All Courses
Get the App Signup / Login
Sign in Open App
Electrical Engineering (EE) Exam  >  Electrical Engineering (EE) Tests  >  Topicwise Question Bank for Electrical Engineering  >  Test: Basics of Digital Electronics- 2 - Electrical Engineering (EE) MCQ

Test: Basics of Digital Electronics- 2 - Electrical Engineering (EE) MCQ


Test Description

20 Questions MCQ Test Topicwise Question Bank for Electrical Engineering - Test: Basics of Digital Electronics- 2

Test: Basics of Digital Electronics- 2 for Electrical Engineering (EE) 2024 is part of Topicwise Question Bank for Electrical Engineering preparation. The Test: Basics of Digital Electronics- 2 questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The Test: Basics of Digital Electronics- 2 MCQs are made for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Basics of Digital Electronics- 2 below.
Solutions of Test: Basics of Digital Electronics- 2 questions in English are available as part of our Topicwise Question Bank for Electrical Engineering for Electrical Engineering (EE) & Test: Basics of Digital Electronics- 2 solutions in Hindi for Topicwise Question Bank for Electrical Engineering course. Download more important topics, notes, lectures and mock test series for Electrical Engineering (EE) Exam by signing up for free. Attempt Test: Basics of Digital Electronics- 2 | 20 questions in 60 minutes | Mock test for Electrical Engineering (EE) preparation | Free important questions MCQ to study Topicwise Question Bank for Electrical Engineering for Electrical Engineering (EE) Exam | Download free PDF with solutions
Test: Basics of Digital Electronics- 2 - Question 1
Save

Which of the following statements about digital systems are correct?
1. These are easier to design compared to analog systems.
2. These are highly affected by unwanted electrical signals.
3. Accuracy and precision of digital systems are greater when compared with analog systems.
4. The fabrication of digital ICs is complicated and costly than that of analog ICs.
Choose the correct code from the given options:

Detailed Solution for Test: Basics of Digital Electronics- 2 - Question 1

The advantages of digital systems over analog systems are as follows:
1. Easier to design.
2. Less affected by noise (unwanted electrical signals).
3. More accuracy and precision.
4. Simple and economical fabrication into ICs.

Test: Basics of Digital Electronics- 2 - Question 2
Save

(1010.01)2 - (111.111)2 results into

Detailed Solution for Test: Basics of Digital Electronics- 2 - Question 2


In binary system, we take borrow as 2 for subtraction.
Thus, (1010.01)2 - (111.111)2 = (0010.011)2.

1 Crore+ students have signed up on EduRev. Have you? Download the App
Test: Basics of Digital Electronics- 2 - Question 3
Save

Assertion (A): The advantage of performing subtraction by the complement method is reduction in the hardware.
Reason (R): Instead of having separate digital circuits for addition and subtraction, only adding circuits are needed for subtraction by complement method.

Detailed Solution for Test: Basics of Digital Electronics- 2 - Question 3

Both assertion and reason are correct and reason is the correct explanation of assertion because when subtraction is performed using complement method, then instead of subtracting one number from other, the complement of the subtrahend is added to the minued, Thus, subtraction is also performed by adders only as in case of addition. Due to this reason the hardware requirement is reduced while performing subtraction by complement method,

Test: Basics of Digital Electronics- 2 - Question 4
Save

The decimal equivalent of the hexadecimal number (A0F9.0EB)16 is
Detailed Solution for Test: Basics of Digital Electronics- 2 - Question 4

On multiplying the given hexadecimal number with the positional weightage, we get: (A0F9.0EB)16
= (10 x 163) + (0 x 162) + (15 x 161) + (9 x 160) + (0 x 16-1) + (14 x 16-2)+(11 x 16-3)
= 40960 + 0 + 240 + 9 + 0 + 0.0546 + 0.0026 
= (41209.0572)10

Test: Basics of Digital Electronics- 2 - Question 5
Save

If 100b = 1610, then the value of b would be equal to
Detailed Solution for Test: Basics of Digital Electronics- 2 - Question 5

On converting 100b to decimal, we have:
1 x b2 + 0 x b1 + 0 x b0 = 16
or, b2 = 16
or, b = 4

Test: Basics of Digital Electronics- 2 - Question 6
Save

Consider the following series with a missing number;
10000,121,100, ?, 24, 22, 20
If in the above series, the same integer is expressed in different number systems, the missing number of the series would be equal to
Detailed Solution for Test: Basics of Digital Electronics- 2 - Question 6
  • If we take the first number to be in binary (base 2), its equivalent will be (16)10 i.e. (10000)2 = (16)10.
  • The next number is 121; it is equal to (16)10 in base 3 i.e. (121)3 = (16)10
  • 100 is equal to (16)10 in base 4 i.e. (100)4 = (16)10.
  • (31)s = (16)10
  • (24)6 = (16)10
  • (22)7 = (16)10
  • (20)8 = (16)10

Hence, the missing number is 31 in base 5.

Test: Basics of Digital Electronics- 2 - Question 7
Save

Each of the following arithmetic operations is correct in at least one number system:
(i) 1234 + 5432 = 6666 is valid in any number system with base ≥ 6.
(ii) √41 = 5 is valid in a number system with base 6.
(iii) 302/20 = 12.1 is valid in a number system with base 5.
Out of the above arithmetic operations:
Detailed Solution for Test: Basics of Digital Electronics- 2 - Question 7
  • 1234 + 5432 = 6666
    i.e.,

    Since the largest digit used is 6, this arithmetic operation is valid in any number system with base ≥ 7
  • √41 = 5
    Let the base be 5.
    Then, its decimal equivalent operation is,
    or, 4b + 1 = 25 or, b = 6 Thus, the base is 6.
  • 302/20 = 12.1
    Expressing in decimal, we have:
    (3b2 + 2)/2b = b + 2 + 1/b
    or, 3b2 + 2 = 2b2 + 4b + 2
    or, b2 - 4b = 0 or b = 4
    (Neglecting b = 0)
    Thus, the base is 4.
    Hence, only (ii) is correct.
Test: Basics of Digital Electronics- 2 - Question 8
Save

Consider the following statements:
1. In a self-complementing code, the code word for the 9's complement of N is the 1’s complement of the codeword for N.
2. Each one of the 4-bit BCD codes has 6 illegal states.
3. The Gray code cannot be used for mathematical operations.
4. Excess-3 code can be used for mathematical operations.
Which of the statements given above is/are correct?
Detailed Solution for Test: Basics of Digital Electronics- 2 - Question 8
  • A code is said to be self-complementing, if the code word of the 9’s complement of N i.e. of (9-N) can be obtained from the code word of N by interchanging all the 0's and 1s. Thus, statement-1 is correct.
  • There are six illegal combinations in 4-bit BCD codes which are 1010, 1011, 1100, 1101, 1110 and 1111 and hence they are not part of the 8421 BCD code system. Thus, statement-2 is also correct.
  • The gray code can not be used for mathematical operations because it is non- weighted code. Thus, statement-3 is also correct.
  • The excess-3 code is also a non-weighted code, but can be used for mathematical operations because it is a sequential code. Thus, statement-4 is also correct.
Test: Basics of Digital Electronics- 2 - Question 9
Save

The ASCII code is a
Detailed Solution for Test: Basics of Digital Electronics- 2 - Question 9

The ASCII code is a alphanumeric code because it represents alphanumeric information i.e. fetters of the alphabet and decimal numbers as a sequence of 0s and 1s.

Test: Basics of Digital Electronics- 2 - Question 10
Save

Assertion (A): The 2’s complement system has two zeros, a positive 0 (all 0s) and a negative 0 (all 1’s).
Reason (R): The complement of the complement gives the original number
Detailed Solution for Test: Basics of Digital Electronics- 2 - Question 10

The 1’s complement system has a disadvantage of having two zero representation i.e. a positive 0 (all 0s) and a negative 0 (all 1s). But, the 2's complement system has a unique zero.
Hence, assertion is not a correct statement.

Test: Basics of Digital Electronics- 2 - Question 11
Save

Assertion (A): The computer method of division requires successive subtraction.
Reason (R): The computer method of multiplication requires repeated addition.
Test: Basics of Digital Electronics- 2 - Question 12
Save

Assertion (A): Gray code is sometimes called reflective code.
Reason (R): The n least significant bits for 2n through (2n +1- 1) are the mirror images for 0 through (2n-1).
Test: Basics of Digital Electronics- 2 - Question 13
Save

Which of the following 4-bit binary pairs does not forms a Gray code pair?
Detailed Solution for Test: Basics of Digital Electronics- 2 - Question 13

The Gray code is a cyclic code in which successive code words in this code differ in one bit position only i.e. it is a unit distance code. In options (a), (b) and (d) both the 4-bit binary numbers differ in one bit position only while in option (c) both the 4-bit binary numbers differs in two bit positions as shown below.

Hence, option (c) does not forms a gray code pair of two given 4-bit binary numbers.

Test: Basics of Digital Electronics- 2 - Question 14
Save

Match List-I (Data representation) with List-ll (Range with n-bits) and select the correct answer using the codes given below the lists:
List-1
A. Signed numbers in 1 ’s complement form
B. Signed magnitude
C. Unsigned magnitude
D. Signed numbers in 2’s complement form
List-ll
1. 0 to (2n - 1)
2. -(2n -1) to + (2n -1 - 1)
3. -(2n -1) to (2n -1)
4. -(2n -1 - 1) to + (2n -1 - 1)
Codes:
    A B C D
(a) 3 3 1 2
(b) 1 4 3 4
(c) 2 4 1 3
(d) 4 4 1 2
Test: Basics of Digital Electronics- 2 - Question 15
Save

A number is represented in 2’s complement as (1101)2. It’s equivalent decimal number is
Detailed Solution for Test: Basics of Digital Electronics- 2 - Question 15

2's complement representation of given number is (1101)2.
Since MSB is 1, therefore the required number must be negative.
1's complement of (1101)2 is (0010)2.
2's complement of 0010 - (0010)2 + (0001)2 = (0011)2.
Thus, the required number = -3 (Decimal equivalent of (0011)2 = 3).

Test: Basics of Digital Electronics- 2 - Question 16
Save

Match List-I with List-ll and select the correct answer using the codes given below the lists:
List-I
A. (345)8
B. (11011.011)2
C. (47)16
List-II
1. (1B.6)16
2. (229)10
3. (107)8
4. (326)10
5. (D8.7)16
Code:
     A B C
(a) 2 5 3
(b) 4 3 2
(c) 2 1 3
(d) 4 1 2
Detailed Solution for Test: Basics of Digital Electronics- 2 - Question 16
  • (345)8 = (82 x 3) + (81 x 4) + (80 x 5) = (229)10 (Octal to decimal conversion
  • (11011.011)2 = (Binary to Hexadecimal conversion)
  • (47)16 - (01000111)2 = = (107)8
    (Hexadecimal to Binary and then to Octal Conversion)
Test: Basics of Digital Electronics- 2 - Question 17
Save

Which of the following statements is/are correct in regard to excess-3 code?
Test: Basics of Digital Electronics- 2 - Question 18
Save

Multiplication of two binary numbers A and B is 11011. If A = 011, then B is
Detailed Solution for Test: Basics of Digital Electronics- 2 - Question 18

Let,
B = (b3 b2b1b0)2
Now,

Thus,
b0 = 1
b1 + b0 = 1   ∴ b1 = 0
b2 + b1 + 0 =  0   ∴ b2 = 0
b3 + 0 = 1   ∴ b3 = 1
Thus,
B = (b3b2b1b0)2
= (1001)2

Test: Basics of Digital Electronics- 2 - Question 19
Save

Which of the following statement is not correct in regard to the “GRAY Code”?
Detailed Solution for Test: Basics of Digital Electronics- 2 - Question 19

The Gray code is not a BCD code.

Test: Basics of Digital Electronics- 2 - Question 20
Save

Assertion (A): The “XS-3 code,” also called “Excess-3 code” is a non-weighted BCD code.
Reason (R): In XS-3 code, each binary code word is the corresponding 8421 code word plus 0011(3).
212 tests
Join Course
Information about Test: Basics of Digital Electronics- 2 Page
In this test you can find the Exam questions for Test: Basics of Digital Electronics- 2 solved & explained in the simplest way possible. Besides giving Questions and answers for Test: Basics of Digital Electronics- 2, EduRev gives you an ample number of Online tests for practice

Top Courses for Electrical Engineering (EE)

Download as PDF

Top Courses for Electrical Engineering (EE)

Important Questions for Basics of Digital Electronics- 2

Find all the important questions for Basics of Digital Electronics- 2 at EduRev.Get fully prepared for Basics of Digital Electronics- 2 with EduRev's comprehensive question bank and test resources. Our platform offers a diverse range of question papers covering various topics within the Basics of Digital Electronics- 2 syllabus. Whether you need to review specific subjects or assess your overall readiness, EduRev has you covered. The questions are designed to challenge you and help you gain confidence in tackling the actual exam. Maximize your chances of success by utilizing EduRev's extensive collection of Basics of Digital Electronics- 2 resources.

Basics of Digital Electronics- 2 MCQs with Answers

Prepare for the Basics of Digital Electronics- 2 within the Electrical Engineering (EE) exam with comprehensive MCQs and answers at EduRev. Our platform offers a wide range of practice papers, question papers, and mock tests to familiarize you with the exam pattern and syllabus. Access the best books, study materials, and notes curated by toppers to enhance your preparation. Stay updated with the exam date and receive expert preparation tips and paper analysis. Visit EduRev's official website today and access a wealth of videos and coaching resources to excel in your exam.

Online Tests for Basics of Digital Electronics- 2 Topicwise Question Bank for Electrical Engineering

Practice with a wide array of question papers that follow the exam pattern and syllabus. Our platform offers a user-friendly interface, allowing you to track your progress and identify areas for improvement. Access detailed solutions and explanations for each test to enhance your understanding of concepts. With EduRev's Online Tests, you can build confidence, boost your performance, and ace Basics of Digital Electronics- 2 with ease. Join thousands of successful students who have benefited from our trusted online resources.
© EduRev
Education Revolution
Follow Us
Signup to see your scores go up
within 7 days!
Takes less than 10 seconds to signup