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Test: Semiconductor Physics - Electrical Engineering (EE) MCQ


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10 Questions MCQ Test GATE Electrical Engineering (EE) Mock Test Series 2025 - Test: Semiconductor Physics

Test: Semiconductor Physics for Electrical Engineering (EE) 2024 is part of GATE Electrical Engineering (EE) Mock Test Series 2025 preparation. The Test: Semiconductor Physics questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The Test: Semiconductor Physics MCQs are made for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Semiconductor Physics below.
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Test: Semiconductor Physics - Question 1

The mobility of free electrons and holes in pure germanium are 3800 and 1800 cm2/V-s respectively. The corresponding values for pure silicon are 1300 and 500 cm2/V-s, respectively. Assuming ni = 2.5 x 1013 cm-3 for germanium and ni = 1.5 x 1010 cm-3 for silicon at room temperature, the values of intrinsic conductivity for germanium and silicon are respectively given by

Detailed Solution for Test: Semiconductor Physics - Question 1

The intrinsic conductivity for germanium is

The intrinsic conductivity for silicon is

Test: Semiconductor Physics - Question 2

What is the concentration of holes and electrons in n-type Silicon at 300°K, if the conductivity is 30 S/cm?
Assume at 300°K, ni = 1.5 x 1010/cm3, μn = 1300 cm2/V-s and μp= 500 cm2/V-s

Detailed Solution for Test: Semiconductor Physics - Question 2

The conductivity of an n-type silicon is a σ = qn μn.
Concentration of electrons,

Using “mass-action law'',


∴ Concentration of holes,

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Test: Semiconductor Physics - Question 3

When an electric field is applied across a semiconductor, free electrons in it will accelerate due to the applied field, and gain energy. This energy can be lost as heat when the electrons

Detailed Solution for Test: Semiconductor Physics - Question 3

When an electron is accelerated by the potential applied to a semiconductor, the energy gained from the field may then be transferred to an atom when the electron collides with the atom.

Test: Semiconductor Physics - Question 4

If a current of 1.6 μA is flowing through a conductor, the number of electrons crossing a particular cross-section per second will be

Detailed Solution for Test: Semiconductor Physics - Question 4

Given, I = 1.6 x 10-6 A
= 1.6 x 10-6 Coulomb/second
Charge crossing a particular cross-section per second = 1.6 x 10-6 C Hence, number of electrons crossing a particular cross-section per second

Test: Semiconductor Physics - Question 5

Match List-l with List-lI and select the correct answer using the codes given below the lists:


Detailed Solution for Test: Semiconductor Physics - Question 5

Energy band diagram for semiconductor, metal and insulator are shown below.

Test: Semiconductor Physics - Question 6

If elements in column IV of the periodic table are placed in increasing order of their atomic number, the order will be 

Test: Semiconductor Physics - Question 7

Assertion (A): The drift velocity is in the direction opposite to that of the electric field.
Reason (R): At each inelastic collision with an ion, an electron loses energy, and a steady-state condition is reached where a finite value of drift speed is attained.

Detailed Solution for Test: Semiconductor Physics - Question 7

Both assertion and reason are individually correct statements. However, the reason for assertion is that due to the applied electric field, and electrostatic force is developed on the electron and the electrons would be accelerated in a direction opposite to the applied electric field and this motion is called directed motion of electron.

Test: Semiconductor Physics - Question 8

The density and mobility of electrons in a conductor are respectively 1020/cm3 and 800 cm2/V-s. If a uniform electric field of 1 V/cm exists across this conductor, then the electron current density would be approximately

Detailed Solution for Test: Semiconductor Physics - Question 8

The current density is given by 

Test: Semiconductor Physics - Question 9

A semiconductor is doped with a donor density ND and no acceptors. If the intrinsic concentration is ni then the free electron density(n) will be equal to

Detailed Solution for Test: Semiconductor Physics - Question 9

Given, NA = 0
Using “charge neutrality equation”, we have:
ND + P = NA + n
or, ND + p = ....(i) 
Using'“Mass-action law”, we have:

Substituting value of p from equation (ii) in equation (i), we have:



Neglecting negative sign, we get:

= free electron density or concentration

Test: Semiconductor Physics - Question 10

In a p-type semiconductor, p = 1016/cm2, and μp = 400 cm2/V-s. If a magnetic field (B) of 5 x 10-4 Weber/cm2 is applied in the x-direction, and an electric field of 2000 V/m is applied in +y direction. The value of electric field caused due to the “Hall effect” is

Detailed Solution for Test: Semiconductor Physics - Question 10

The force acting on a charge q placed in a magnetic field B and an electric field E is given by
F = qv x B
The velocity of the hole placed in an electric field is


Now, F - + q E ...(ii) (+q = charge on a hole)
Comparing equations (i) and (ii), the electric field due to the Hall effect will be -400 V/cm in +z direction.

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