JEE Exam  >  JEE Tests  >  Mock Tests for JEE Main and Advanced 2025  >  JEE Main Mock Test - 14 - JEE MCQ

JEE Main Mock Test - 14 - JEE MCQ


Test Description

30 Questions MCQ Test Mock Tests for JEE Main and Advanced 2025 - JEE Main Mock Test - 14

JEE Main Mock Test - 14 for JEE 2025 is part of Mock Tests for JEE Main and Advanced 2025 preparation. The JEE Main Mock Test - 14 questions and answers have been prepared according to the JEE exam syllabus.The JEE Main Mock Test - 14 MCQs are made for JEE 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for JEE Main Mock Test - 14 below.
Solutions of JEE Main Mock Test - 14 questions in English are available as part of our Mock Tests for JEE Main and Advanced 2025 for JEE & JEE Main Mock Test - 14 solutions in Hindi for Mock Tests for JEE Main and Advanced 2025 course. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free. Attempt JEE Main Mock Test - 14 | 75 questions in 180 minutes | Mock test for JEE preparation | Free important questions MCQ to study Mock Tests for JEE Main and Advanced 2025 for JEE Exam | Download free PDF with solutions
JEE Main Mock Test - 14 - Question 1

The power factor of an ac circuit having resistance (R) and inductance (L) connected in series and an angular velocity ω is

Detailed Solution for JEE Main Mock Test - 14 - Question 1
Power factor = R/Z

For an LR circuit,

Hence, the power factor is

JEE Main Mock Test - 14 - Question 2

Two point charges, q and 4q are held a distance 'r' apart. The electric field due to them is zero at a distance

Detailed Solution for JEE Main Mock Test - 14 - Question 2
Let the electric field be zero at a distance x from charge 4q. Then

Or 2(r – x) = x

Or x = 2r/3, which is option (4).

JEE Main Mock Test - 14 - Question 3

What should be the angle of banking of the road if a vehicle, travelling with speed v, negotiates a curve of radius r?

Detailed Solution for JEE Main Mock Test - 14 - Question 3
On the banked road the component of the normal reaction N cos θ will balance the weight of the vehicle

N cos θ = mg …..1

N sin θ will provide the necessary centripetal force

JEE Main Mock Test - 14 - Question 4

Let there be a spherically symmetric charge distribution with charge density varying as up to r = R and ρ (r) = 0 for r > R, where r is the distance from the origin. The electric field at a distance r (r < r)="" from="" the="" origin="" is="" given="" />

Detailed Solution for JEE Main Mock Test - 14 - Question 4
Consider a thin spherical shell of radius x and thickness dx as shown in the figure.

Volume of the shell, dV = 4πx2dx

Let us draw a Gaussian surface of radius r (r < r)="" as="" shown="" in="" the="" figure="" />

Total charge enclosed inside the Gaussian surface,

According to Gauss's law,

JEE Main Mock Test - 14 - Question 5

Electromagnetic waves are transverse in nature, is evident by

Detailed Solution for JEE Main Mock Test - 14 - Question 5
Interference and diffraction explain the wave nature of light or EM waves. Polarisation is the phenomenon by which we restrict the vibration of wave in a particular direction perpendicular to direction of wave propagation. So, it explains the transverse nature of EM waves.
JEE Main Mock Test - 14 - Question 6

A car is moving on a straight road. If its engine is delivering constant power, then the distance covered by the car in time t is proportional to

Detailed Solution for JEE Main Mock Test - 14 - Question 6
Power is defined as the dot product of force and velocity.

As the car is moving in a straight line with constant power, the direction of the force and velocity will be same.

So, P = Fv and F = ma

So, P = mav

Acceleration of the car over the time interval 't' starting from rest is given by:

Let the displacement of the car over the time interval 't' be x.

Then,

Hence,

As the power is constant, we have

x2 ∝ t3

JEE Main Mock Test - 14 - Question 7

A light spring balance hangs from the hook of the other light spring balance and a block of mass M kg hangs from the former one. Then, the true statement about the scale reading is

Detailed Solution for JEE Main Mock Test - 14 - Question 7
Both the scales read M kg each.

For the block M,

T1 = Mg

For the scale S1,

T2 = T, = Mg

Hence, both scales will show the same reading.

JEE Main Mock Test - 14 - Question 8

Two particles starting from a point on a circle of radius 4 m in a horizontal plane move along the circle in opposite directions with constant speeds of 4 ms-1 and 6 ms-1. The particles will collide with each other in

Detailed Solution for JEE Main Mock Test - 14 - Question 8
As the particles are moving in opposite directions,

Relative speed of the particles = 6 + 4 = 10 ms-1

Distance covered = 2πR = 2 × 3.14 × 4

JEE Main Mock Test - 14 - Question 9

Which of the following represents the Boolean function for the given circuit of gates?

Detailed Solution for JEE Main Mock Test - 14 - Question 9

JEE Main Mock Test - 14 - Question 10

When a system is taken from state i to state f along the path iaf, it is found that Q = 50 cal and W = 20 cal. Along the path ibf, Q = 36 cal. W along the path ibf is

Detailed Solution for JEE Main Mock Test - 14 - Question 10

According to first law of thermodynamics, for the path iaf,

Qiaf = ΔUiaf + Wiaf

or, ΔUiaf = Qiaf - Wiaf

= 50 - 20 = 30 cal

For the path ibf,

Qibf = ΔUiaf + Wibf

Since ΔUiaf = ΔUibf, change in internal energy is path independent.

Qibf = ΔUiaf + Wiaf

∴ Wibf = Qibf - ΔUiaf = 36 - 30 = 6 cal

JEE Main Mock Test - 14 - Question 11

If force F is related with distance x and time t as F = A√x + Bt2 , the dimensions of A/B is

Detailed Solution for JEE Main Mock Test - 14 - Question 11
All terms of an equation must have same dimensions

JEE Main Mock Test - 14 - Question 12

A bob is hanging over a pulley inside a car through a string. The second end of the string is in the hand of a person standing in the car. The car is moving with constant acceleration aa directed horizontally as shown in the figure. Another end of the string is pulled with constant acceleration a vertically. The tension in the string is equal to :

Detailed Solution for JEE Main Mock Test - 14 - Question 12

(Force diagram in the frame of the car)

Applying Newton's law perpendicular to the string

mg sinθ = ma cosθ

tanθ = a/g

Applying Newton's law along the string

JEE Main Mock Test - 14 - Question 13

A disc of mass M and radius R is rolling with angular speed ωω on a horizontal plane as shown. The magnitude of angular momentum of the disc about the origin O is

Detailed Solution for JEE Main Mock Test - 14 - Question 13
From the theorem

Angular momentum about O = Angular momentum about CM + Angular momentum of CM about origin

L0 = Iω + MRv

JEE Main Mock Test - 14 - Question 14

The magnitude of the maximum acceleration is π times that of the maximum velocity of a simple harmonic oscillator. The time period of the oscillator in seconds is

Detailed Solution for JEE Main Mock Test - 14 - Question 14
Maximum acceleration = Maximum velocity × π

I.e., ω2A = πωA

where A is amplitude and ω is angular velocity.

⇒ ω = π

⇒ 2π/T = π

⇒ T = 2 s

JEE Main Mock Test - 14 - Question 15

An object of specific gravity ρ is hung from a thin steel wire. The fundamental frequency for transverse standing waves in the wire is 300 Hz. The object is immersed in water, so that one half of its volume is submerged. The new fundamental frequency (in Hz) is

Detailed Solution for JEE Main Mock Test - 14 - Question 15
The diagrammatic representation of the given problem is shown in figure. The expression of fundamental frequency is

In air , T = mg = Vρg

When the object is half immersed in water

The new fundamental frequency

JEE Main Mock Test - 14 - Question 16

One mole of ideal gas goes through process then change in temperature of the gas when volume changes from V = 1 m3 to 2 m3 is:

Detailed Solution for JEE Main Mock Test - 14 - Question 16

JEE Main Mock Test - 14 - Question 17

A very long straight wire carries a current I. At the instant when a charge +Q at point P has velocity , as shown, the force on the charge is

Detailed Solution for JEE Main Mock Test - 14 - Question 17
The direction of

∴ The magnetic force

is along OY.

JEE Main Mock Test - 14 - Question 18

The ratio of the volume occupied by an atom to the volume of the nucleus is

Detailed Solution for JEE Main Mock Test - 14 - Question 18
The radius of an atom = rA ≈ 10−10 m

The radius of the nucleus = rN ≈ 10−15 m

So, the ratio of their volumes is

⇒ VA : VN = 1015 : 1

JEE Main Mock Test - 14 - Question 19

Energy from the sun falls on the earth at a rate of 1353 W/m2, which is known as solar constant, i.e., the power incident per unit area per second at the top of atmosphere. Find the r.m.s values of the electric and magnetic fields in the sunlight reaching the top of the atmosphere.

Detailed Solution for JEE Main Mock Test - 14 - Question 19
For an electromagnetic wave of sinusoidal form

Energy flux is given by

The mean value of energy flux is intensity

[The mean value of cos2θ over on cycle is 1/2]

Hence

JEE Main Mock Test - 14 - Question 20

The effect on the interference fringes if the monochromatic source is replaced by a source of white light would be:

Detailed Solution for JEE Main Mock Test - 14 - Question 20
The interference patterns due to different component colours of white light overlap (incoherently). The central bright fringes for different colours are at same position. Therefore, the central fringe is white.

For a point P for which:

S2P - S1P = λb/2

λb ≈ 4000 Å represents the wavelength of blue colour, the blue colour will be absent and the fringe will appear red in colour. Slightly farther away where,

S2Q - S1Q = λb = λr/2

Where λr ≈ 8000 Å represents the wavelength of red colour, the fringe will be predominantly blue.

*Answer can only contain numeric values
JEE Main Mock Test - 14 - Question 21

A Carnot engine takes 3 × 106 cal of heat from a reservoir at 627°C and gives it to a sink at 27°C. The work done by the engine is W × 106 J. State the value of W. (Nearest integer)


Detailed Solution for JEE Main Mock Test - 14 - Question 21

Heat energy = 3 × 106 cal = 3 × 106 × 4.2 J

∴ Work done by engine = (Heat energy) × (Efficiency)

= (3 × 106 × 4.2) × 2/3 J

= 8.4 × 106 J

≈ 8 × 106 J

*Answer can only contain numeric values
JEE Main Mock Test - 14 - Question 22

In a series resonant LCR circuit, the voltage across R is 100 volts and R = 1 k Ω with C = 2 μF. The resonant frequency is 200 rad/s. At resonance, the voltage across L, in Volt, is


Detailed Solution for JEE Main Mock Test - 14 - Question 22
At resonance, impedance is purely resistive.

Z = R

Hence, I = V/R

Secondly, at resonance, voltage across inductor = Voltage across capacitor

VL = VC

*Answer can only contain numeric values
JEE Main Mock Test - 14 - Question 23

A boy weighing 50 kg eats bananas.The energy content of banana is 1000 cal. If this energy is used to lift the boy from ground, then find the height (in cm) through which he is lifted. Take g = 10 m s−2 mechanical equivalent of heat = 4.2 J cal−1


Detailed Solution for JEE Main Mock Test - 14 - Question 23
Energy used by boy is

E = 1000 × 4.2 J = mgh = 50 × 10 × h

h = 8.4 m

*Answer can only contain numeric values
JEE Main Mock Test - 14 - Question 24

The magnification produced by the objective lens and the eye lens of a compound microscope are 25 and 6 respectively. The magnification of this microscope is 50n, then find nn.


Detailed Solution for JEE Main Mock Test - 14 - Question 24

Magnification of combination of two or more lens is given by product of magnification produced by all.

Given M0 = 25 Me, = 6

∴ magnification of this microscope is

M = M0 × Me = 25 × 6 = 150 = 50 × 3 ⇒ n = 3

*Answer can only contain numeric values
JEE Main Mock Test - 14 - Question 25

A simple pendulum has a time period T1 when on the earth’s surface, and T2 when taken to a height R above the earth’s surface, where R is the radius of the earth. The value of T2/T1 is


Detailed Solution for JEE Main Mock Test - 14 - Question 25

JEE Main Mock Test - 14 - Question 26

The radioactive isotope which is used in the treatment of cancer, can be made by (n, p) reaction. What is the target nucleus for this reaction?

Detailed Solution for JEE Main Mock Test - 14 - Question 26

Hence, the target nucleus is

JEE Main Mock Test - 14 - Question 27

The bond lengths and bond angles in the molecules of methane, ammonia and water are given below:

This variation in bond angle is a result of

(i) the increasing repulsion between hydrogen atoms as the bond length decreases

(ii) the number of non-bonding electron pairs in the molecule

(iii) a non-bonding electron pair having a greater repulsive force than a bonding electron pair

Detailed Solution for JEE Main Mock Test - 14 - Question 27
In methane, ammonia and water, the central atom is sp3 hybridised and expected bond angle is 109.5°.

However, the bond angle changes due to the presence of lone pairs of electrons.

This is because: lone pair-lone pair repulsions > lone pair-bond pair repulsions > bond pair-bond pair repulsions.

Methane (no lone pair) has a regular tetrahedral geometry with bond angle of 109.5°.

Ammonia (one lone pair) has a pyramidal geometry with bond angle of 107°.

Water (two lone pairs) has an angular bent geometry with bond angle of 104.5°.

JEE Main Mock Test - 14 - Question 28

For a first order reaction A P, the temperature (T) dependent rate constant (k) was found to follow the equation log

The pre-exponential factor A and the activation energy Ea respectively are

Detailed Solution for JEE Main Mock Test - 14 - Question 28
According to Arrhenius equation,

Comparing equations (i) and (ii),

log A = 6 ⇒ A = 1 × 106 s-1

Ea = 2000 × 2.303 × 8.314

⇒ Ea = 38294 J/mol or Ea ≈ 38.3 kJ mol-1

JEE Main Mock Test - 14 - Question 29

Directions: The following question has four choices, out of which ONLY ONE is correct.

Wavelengths of X-ray lines of Mg and Cr are 0.987 nm and 0.229 nm, respectively. The values of the constants 'a' and 'b' for this series should respectively be

Detailed Solution for JEE Main Mock Test - 14 - Question 29

Now, when b = 0.785

= a(12 - 0.785)

a = 4.9 × 107

So, this option is the correct answer.

JEE Main Mock Test - 14 - Question 30

Identify the incorrect statement.

Detailed Solution for JEE Main Mock Test - 14 - Question 30
Cl2 reacts with excess of NH3 to give N2 and ammonium chloride. The chemical reactions involved in this process are as follows.

Hence, the reaction described in the option (1) is incorrect.

View more questions
356 docs|142 tests
Information about JEE Main Mock Test - 14 Page
In this test you can find the Exam questions for JEE Main Mock Test - 14 solved & explained in the simplest way possible. Besides giving Questions and answers for JEE Main Mock Test - 14, EduRev gives you an ample number of Online tests for practice
Download as PDF