NEET Exam  >  NEET Tests  >  Physics Class 11  >  Test: Newton’s First Law of Motion - NEET MCQ

Test: Newton’s First Law of Motion - NEET MCQ


Test Description

10 Questions MCQ Test Physics Class 11 - Test: Newton’s First Law of Motion

Test: Newton’s First Law of Motion for NEET 2024 is part of Physics Class 11 preparation. The Test: Newton’s First Law of Motion questions and answers have been prepared according to the NEET exam syllabus.The Test: Newton’s First Law of Motion MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Newton’s First Law of Motion below.
Solutions of Test: Newton’s First Law of Motion questions in English are available as part of our Physics Class 11 for NEET & Test: Newton’s First Law of Motion solutions in Hindi for Physics Class 11 course. Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free. Attempt Test: Newton’s First Law of Motion | 10 questions in 10 minutes | Mock test for NEET preparation | Free important questions MCQ to study Physics Class 11 for NEET Exam | Download free PDF with solutions
Test: Newton’s First Law of Motion - Question 1

A car of mass 1000 kg is moving at a velocity of 20 m/s. Suddenly, the driver applies the brakes, and the car comes to a stop in 4 seconds. What is the magnitude of the average force exerted by the brakes on the car? (Assume no external forces are acting on the car)

Detailed Solution for Test: Newton’s First Law of Motion - Question 1

Given:
Mass of the car (m) = 1000 kg
Initial velocity (u) = 20 m/s
Final velocity (v) = 0 m/s
Time (t) = 4 s

Using the equation of motion: v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time, we can rearrange the equation to solve for the acceleration.

0 = 20 m/s + a * 4 s
a = -5 m/s² (negative sign indicates deceleration)

Since the car comes to a stop, its final velocity is 0 m/s. We can use Newton's second law, F = ma, where F is the force, m is the mass, and a is the acceleration, to find the magnitude of the force.

F = 1000 kg * (-5 m/s²)
F = -5000 N

The magnitude of the force is 5000 N. However, since the force is acting in the opposite direction to the car's motion (deceleration), we take the magnitude as the answer.

Therefore, the correct answer is A: 5000N.

Test: Newton’s First Law of Motion - Question 2

A block of mass 2 kg is initially at rest on a frictionless horizontal surface. A force of 8 N is applied to the block horizontally for 5 seconds. What is the final velocity of the block?

Detailed Solution for Test: Newton’s First Law of Motion - Question 2

Given:
Mass of the block (m) = 2 kg
Force applied (F) = 8 N
Time (t) = 5 s

Since no external forces are acting on the block other than the applied force, the net force is equal to the applied force. Using Newton's second law, F = ma, where F is the force, m is the mass, and a is the acceleration.

8 N = 2 kg * a
a = 4 m/s²

Now, we can use the equation of motion: v = u + at, where v is the final velocity, u is the initial velocity (which is 0 m/s), a is the acceleration, and t is the time.

v = 0 + 4 m/s² * 5 s
v = 20 m/s

Therefore, the final velocity of the block is 20 m/s.

1 Crore+ students have signed up on EduRev. Have you? Download the App
Test: Newton’s First Law of Motion - Question 3

Two masses are in the ratio 1:5. What is ratio of their inertia?

Detailed Solution for Test: Newton’s First Law of Motion - Question 3

Force of inertia = ma

Let the masses be 1x and 5x

Force of inertia for 1st body= 1x * a

Force of inertia for 2nd = 5x * a

Ratio= x * a / 5x * a = 1:5

Additional Information: The inability of a body to change it’s state of rest or uniform motion is called inertia.

Test: Newton’s First Law of Motion - Question 4

A 6 kg object is subject to three forces
F1 = 20+ 30j N
F2 = 8i - 50j N
F3 = 2i + 2j N
Find the acceleration of object.

Detailed Solution for Test: Newton’s First Law of Motion - Question 4

F = F1 + F2 + F3 = ( 20i + 30j) N+(8i - 50j) N+(2i +2 j) N

=(20+8+2)i+(30-50+2)j

F=30i - 18j

F = ma

Substituting F and m = 6 kg (given) in the above equation we get,

30i - 18j = 6*a

A = 5i - 3j

Hence (b) is correct choice

Test: Newton’s First Law of Motion - Question 5

A body of mass 2kg is sliding with a constant velocity of 4m/s on a frictionless horizontal table. The net force required to keep the body moving with the same velocity is

Detailed Solution for Test: Newton’s First Law of Motion - Question 5

According to newton's first law of motion, an object either remains at rest or continues to move at a constant velocity, unless acted upon by an external net force.
Therefore The force required to keep the body moving with the same velocity is zero.

Test: Newton’s First Law of Motion - Question 6

An object of mass 5 kg is initially moving with a velocity of 10 m/s. An unbalanced force of 30 N is applied to the object in the opposite direction of its motion. Calculate the acceleration of the object.

Detailed Solution for Test: Newton’s First Law of Motion - Question 6

To calculate the acceleration of the object, we can use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration.

Given:
Mass of the object (m) = 5 kg
Initial velocity (u) = 10 m/s
Force applied (F) = -30 N (opposite direction of motion)

Using Newton's second law, F = ma,
we can rearrange the equation to solve for acceleration (a).
-30 N = 5 kg * a
a = -6 m/s2 (negative sign indicates the opposite direction)

Therefore, the acceleration of the object is 6 m/s2 in the opposite direction of its initial motion.

The correct answer is a) 6 m/s2.

Test: Newton’s First Law of Motion - Question 7

We slip on a rainy day due to ______.

Detailed Solution for Test: Newton’s First Law of Motion - Question 7
  • It is usually seen that during rainy days we tend to slip because rainwater acts as a lubricant between our feet and the ground.  

  • This lubrication (rainwater) converts dry friction into fluid friction. 

  • That is, the friction between feet and ground reduces, making us slip.

Therefore, due to less friction, we slip on a rainy day.

Test: Newton’s First Law of Motion - Question 8

Passengers in a bus lean forward as bus suddenly stops. This is due to

Detailed Solution for Test: Newton’s First Law of Motion - Question 8

When the bus moves, the passenger's body comes into a state of motion but when the bus stops the lower part of the body which is in contact with the floor comes into a state of rest whereas the upper part of the body still remains in the state of motion and because of this the upper part of the body falls in the forward direction. This is due to the presence of inertia. 

Hence the correct answer is C.

Test: Newton’s First Law of Motion - Question 9

A particle of mass 'm' original at rest, is subjected to a force whose direction is constant but whose magnitude varies with according to the relation
 

Where F0​ and T are constant.
Then speed of the particle after a time 2T is:

Detailed Solution for Test: Newton’s First Law of Motion - Question 9

Given: 


Speed of the particle after a time 2T, 



Test: Newton’s First Law of Motion - Question 10

How is inertia used when riding a bicycle?

Detailed Solution for Test: Newton’s First Law of Motion - Question 10
  • Newton’s first law of inertia states that an object at rest or in motion tends to stay at rest or moving with constant motion unless enacted upon by an unbalanced force. 

  • The law of inertia relates to the sport of cycling due to the fact that the cyclist is in constant motion when on the cycle. 

  • The motion of the bike is caused by the rider pressing down upon the pedals, which, in turn, enables the rider to accelerate on the bike. 

  • As well, the cyclist will continue to move unless enacted upon by an opposing unbalanced force, such as the force of friction on the bike tires, when the bike decelerates to a stop. 

  • The Law of Inertia is also displayed when the cyclist begins to move on the bicycle from a stop. 

  • The action is related to the concept of Inertia for the reason that the cyclist is applying an unbalanced force to the bicycle pedals when not in motion. As a result, the bicycle would gain acceleration and therefore begin to move.

Therefore the correct answer is B. 

102 videos|411 docs|121 tests
Information about Test: Newton’s First Law of Motion Page
In this test you can find the Exam questions for Test: Newton’s First Law of Motion solved & explained in the simplest way possible. Besides giving Questions and answers for Test: Newton’s First Law of Motion, EduRev gives you an ample number of Online tests for practice

Top Courses for NEET

102 videos|411 docs|121 tests
Download as PDF

Top Courses for NEET