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Test: Network Equation (Mesh & Node) - 2 - Electrical Engineering (EE) MCQ


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7 Questions MCQ Test Network Theory (Electric Circuits) - Test: Network Equation (Mesh & Node) - 2

Test: Network Equation (Mesh & Node) - 2 for Electrical Engineering (EE) 2025 is part of Network Theory (Electric Circuits) preparation. The Test: Network Equation (Mesh & Node) - 2 questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The Test: Network Equation (Mesh & Node) - 2 MCQs are made for Electrical Engineering (EE) 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Network Equation (Mesh & Node) - 2 below.
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Test: Network Equation (Mesh & Node) - 2 - Question 1

i1 = ?

Detailed Solution for Test: Network Equation (Mesh & Node) - 2 - Question 1


i1 = 0.02 A

Test: Network Equation (Mesh & Node) - 2 - Question 2

For the circuit of Fig. P1.3.38 the value of vs, that will result in v1 = 0, is

Detailed Solution for Test: Network Equation (Mesh & Node) - 2 - Question 2

If v1 = 0, the dependent source is a short circuit

Test: Network Equation (Mesh & Node) - 2 - Question 3

i1, i2 = ?

Detailed Solution for Test: Network Equation (Mesh & Node) - 2 - Question 3

ix = i1 - i2

 ....(i)

 ...(ii)

Test: Network Equation (Mesh & Node) - 2 - Question 4

v1 = ?

Detailed Solution for Test: Network Equation (Mesh & Node) - 2 - Question 4



Test: Network Equation (Mesh & Node) - 2 - Question 5

vx = ?

Detailed Solution for Test: Network Equation (Mesh & Node) - 2 - Question 5

Let i1 and i2 be two loop current

 ...(i)

 ...(ii)

Test: Network Equation (Mesh & Node) - 2 - Question 6

The power being dissipated in the 2Ω resistor in the circuit of Fig. P1.3.42 is

Detailed Solution for Test: Network Equation (Mesh & Node) - 2 - Question 6


Test: Network Equation (Mesh & Node) - 2 - Question 7

In given circuit diagram, determine the number of -
1. Junction points
II. Meshes​​​​​​​
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Detailed Solution for Test: Network Equation (Mesh & Node) - 2 - Question 7

Junction points in a circuit are points where three or more circuit elements meet. These are crucial for analyzing circuits using techniques like the Node-Voltage method. There are 4 junction points present in the given circuit.
A mesh is a loop that does not contain any other loops within it. Mesh analysis is a method used in circuit theory to find the current circulating around a mesh. There are 3 meshes in the given circuit.
In the given circuit diagram, determining the number of junction points and meshes is essential for applying Kirchhoff's rules.

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