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Electrical Engineering (EE) Exam  >  Electrical Engineering (EE) Tests  >  Network Theory (Electric Circuits)  >  Test: Problems on Initial Conditions - Electrical Engineering (EE) MCQ

Test: Problems on Initial Conditions - Electrical Engineering (EE) MCQ


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10 Questions MCQ Test Network Theory (Electric Circuits) - Test: Problems on Initial Conditions

Test: Problems on Initial Conditions for Electrical Engineering (EE) 2024 is part of Network Theory (Electric Circuits) preparation. The Test: Problems on Initial Conditions questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The Test: Problems on Initial Conditions MCQs are made for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Problems on Initial Conditions below.
Solutions of Test: Problems on Initial Conditions questions in English are available as part of our Network Theory (Electric Circuits) for Electrical Engineering (EE) & Test: Problems on Initial Conditions solutions in Hindi for Network Theory (Electric Circuits) course. Download more important topics, notes, lectures and mock test series for Electrical Engineering (EE) Exam by signing up for free. Attempt Test: Problems on Initial Conditions | 10 questions in 30 minutes | Mock test for Electrical Engineering (EE) preparation | Free important questions MCQ to study Network Theory (Electric Circuits) for Electrical Engineering (EE) Exam | Download free PDF with solutions
Test: Problems on Initial Conditions - Question 1
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In the circuit shown below, steady state was reached when the switch ‘s’ was open. The switch was closed at t = 0. Then initial value of the current through the capacitor 2C is?

Detailed Solution for Test: Problems on Initial Conditions - Question 1

At steady-state conditions, the capacitor acts as an open circuit, and the inductor acts as a short circuit.

Now considering t = 0-,

Now voltage across 4 Ω resistor is 12 V.

Considering t = 0+

By KCL, 

i2c (0+) = 2 A

The initial value of the current through the capacitor 2 C is 2 A.

Test: Problems on Initial Conditions - Question 2
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In the circuit shown in the figure, the switch S is closed at time t = 0. The supply current at t = 0+ and the capacitor voltage at t → ∞ are, respectively

Detailed Solution for Test: Problems on Initial Conditions - Question 2

The switch s is closed at time, t = 0

At, t = 0+, the capacitor is short circuited and inductor is open circuited. Now circuit will become

At, t = ∞, the capacitor is open circuited and inductor is short circuited. Now the circuit will become

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*Answer can only contain numeric values
Test: Problems on Initial Conditions - Question 3
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If initial voltage retained by the capacitor C1 is 100 V and C2 is zero, the switch k is closed at t = 0, the voltage drop across capacitor C1  in steady state is ________ V


Detailed Solution for Test: Problems on Initial Conditions - Question 3

The circuit after the switch is closed is given in the s-domain in the below figure

The voltage drop across capacitor C1 is

= 33.33 V

*Answer can only contain numeric values
Test: Problems on Initial Conditions - Question 4
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The circuit shown in figure was at steady state for t < 0 with switch at position ‘A’. The switch is thrown to position ‘B’ at time t = 0. The voltage across the 10 ohm resistor at time t = 0+ is ________V.

Detailed Solution for Test: Problems on Initial Conditions - Question 4

At t < 0 the circuit was in steady state and switch at ‘A’

The current drawn by circuit i
= 

Current through the inductor IL­(0-)
= 

Immediately after t > 0 the circuit will be the current through Inductor IL­(0-) = IL­(0+)

at t= 0+

V = IL­(0+) × 10Ω

= -3 × 10 = -30V

*Answer can only contain numeric values
Test: Problems on Initial Conditions - Question 5
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When current changes from 4A to 0A in 0.1s in an inductor the induced emf is found to be 100V, then find the value of self-inductance is :

Detailed Solution for Test: Problems on Initial Conditions - Question 5

 

*Answer can only contain numeric values
Test: Problems on Initial Conditions - Question 6
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For the circuit shown in the figure, the value of  is _____ (in A/s)

Detailed Solution for Test: Problems on Initial Conditions - Question 6

At t = 0-, the circuit is as shown below.

i(0−) = 12 / 6 = 2A

V(0-) = 12 V

The inductor doesn’t allow the sudden change in current.

I(0+) = i(0-) = 2 A

Capacitor doesn’t allow the sudden change in voltage.

V(0-) = V(0+) = 12 V

At t = 0+, the circuit becomes,

By applying KVL,

-12 + 4(2) + 6(2) + VL(0+) = 0

VL(0+) = -8 V

Since  

 

Test: Problems on Initial Conditions - Question 7
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In the circuit shown in the figure, the switch s open for a long time. It is closed at t=0 For t>0 the current flowing through the inductor will be given by
Detailed Solution for Test: Problems on Initial Conditions - Question 7

For t < 0,S is open and network is in steady state so the inductor acts like a short circuit.

Test: Problems on Initial Conditions - Question 8
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The network shown in the figure given below reaches a steady state with the switch K in position a. At t = 0, the switch is moved from a to b by a make-before-break mechanism. Assume the initial current in 2 H inductors as zero. What is the current in 1 H inductor at t = 0+and t = ∞, respectively?
Detailed Solution for Test: Problems on Initial Conditions - Question 8

Before t = 0 the circuit is

I = 5/2 = 2.5 A

As t → ∞ the current tends to zero, since no power source is present in the circuit, the power stored inductor is dissipated through the resistor.

Test: Problems on Initial Conditions - Question 9
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Find  i(0+) and V (2 m sec) for the circuit shown below.
Detailed Solution for Test: Problems on Initial Conditions - Question 9

V(0−) = 50 V = V(0+)

For t > 0, RC = 1.6 m sec.

Test: Problems on Initial Conditions - Question 10
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In Reciprocity Theorem, which of the following ratios is considered?
Detailed Solution for Test: Problems on Initial Conditions - Question 10

The Reciprocity Theorem states that if an Emf E in one branch produces a current I in a second branch, then if the same emf E is moved from the first to the second branch, it will produce the same current in the first branch, when the Emf E in the first branch is replaced with a short circuit. Therefore the ratio of Voltage to Current is considered in case of Reciprocity Theorem.

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