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Chemistry: Topic-wise Test- 1 - NEET MCQ


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Chemistry: Topic-wise Test- 1 - Question 1

The vapour density of a mixture of gas A (Molecular mass = 40) and gas B (Molecular mass = 80) is 25.Then mole % of gas B in the mixture would be

Detailed Solution for Chemistry: Topic-wise Test- 1 - Question 1

As vapour density of mixture is 25,

Molar mass of mixture is 2×25=50.

Now, assume mole % of B in mixture is x.

Chemistry: Topic-wise Test- 1 - Question 2

Atomic mass of Cl is 35.5 g. Calculate the mass of 4.50 moles of chlorine gas, Cl2.​

Detailed Solution for Chemistry: Topic-wise Test- 1 - Question 2

Mass of 1 mole of Clis 71 g. Hence mass of 4.50 moles is 71 X 4.50 = 319.5 g

Chemistry: Topic-wise Test- 1 - Question 3

Modern periodic table is based on atomic no. experiments which proved importance of at no. was -

Detailed Solution for Chemistry: Topic-wise Test- 1 - Question 3

Moseley's work on X-ray spectra proved the significance of the atomic number.

Chemistry: Topic-wise Test- 1 - Question 4

Atomic wt. or Cl = 35.5 and of I = 127. According to doeberiner triad rule, At. wt. of Br will be -

Detailed Solution for Chemistry: Topic-wise Test- 1 - Question 4

Chemistry: Topic-wise Test- 1 - Question 5

The elements of groups, 1, 2, 13, 14, 15, 16 and 17 are collectively called -

Detailed Solution for Chemistry: Topic-wise Test- 1 - Question 5

Representative elements in modern periodic table
The first two groups on the extreme left and last six groups on the extreme right involve the filling of s- and p- orbitals, respectively, These groups represent the main groups of the periodic table and are numbered as 1, 2, 13, 14, 15, 16, 17 and 18. The elements present in these groups are known as normal elements or representative elements.

Chemistry: Topic-wise Test- 1 - Question 6

Justification of putting H in VII A group is -

Detailed Solution for Chemistry: Topic-wise Test- 1 - Question 6

The reason for the putting of VII A group is that the reaction of hydrogen with group 1 elements as the same as that of other halogens.

Chemistry: Topic-wise Test- 1 - Question 7

There is no S-S bond in

Detailed Solution for Chemistry: Topic-wise Test- 1 - Question 7


Chemistry: Topic-wise Test- 1 - Question 8

A : tetracyanomethane                           B : Carbondioxide

C : Benzene                                           D : 1, 3-buta-di-ene

Ratio of σ and π bond is in order:

Detailed Solution for Chemistry: Topic-wise Test- 1 - Question 8

(A) Tetra cyanomethane


Chemistry: Topic-wise Test- 1 - Question 9

Which of the following models best describes the bonding within a layer of the graphite structure ?

Detailed Solution for Chemistry: Topic-wise Test- 1 - Question 9

Chemistry: Topic-wise Test- 1 - Question 10

In  , the shape is square planer. The number of bond pair-lone pair repulsion at 90° are :

Detailed Solution for Chemistry: Topic-wise Test- 1 - Question 10


⇒ No of bond pair-lone pair repulsion = 8

Chemistry: Topic-wise Test- 1 - Question 11

The critical temperature of water is higher than that of O2 because the H2O molecules has :

Detailed Solution for Chemistry: Topic-wise Test- 1 - Question 11

⇒ H2O is polar molecule
⇒ Hence  H2O has higher critical temp

Chemistry: Topic-wise Test- 1 - Question 12

Among these canonical structures, the correct order of stability is

Chemistry: Topic-wise Test- 1 - Question 13

Amongt these canonical structures which one is least stable ?

Chemistry: Topic-wise Test- 1 - Question 14

CH2 = CH – CH = CH – CH3 is more stable than CH3 – CH = C = CH – CH3 because

Chemistry: Topic-wise Test- 1 - Question 15

For phenol which ofthe following resonating structure is the most stable ?

Chemistry: Topic-wise Test- 1 - Question 16

Among these three canonical structures (through more are possible) what would be their relative contribution in the hybrid

Chemistry: Topic-wise Test- 1 - Question 17

The most stable resonating structure of following compound is

Chemistry: Topic-wise Test- 1 - Question 18

Which of the following is not a possible termination step in the free radical chlorination of methane?

Detailed Solution for Chemistry: Topic-wise Test- 1 - Question 18

Termination is the last step. So there shouldn't be any free radical atom remaining. In first option there is Cl• remaining it can't be termination step.The steps in free radical halogenation are as

Chemistry: Topic-wise Test- 1 - Question 19

The major monobromination product which results when ethyl cyclohexane is subjected to free radical bromination, is

Detailed Solution for Chemistry: Topic-wise Test- 1 - Question 19


Free radical bromination reaction is highly selective, occurs mainly at the carbon where most stable free radical is formed.
We know that the stability of free radical is in the order,
Tertiary radical > Secondary radical > Primary radical
In (a), (b) and (c), the bromination occurs at secondary carbon whereas in (d) the bromination occurs at tertiary carbon. Since, tertiary radicals are more stable than secondary radical the major product of monobromination of ethyl cyclohexane is (d).
The stability of tertiary radical is due to the higher number of α−Hygrogens which give more hyperconjugation effect than secondary.

Chemistry: Topic-wise Test- 1 - Question 20

Which set of reagent(s) in correct order would accomplish the following transformation?

Chemistry: Topic-wise Test- 1 - Question 21

The major product of the following reaction is

Chemistry: Topic-wise Test- 1 - Question 22

Direction (Q. Nos. 1 - 7) This section contains 7 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONLY ONE option is correct.

Q. What is true about the reaction given below?

Chemistry: Topic-wise Test- 1 - Question 23

What is major product in the following reaction?

Chemistry: Topic-wise Test- 1 - Question 24

Direction (Q. Nos. 12 and13) This section contains a paragraph, describing theory, experiments, data, etc. Two questions related to the paragraph have been given. Each question has only one correct answer among the four given options (a), (b), (c) and (d).

Passage

Caryophyllene (C15H24) contain a six membered ring and on ozonolysis gives following product.

Q. The structure of caryophyllene is

Chemistry: Topic-wise Test- 1 - Question 25

Caryophyllene (C15H24) contain a six membered ring and on ozonolysis gives following product.

Q. If caryophyllene is treated with 1.0 mole of HCI, a ring closure reaction takes place to form monochloride. What is the most likely product of this reaction?

Chemistry: Topic-wise Test- 1 - Question 26

Ethanol has a higher boiling point than dimethyl ether though they have the same molecular weight. This is due to :

Detailed Solution for Chemistry: Topic-wise Test- 1 - Question 26


⇒ due to intermolecular H-bond, it has higher b.p. than CH3OCH3

Chemistry: Topic-wise Test- 1 - Question 27

Arrange the following in order of decreasing boiling point :

(I) n-Butane (II) n-Butanol (III) n-Butyl chloride (IV) Isobutane

Detailed Solution for Chemistry: Topic-wise Test- 1 - Question 27

(I) H3C—CH2—CH2—CH3 n-butane




II > III >I > IV
As H-bond>d Interaction
> st. chain > Branch chain

Chemistry: Topic-wise Test- 1 - Question 28

Which of the following compounds would have significant intermolecular hydrogen bonding ?

HF, CH3OH, N2O4, CH4

Detailed Solution for Chemistry: Topic-wise Test- 1 - Question 28


⇒ due to intermolecular H-bond, it has higher b.p. than CH3OCH3

Chemistry: Topic-wise Test- 1 - Question 29

For H2O2, H2S, H2O and HF , the correct order of decreasing extent of hydrogen bonding is :

Detailed Solution for Chemistry: Topic-wise Test- 1 - Question 29

Chemistry: Topic-wise Test- 1 - Question 30

A simplified application of MO theory to the hypothetical `molecule' OF would give its bond order as

Detailed Solution for Chemistry: Topic-wise Test- 1 - Question 30

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