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Class 10 Exam  >  Class 10 Tests  >  Case Based Questions Test: Carbon & Its compounds - 2 - Class 10 MCQ

Case Based Questions Test: Carbon & Its compounds - 2 - Class 10 MCQ


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15 Questions MCQ Test - Case Based Questions Test: Carbon & Its compounds - 2

Case Based Questions Test: Carbon & Its compounds - 2 for Class 10 2024 is part of Class 10 preparation. The Case Based Questions Test: Carbon & Its compounds - 2 questions and answers have been prepared according to the Class 10 exam syllabus.The Case Based Questions Test: Carbon & Its compounds - 2 MCQs are made for Class 10 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Case Based Questions Test: Carbon & Its compounds - 2 below.
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Case Based Questions Test: Carbon & Its compounds - 2 - Question 1
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Read the passage and answer the question :

A homologous series is a series of organic compounds which belong to the same family (i.e. possess the same functional group) and show similar chemical properties. The members of this series are called homologous and differ from each other by the number of CH2 units in the main carbon chain.

Q. The chemical properties of which of the following compounds is similar to butane ?

Detailed Solution for Case Based Questions Test: Carbon & Its compounds - 2 - Question 1
Pentane is an organic compound which is a clear colourless liquid. The odour of pentane is similar to petroleum. It is less dense than the water and is insoluble in water.

n-butane(C4H10) is an alkane satisfying the formula CnH2n+2.

Case Based Questions Test: Carbon & Its compounds - 2 - Question 2
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A homologous series is a series of organic compounds which belong to the same family (i.e. possess the same functional group) and show similar chemical properties. The members of this series are called homologous and differ from each other by the number of CH2 units in the main carbon chain.

Q. Which of the following is not the property of a homologous series ?

Detailed Solution for Case Based Questions Test: Carbon & Its compounds - 2 - Question 2
Four characteristics of a homologous series are

(i) The general formula of all compounds in the series is the same.

(ii) They have the same functional group.

(iii) Their physical properties such as melting point, boiling point, density, generally show a gradual change with increase of molecular formula in the series.

(iv) Their chemical properties show close similarities due to the pressure of the same functional group in them.

(v) Consecutive members of the series differ from each other by the -CH2- group which is known as the methylene group and their molecular weight differs by 14 units.

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Case Based Questions Test: Carbon & Its compounds - 2 - Question 3
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Read the passage and answer the question :

A homologous series is a series of organic compounds which belong to the same family (i.e. possess the same functional group) and show similar chemical properties. The members of this series are called homologous and differ from each other by the number of CH2 units in the main carbon chain.

Q. What is the difference between two consecutive members in a homologous series in alkanes in terms of molecular mass and number of atoms of elements is:

Detailed Solution for Case Based Questions Test: Carbon & Its compounds - 2 - Question 3
In homologous series the two consecutive members will differ by 14u or CH2 units

In case of alkanes (General Formula : CnH2n+2)

Example methane and ethane.

CH4 , C2H6, C3H8

Molecules masses are 16, 30, 44

Consecutive ones differ by 14.

And each differs by -CH2 units.

Case Based Questions Test: Carbon & Its compounds - 2 - Question 4
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Read the passage and answer the question :

A homologous series is a series of organic compounds which belong to the same family (i.e. possess the same functional group) and show similar chemical properties. The members of this series are called homologous and differ from each other by the number of CH2 units in the main carbon chain.

Q. Which of the following represent the name and formula of the 2nd member of homologous series having the general formula CnH2n + 2 ?
Detailed Solution for Case Based Questions Test: Carbon & Its compounds - 2 - Question 4
The second member of this homologous series is Ethane, C2H6

​

Case Based Questions Test: Carbon & Its compounds - 2 - Question 5
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Read the passage and answer the question :

A homologous series is a series of organic compounds which belong to the same family (i.e. possess the same functional group) and show similar chemical properties. The members of this series are called homologous and differ from each other by the number of CH2 units in the main carbon chain.

Q. The compound CH3 CH (OH) CH3 belongs to which of the following homologous series ?
Detailed Solution for Case Based Questions Test: Carbon & Its compounds - 2 - Question 5

Answer:


Homologous Series:



  • A homologous series is a series of organic compounds that have the same functional group and show similar chemical properties.

  • The members of a homologous series are called homologous and differ from each other by the number of CH2 units in the main carbon chain.


Identification of Compound:



  • The compound CH3 CH (OH) CH3 belongs to a homologous series.

  • We need to determine which homologous series it belongs to.

  • The compound contains the functional group -OH, which is the characteristic functional group of alcohols.


Conclusion:



  • The compound CH3 CH (OH) CH3 belongs to the alcohol homologous series.


Answer: B

Case Based Questions Test: Carbon & Its compounds - 2 - Question 6
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Carbon has the unique property to form bonds with other atoms of carbon. Answer the question :

Name the characteristic property of carbon as depicted in the fig. A
Detailed Solution for Case Based Questions Test: Carbon & Its compounds - 2 - Question 6
(i) Property of carbon atom to multiple bonds with other carbon atoms is called catenation.

(ii) Carbon is a tetravalent atom. It's 4 valence electrons can be shared by other atoms. Thus carbon atoms form bonds with each other giving rise to catenation.

Case Based Questions Test: Carbon & Its compounds - 2 - Question 7
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Carbon has the unique property to form bonds with other atoms of carbon. Answer the question :

Give the number of single bonds present in the Cyclohexane compound.
Detailed Solution for Case Based Questions Test: Carbon & Its compounds - 2 - Question 7

Cyclohexane is a saturated cyclic hydrocarbon which has 18 single bonds present in it.

Case Based Questions Test: Carbon & Its compounds - 2 - Question 8
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Carbon has the unique property to form bonds with other atoms of carbon. Answer the question :

Q. Carbon forms large number of compounds due to :
Detailed Solution for Case Based Questions Test: Carbon & Its compounds - 2 - Question 8

Catenation: The unique property of the 'C' element to be able to form continuous links with other 'C' atoms through covalency called catenation, is one reason for the existence of a large number of organic compounds.

Tetravalency: The carbon atom's four valence electrons can be shared by other atoms that have electrons to share, thus forming covalent (shared-electron) bonds. They can even be shared by other carbon atoms, which in turn can share electrons with other carbon atoms and so on, forming long strings of carbon atoms, bonded to each other like links in a chain.

Case Based Questions Test: Carbon & Its compounds - 2 - Question 9
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Carbon has the unique property to form bonds with other atoms of carbon. Answer the question :

Carbon is :
Case Based Questions Test: Carbon & Its compounds - 2 - Question 10
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Carbon has the unique property to form bonds with other atoms of carbon. Answer the question :

Q. Write the name and structure of a saturated compound in which 6 carbon atoms are arranged in a ring.
Case Based Questions Test: Carbon & Its compounds - 2 - Question 11
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An organic compound A of molecular formula C2H4 on reduction gives another compound B of molecular formula C2H6. B on reaction with chlorine in the presence of sunlight gives C of molecular formula C2H5Cl.

Q. Name the compounds A, B and C.
Detailed Solution for Case Based Questions Test: Carbon & Its compounds - 2 - Question 11
A: CH2 = CH2 Ethene B : CH3 = CH3 Ethane C : CH3 – CH2 – Cl Chloroethane
Case Based Questions Test: Carbon & Its compounds - 2 - Question 12
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Read the passage and answer the questions :

An organic compound A of molecular formula C2H4 on reduction gives another compound B of molecular formula C2H6. B on reaction with chlorine in the presence of sunlight gives C of molecular formula C2H5Cl.

Q. The general formula for alkene is :
Detailed Solution for Case Based Questions Test: Carbon & Its compounds - 2 - Question 12

The given passage provides information about the organic compound A and its reactions to form compounds B and C. From the given information, we can deduce the general formula for alkene.
Key points:
- Compound A has a molecular formula of C2H4.
- On reduction, compound A forms compound B with a molecular formula of C2H6.
- Compound B reacts with chlorine in the presence of sunlight to form compound C with a molecular formula of C2H5Cl.
Analysis:
- The reduction of compound A to form compound B suggests the addition of hydrogen atoms to compound A.
- The reaction of compound B with chlorine in the presence of sunlight suggests the substitution of a hydrogen atom with a chlorine atom.
Answer:
The general formula for alkene is CnH2n. In this case, the compound A has a molecular formula of C2H4, which corresponds to an alkene.
Case Based Questions Test: Carbon & Its compounds - 2 - Question 13
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Read the passage and answer the questions :

An organic compound A of molecular formula C2H4 on reduction gives another compound B of molecular formula C2H6. B on reaction with chlorine in the presence of sunlight gives C of molecular formula C2H5Cl.

Q. Name the type of reaction.
Detailed Solution for Case Based Questions Test: Carbon & Its compounds - 2 - Question 13

Type of reaction: Addition
Explanation:
The given passage describes a series of reactions that lead to the formation of compound C with a molecular formula C2H5Cl. Let's analyze each step of the reaction sequence:
1. Compound A (C2H4) is subjected to reduction, resulting in the formation of compound B (C2H6). This reduction reaction involves the addition of hydrogen (H2) to compound A, leading to the increase in the number of hydrogen atoms in the final product.
2. Compound B (C2H6) reacts with chlorine (Cl2) in the presence of sunlight, resulting in the formation of compound C (C2H5Cl). This reaction is known as halogenation, where a halogen atom (Cl) replaces one or more hydrogen atoms in the starting compound.
Based on the reactions described, it can be concluded that the overall reaction is an addition reaction and not substitution or halogenation. Therefore, the correct answer is option C: Addition.
Case Based Questions Test: Carbon & Its compounds - 2 - Question 14
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Read the passage and answer the questions :

An organic compound A of molecular formula C2H4 on reduction gives another compound B of molecular formula C2H6. B on reaction with chlorine in the presence of sunlight gives C of molecular formula C2H5Cl.

Q. Choose the correct condition for conversion of ethene to ethane:
Detailed Solution for Case Based Questions Test: Carbon & Its compounds - 2 - Question 14
Hydrogenation in presence of catalyst like nickel or Palladium.
Case Based Questions Test: Carbon & Its compounds - 2 - Question 15
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Read the passage and answer the questions :

An organic compound A of molecular formula C2H4 on reduction gives another compound B of molecular formula C2H6. B on reaction with chlorine in the presence of sunlight gives C of molecular formula C2H5Cl.

Q. Essential conditions required for the addition reaction to occur :
Detailed Solution for Case Based Questions Test: Carbon & Its compounds - 2 - Question 15
Multiple bonds (double and triple bonds) must be present between carbon atoms in the chain of hydrocarbons.
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