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Test: Structure of Atom (May 11) - NEET MCQ


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15 Questions MCQ Test Daily Test for NEET Preparation - Test: Structure of Atom (May 11)

Test: Structure of Atom (May 11) for NEET 2024 is part of Daily Test for NEET Preparation preparation. The Test: Structure of Atom (May 11) questions and answers have been prepared according to the NEET exam syllabus.The Test: Structure of Atom (May 11) MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Structure of Atom (May 11) below.
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Test: Structure of Atom (May 11) - Question 1

Radiation of λ = 155 nm was irradiated on Li (work function = 5eV) plate. The stopping potential (in eV) is.

Detailed Solution for Test: Structure of Atom (May 11) - Question 1

3 eV
Corite Actual
Correct option

= 8 – 5
= 3eV
∴ V0 = 3 eV

Test: Structure of Atom (May 11) - Question 2

If in the hydrogen atom P.E. at ∞ is choosen to be 13.6 eV then the ratio of T.E. to K.E. for 1st orbit of H-atom is __________ .

Detailed Solution for Test: Structure of Atom (May 11) - Question 2

Zero
Refrence level is Ist orbit
itself T. E. = 0
Ratio becomes zero

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Test: Structure of Atom (May 11) - Question 3

The light radiations with discrete quantities of energy are called ___________ .

Detailed Solution for Test: Structure of Atom (May 11) - Question 3

A photon is the quantum of electromagnetic radiation. The term quantum is the smallest elemental unit of a quantity, or the smallest discrete amount of something. Thus, one quantum of electromagnetic energy is called a photon. The plural of quantum is quanta.

Test: Structure of Atom (May 11) - Question 4

The energy of electron is maximum at :

Detailed Solution for Test: Structure of Atom (May 11) - Question 4

An electron bound to the nucleus by the mutual attraction between unlike charges, has a negative energy. Its most tightly bound to the nucleus nearer it is to the nucleus. That is an electron has least energy when it is in the n=1 shell. As the electron moves away from the nucleus its energy becomes less and less negative, i.e. its energy increases. When the electron is not under the attractive Coulomb force of the nucleus its potential energy is zero and whatever energy it has now, is kinetic energy, which is always positive. So farther the electron more energy it has.

Test: Structure of Atom (May 11) - Question 5

Which electronic level would allow the hydrogen atom to absorb a photon but not to emit a photon:

Detailed Solution for Test: Structure of Atom (May 11) - Question 5

Is → As it is the ground state

Test: Structure of Atom (May 11) - Question 6

The orbital angular momentum of an electron in 2s orbital is :

Detailed Solution for Test: Structure of Atom (May 11) - Question 6

Orbital Angular momentum is given by [√l(l+1)]×h/2π
For s orbital, we have l = 0
Therefore orbital angular momentum = 0

Test: Structure of Atom (May 11) - Question 7

Which quantum number is not related with Schrodinger equation :

Detailed Solution for Test: Structure of Atom (May 11) - Question 7

Spin quantum number do not follow Schrodinger Wave Equation because it is related to spin of the electrons.It is needed to explain Pauli's exclusion principle which sates that no two electrons can share the same state (i.e. have the same quantum numbers) at the same time.Therefore, if the quantum numbers n, l and are same then the electrons should have different spin.

Test: Structure of Atom (May 11) - Question 8

An electron in a hydrogen atom in its ground state absrobs energy equal to the ionisation energy of Li+2. The wavelength of the emitted electron is

Detailed Solution for Test: Structure of Atom (May 11) - Question 8

 

V2 = 4.32 × 1013
V2 = 43.2 × 1012
V = 6.57 × 106

Test: Structure of Atom (May 11) - Question 9

Given ΔH for the process Li(g) → Li+3(g) + 3e- is 19800 kJ/mole & IE1 for Li is 520 then IE2 & IE3 of Li+ are respectively (approx, value) :

Detailed Solution for Test: Structure of Atom (May 11) - Question 9

IE1 + IE2 + IE3 = 19800
IE2 + IE3 = 19800 – 520
IE2 + IE3 = 19280

Test: Structure of Atom (May 11) - Question 10

The ratio of difference in wavelengths of 1st and 2nd lines of Lyman series in H-like atom to difference in wavelength for 2nd and 3rd lines of same series is :

Detailed Solution for Test: Structure of Atom (May 11) - Question 10




Test: Structure of Atom (May 11) - Question 11

The ratio of wave length of photon corresponding to the α-line of lyman series in H-atom and β-line of Baimer series in He+ is

Detailed Solution for Test: Structure of Atom (May 11) - Question 11


Test: Structure of Atom (May 11) - Question 12

Three energy levels P, Q, R of a certain atom are such that EP < EQ < ER. If λ1, λ2, and λ3, are the wave length of radiation corresponding to transition R → Q : Q → P and R → P respectively. The correct relationship between λ1, λ2 and λ3 is

Detailed Solution for Test: Structure of Atom (May 11) - Question 12

We know that, for wave no.

Test: Structure of Atom (May 11) - Question 13

The first use of quantum theory to explain the structure of atom was made by :

Detailed Solution for Test: Structure of Atom (May 11) - Question 13

Bohr's theory was based upon some postulations of classical physics and some postulations of the newly proposed quantum theory of Planck. 

Test: Structure of Atom (May 11) - Question 14

What is uncertainity in location of a photon of wavelength 5000 Å if wavelength is known to an accuracy of 1 pm?

Detailed Solution for Test: Structure of Atom (May 11) - Question 14




0.0199 m

Test: Structure of Atom (May 11) - Question 15

A 1-kW radio transmitter operates at a frequency of 880 Hz. How many photons per second does it emit -

Detailed Solution for Test: Structure of Atom (May 11) - Question 15

Given :
P = 1 kW
P = 1 × 103 watt
E = 103 J/S in one sec
v = 880 Hz
∴ E = nhv
⇒  103 x  ×  6.626 × 10–34 × 880
⇒  x = 1.71 × 1033 in one sec

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