network Theorems (A.C.) - 2 - Question 1

Solution:

Thevenin Voltage Calculation:

- First, we need to find the Thevenin equivalent circuit for the given circuit.
- Remove the load resistor (RL) from the circuit.
- Calculate the equivalent resistance (Rth) looking back into the circuit.
- Calculate the open-circuit voltage (Voc) which is the Thevenin voltage.

Calculations:

- The Thevenin resistance (Rth) can be calculated by shorting all the independent sources and then finding the equivalent resistance looking back into the circuit.
- By shorting the voltage source, the circuit reduces to a simple resistive network, and Rth can be calculated.
- Once Rth is calculated, the next step is to find the open-circuit voltage (Voc) which is the Thevenin voltage.
- The Thevenin voltage can be calculated by finding the voltage across the terminals where the load resistor was connected with RL removed.
- The Thevenin voltage is the voltage between those two terminals.

Final Answer:

- The Thevenin voltage as seen by RL is 5.74 ∠-16.7° V.

Test: Network Theorems (A.C.) - 2 - Question 2

The Norton equivalent current is

1 Crore+ students have signed up on EduRev. Have you? Download the App
Test: Network Theorems (A.C.) - 2 - Question 3

The Thevenin equivalent voltage is

Test: Network Theorems (A.C.) - 2 - Question 4

In order to get maximum power transfer from a capacitive source, the load must

Test: Network Theorems (A.C.) - 2 - Question 5

Determine VTH if R1 is changed to 3.3 kΩ.

Test: Network Theorems (A.C.) - 2 - Question 6

Referring to the given circuit, find ZTH if R is 15 kΩ and RL is 38 kΩ.

Test: Network Theorems (A.C.) - 2 - Question 7

Determine VTH when R1 is 180 Ω and XL is 90 Ω.

Test: Network Theorems (A.C.) - 2 - Question 8

Find the voltage across 2Ω resistor due to 20V source in the circuit shown below:

Detailed Solution for Test: Network Theorems (A.C.) - 2 - Question 8

The voltage at node A in the figure is
(V - 20)/20 + (V - 10)/10 + V/2 = 0
⇒ V = 3.07V. Now short circuiting 10V source,

(V - 20)/20 + V/2 + V/10 = 0
⇒ V = 1.5V.

Test: Network Theorems (A.C.) - 2 - Question 9

Find the equivalent thevenin’s resistance between terminals A and B in the circuit shown below.

Detailed Solution for Test: Network Theorems (A.C.) - 2 - Question 9

To find Rth, two voltage sources are removed and replaced with short circuit. The resistance at terminals AB then is the parallel combination of the 10Ω resistor and 5Ω resistor

⇒ Rth=(10 × 5)/15 = 3.33Ω.

Test: Network Theorems (A.C.) - 2 - Question 10

Find the current flowing between terminals A and B of the circuit shown below.

Detailed Solution for Test: Network Theorems (A.C.) - 2 - Question 10

The magnitude of the current in Norton’s equivalent circuit is equal to the current passing through the short circuited terminals that are I = 20/5 = 4A.

25 docs|247 tests
Information about Test: Network Theorems (A.C.) - 2 Page
In this test you can find the Exam questions for Test: Network Theorems (A.C.) - 2 solved & explained in the simplest way possible. Besides giving Questions and answers for Test: Network Theorems (A.C.) - 2, EduRev gives you an ample number of Online tests for practice

Top Courses for Electrical Engineering (EE)

Download as PDF

Top Courses for Electrical Engineering (EE)