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Test: Control Systems - 1 - Electrical Engineering (EE) MCQ


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15 Questions MCQ Test - Test: Control Systems - 1

Test: Control Systems - 1 for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Test: Control Systems - 1 questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The Test: Control Systems - 1 MCQs are made for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Control Systems - 1 below.
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Test: Control Systems - 1 - Question 1

Traffic light system is the example of:

Detailed Solution for Test: Control Systems - 1 - Question 1

The traffic lamp will glow according to the set timing and sequence and is time-dependent. The sequence and time are controlled by relays that work on the pre-programmed time. It does not depend upon the rush of the road.
Hence the correct answer is an option (a).

Test: Control Systems - 1 - Question 2

The negative feedback closed-loop system was subjected to 15V. The system has a forward gain of 2 and a feedback gain of 0.5. Determine the output voltage and the error voltage.

Detailed Solution for Test: Control Systems - 1 - Question 2

Given:
G(s) = 2
H(s) = 0.5 and R(s) = 10V
Output voltage:
= (2/1+2x 0.5) x 15 = 15V
Error voltage:
= (1/1+2x 0.5) x 15 = 7.5V
Hence the correct answer is option (c).

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Test: Control Systems - 1 - Question 3

The force equation of the given system is:

Detailed Solution for Test: Control Systems - 1 - Question 3

Given: x is the displacement in the above diagram. The Laplace transform of x is X(s). The differential equations governing the system are the balanced force equation at these nodes.
Here,
F is the opposite force due to mass.
F =
f is the opposite force due to friction
F =
k is the ideal elastic spring element that has negligible mass and friction. The force generated by the spring is directly proportional to the displacement of the body.
F = Kx
So, the force equation can be represented as:


Hence, the correct answer is an option (c).

Test: Control Systems - 1 - Question 4

Loop gain is equal to:

Detailed Solution for Test: Control Systems - 1 - Question 4

According to Mason's Gain formula, the transfer function can be calculated as:
T(s) = C(s)/R(s)

Where,
Pk is the forward path gain
∆ is the loop gain, which is calculated as:
∆ = 1-∑(All loop gain) + ∑(Gain product of two non-touch in gloops) - ∑(Gain product of three non-touching loops)
∆k is calculated bye liminating all loops touching Pk
Here, the loop gain is defined as the product of the branch gain that is traversing a forward path.
Hence, the correct answer is an option (b).
The Mason's gain formula is used to find the overall transfer function of a signal graph.

Test: Control Systems - 1 - Question 5

The block diagram representation of a closed-loop system. Write the time response equation for the given system with a unit step input, assuming zero initial conditions.

Detailed Solution for Test: Control Systems - 1 - Question 5

The transfer function of a loop is G/(1+GH)
We will first simplify the above block diagram into the simple system. Let's calculate the transfer function of the first loop.
TF = [1/ (40s+2)] / [1 + 2/ (40s+2)] = 1/ (40s +4)
Now, two blocks are left in cascade. The equivalent block is the product of these two blocks, as given below:
C(s)/R(s) = 4. (1/ (40s +4)) = 1/ (10s + 1)
The Laplace transform of the step input is 1/s. It means R(s) = 1/s.
C(s) = [1/ (10s + 1)]. R(s)
C(s) = [1/ s (10s + 1)
Taking the inverse Laplace of the above equation, we get:
1-e-t⁄10

Test: Control Systems - 1 - Question 6

The transfer function of a system is given as 81/ (s2 + 16s + 81). Find the undamped natural frequency, damping ratio, and peak time for a unit step input.

Detailed Solution for Test: Control Systems - 1 - Question 6

The standard transfer function can be written as:


The given equation is: 81/ (s2 + 16s + 81)
Comparing the values, we get:

Thus, the undamped natural frequency is 9, and the damping ratio is 0.889.
The Peak time can be calculated as:


Hence, the correct answer is an option (a).

Test: Control Systems - 1 - Question 7

Consider a system with transfer function G(s) = (s + 4)/ (ks2 + s + 4). The value of damping ratio will be 0.5 when the value of k is:

Detailed Solution for Test: Control Systems - 1 - Question 7

The given transfer function is:
G(s) = (s + 4)/ (ks2 + s + 4)
The characteristic equation ks2 + s + 4 = 0
Dividing the equation by k, we get:
S2 +s/k + 4/k = 0

Hence, the correct answer is an option (b).

Test: Control Systems - 1 - Question 8

The transfer function of a control system is given by G(s) = 25/ (s2 + 6s + 25). The first maximum value of the response occurs at t, which is given by:

Detailed Solution for Test: Control Systems - 1 - Question 8

The given transfer function is: G(s) = 25/ (s2 + 6s + 25)
Comparing the value of the given transfer function with the standard equation


we know

Hence, the correct answer is option (c).

Test: Control Systems - 1 - Question 9

Calculate the poles and zeroes for the given transfer function G(s) = 5 (s + 2)/ (s2 + 3s + 2)

Detailed Solution for Test: Control Systems - 1 - Question 9

The zeroes can be calculated by equating the numerator to zero:
5 (s + 2) = 0
5s + 10 = 0
5s = -10
s = -2
The poles can be calculated by equating the denominator to zero:
s2 + 3s + 2 = 0
s2 + 2s + s + 2 = 0
s (s + 2) + 1 (s + 2) = 0
(s + 1) (s + 2) = 0
s = -1, -2
Hence, the correct answer is an option (a).

Test: Control Systems - 1 - Question 10

The centroid in the root locus is a point where

Detailed Solution for Test: Control Systems - 1 - Question 10

Centroid is defined as a common point where all the asymptotes intersect on the real axis. The value of centroid is always real. But, it can be located either on the positive or negative real axis.

Test: Control Systems - 1 - Question 11

In a bode-plot of a unity feedback control system, the value of phase of G(jw) at the gain cross over frequency is -115 degrees. The phase margin of the system is:

Detailed Solution for Test: Control Systems - 1 - Question 11

The phase margin can be calculated as 180 +
Where,
∅ is the phase of G(jw) at the gain cross over frequency.
So, phase margin = 180 + (-115)
= 180 - 115
= 65 degrees
Hence, the correct answer is an option (d).

Test: Control Systems - 1 - Question 12

Determine the phase cross-over frequency of the given open-loop transfer function:
G(s) = 1 / s(s + 1) (2s + 1)

Detailed Solution for Test: Control Systems - 1 - Question 12

The given open-loop transfer function is: G(s) = 1 / s(s + 1) (2s + 1)

The imaginary part of the system at phase cross over frequency is zero. Hence, we will equate the imaginary part to zero, as shown below:

It means that the phase cross-over frequency to the system is 0.707 Radians/s.
Hence, the correct answer is an option (c).

Test: Control Systems - 1 - Question 13

Which of the following statements are correct?

1. Bode plot is in the frequency domain.
2. Root locus is in the time domain.
3. Nyquist criteria are in the frequency domain.
4. Routh Hurwitz's criteria are in the time domain.

Detailed Solution for Test: Control Systems - 1 - Question 13

The Bode plot is defined as the frequency response plot of the sinusoidal transfer function of a system. The two graphs of the Bode plot are the plot of magnitude and phase angle. Thus, it is in the frequency domain.

The Nyquist plot is considered as the extension of the polar plot. The variation of frequency from infinity to -infinity results in the plot, known as the Nyquist plot. Hence, the Nyquist criterion is in the frequency domain.

Hence, the correct answer is an option (b).

Test: Control Systems - 1 - Question 14

Calculate the damping ratio of the system whose phase margin is 45 degrees.

Detailed Solution for Test: Control Systems - 1 - Question 14

The formula to calculate the damping ratio using the phase margin is:
Damping Ratio = tan∅√cos ∅⁄2
= ((tan45√cos45))⁄2
= 0. 42
Hence, the correct answer is an option (b).

Test: Control Systems - 1 - Question 15

The most powerful controller is:

Detailed Solution for Test: Control Systems - 1 - Question 15

The PID is the combination of proportional, integral, and derivate control modes. Such a combination makes it the most powerful controller.

Hence, the correct answer is an option (c).

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