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GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) - Electrical Engineering (EE) MCQ


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30 Questions MCQ Test - GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23)

GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) MCQs are made for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) below.
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GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) - Question 1

Coffee stains made the note ________.

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) - Question 1
The correct spelling is 'illegible', which means 'not clear enough to be read'.
GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) - Question 2

Choose the statement where bold word is used correctly.

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) - Question 2
Banal’ means boring because it contains nothing new and lacks originality.
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GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) - Question 3

Which one of the following is the antonym of the word FEARLESS?

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) - Question 3
'Craven' means 'contemptibly lacking in courage, i.e. cowardly', which is antonymous to 'fearless'.
GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) - Question 4

A man covers a certain distance on a toy train. If the train moved 4 km/hr faster, it would take 30 minute less and if it moved 2 km/hr slower, it would have taken 20 minutes more, then the distance (in km) is _________.


Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) - Question 4
Let the original speed be s km/hr and original time taken be ‘t’ hr. and original distance covered ‘d’ km

St = d

From given data we have,

From equation (i) and (ii),

T = 3 hours, and s = 20km/h and d = 60 km

Hence, the distance covered is 60 km.

GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) - Question 5

A boat goes 48 km upstream in 6 hours and 44 km downstream in 4 hours. Find the speed of the boat in still water.

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) - Question 5
Speed upstream, U = 48 ÷ 6 = 8 km/h

Speed downstream, D = 44 ÷ 4 = 11 km/h

Speed of the boat in still water = 9.5 km/h

GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) - Question 6

Direction: Study the following table carefully and answer the questions given below it.

Fare in rupees for three different types of vehicles

Note: Fare per km for intermittent distance is the same.

Mr. X wants to travel a distance of 9 kms by Type A vehicle. How much more money will be required to be spent if he decides to travel by Type B vehicle instead of Type A ________.


Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) - Question 6
Total travelling distance= 9km = 7 km fixed + 2 km intermittent distance

For Type A vehicle:

Fare up to 10 km, spending = Rs. 17.25.

Fare up to 7 km, spending = Rs. 13.50.

Intermittent distance between these are km = (10-7)= 3 km

Money spending for this intermittent distance = Rs. (17.25 – 13.50) = Rs. 3.75

For 3 km intermitted distance cost is 3.75 rupees

For 1 km intermitted distance cost = Rs. 3.75/3 = 1.25 rupees

For Type B vehicle:

Fare up to 10 km, spending = Rs. 33.25.

Fare up to 7 km, spending = Rs. 24.25.

Intermittent distance between these are = (10 – 7) km = 3 km

Money spending for this intermittent distance = Rs. (33.25 – 24.25) = Rs. 9.00

For 3 km intermittent distance cost is 9 rupees

For 1 km intermittent distance cost = Rs. 9/3 = 3 rupees

Travelling by Type A train:

Spending = Cost for 7 km fixed + cost for 2 km intermittent distance

Travelling by Type B train :

Spending = Cost for 7 km fixed + cost for 2 km intermittent distance

Excess cost for travelling in Type B vehicles instead of Type A vehicle will be

= Rs (30.25 – 16)= Rs. 14.25

GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) - Question 7

A contractor undertook a certain job to be completed in 55 days and employed 48 men to do it. In 11 days, only 1/6 of the work was completed. How many extra men should he employ in order to complete the work in the allotted time?

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) - Question 7
In 11 days, only 1/6 of the work was done. It is evident that the remaining 5/6 of the work will be finished within 55 days.

But, he wants to finish the remaining work in 55 - 11 = 44 days.

In 55 days, the remaining work can be finished by 48 men.

⇒ In 44 days, the work can be finished by 48 x(55/44)men = 60 men

So, he should employ (60 - 48) = 12 more men.

GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) - Question 8

Directions: In the question below are given three statements followed by two conclusion numbered I and II. You have to take the given statements to be true even if they seem to be at variance with commonly known facts. Read all the conclusions and then decide which of the given conclusions logically follows from the given statements, disregarding commonly known facts.

Statements :

All lizards are birds

Some ants are birds

All ants are cobras

Conclusions :

I.All lizards being cobras is a possibility

II.Some cobras are birds.

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) - Question 8
Consider the least possible Venn diagram

Conclusions :

I : All lizards being cobras is a possibility → Possibility is true as shown below.

II : Some cobras are birds Clearly true, as shown above.

Hence, both the conclusions follow.

GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) - Question 9

A man starting at a point walks 1 km east, 2 km north, 1 km east, 1 km north, 1 km east and then 1 km north to arrive at a destination. What is the shortest distance (in km) from the starting point to the destination?

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) - Question 9
Let the man start from point O and reach his destination at point A.

The shortest distance between O and his destination is

GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) - Question 10

If first nine multiples of five are multiplied together, then the number of zeros at the end of the product are ________.


Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) - Question 10

So, first nine multiples of five will have 510 x 27 as factors and 510 x 27 will end with 7 zeros.

Hence, the number of zeros at the end of the product are 7.

GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) - Question 11

For the linear network shown below, V-I characteristic is also given in the figure. The value of Norton equivalent current and resistance are respectively

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) - Question 11
The circuit with Norton equivalent is,

From the given graph,

The equation of line,

I = 2V - 6 .. (ii)

On comparing equation (i) and (ii),

GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) - Question 12

A voltage commutation circuit is shown in figure. The turn-off time of the both SCR is 60 sec and current through R1 and R2 is 20 A and voltage is 120 V. What will be the minimum value of capacitor (in μF) required for proper commutation? (Answer up to one decimal place)


Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) - Question 12
GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) - Question 13

Consider the network shown in figure

The Thevenin’s equivalent resistance, across terminals a-b, is

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) - Question 13
Given circuit is shown below,

To find Thevenin’s resistance , deactivating independent source and applying a dummy voltage source of “V” volts and assuming current from it as “I ” amperes, then

KVL can be written as

GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) - Question 14

The type of single-phase induction motor having the highest power factor at full load is

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) - Question 14
1-phase induction motor is not self starting, so it is used to start with a different method at full load condition. Capacitor-run type motors have higher power factor. In this type, the capacitor is connected in running condition.
GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) - Question 15

Consider the closed loop control system shown in figure below, the closed loop poles of the system are located at and

Then the value of is _____. (Correct upto one decimal place)


Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) - Question 15
Given :

From block diagram, characteristic equation is given by,

Given closed loop poles are located at S = -1 and S =-5, therefore the characteristics equation is

GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) - Question 16

ACSR conductor implies

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) - Question 16
Aluminium conductor steel-reinforced cable (ACSR) is a type of high-capacity, high-stranded conductor usually used in overhead power lines. For its solid conductivity, light weight and low cost, the outer strands are high-purity aluminum.
GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) - Question 17

Consider the MUX circuit shown in figure below

The boolean function realized by above MUX is

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) - Question 17
MUX output

Using K map

GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) - Question 18

For an induction motor, operating at a slip s, the ratio of gross power output to air gap power is equal to

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) - Question 18
GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) - Question 19

The value of integral is _________(Correct upto nearest integer)


Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) - Question 19
Given :

Formula

,

(Doublet function)

Where,

GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) - Question 20

If x cos y + y cos x = π and initial value of x and y is equal to 0, then y' (0) =

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) - Question 20
x cosy + y cosx = π

Differentiating both side with respect to x

cosy + x (-siny) dy/dx + cosx dy/dx - y sinx = 0

dy/dx = (- y sinx+ cosy)/(cosx - x siny)

Putting here x= 0 and y = 0

dy/dx = (1)/1 = 1

GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) - Question 21

A single phase full bridge VSI has a source a voltage of 200 V d.c. The load consists of RLC in series where , and . Identify the fundamental component of the load current from the following

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) - Question 21

GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) - Question 22

On the torque/speed curve of an induction motor shown in the figure, four points of operation are marked as W, X, Y and Z. Which of them represents the operation at a slip greater than 1?

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) - Question 22
Given torque/speed curve of the induction motor

When the speed of the motor is in forward direction then slip varies from 0 to 1 but when speed of motor is in reverse direction or negative then slip is greater then 1.

So at point W slip is greater than 1.

GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) - Question 23

x and y are statistically independent. If x has uniform pdf in the interval [0, a] and y has uniform pdf in the interval [0, b]. then the expected value of product of x and y is

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) - Question 23
Given x and y are statistically independent

GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) - Question 24

For the system shown in figure, the rise time and settling time are respectively

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) - Question 24

GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) - Question 25

The current coil of a dynamometer wattmeter is connected to a 24V dc source in series with 6Ω resistor. The potential circuit is connected through an ideal half wave rectifier in series with 50Hz source of 100V. The inductance of pressure circuit and current coil resistance are negligible. The reading of wattmeter in watts is ______________. (Correct upto nearest integer)


Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) - Question 25

The pressure coil is energized by an ideal half wave rectifier therefore, the pressure coil carrier current during one half cycle and in the other half cycle there is no current in it. This means that there is a deflecting torque on the meter during one half cycle.

Reading of the wattmeter = Average power over a cycle

GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) - Question 26

Which characteristic of a d.c. shunt generator is represented by the graph shown below?

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) - Question 26

In the given graph, internal characteristic option is not correct because generated emf cannot be zero and open circuit and magnetic characteristics show the saturation.

GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) - Question 27

A 230 V, dc shunt motor runs at 800 rpm and takes armature current of 50 A. Assume flux proportional to field current. Armature resistance =0.15Ω and field winding resistance=250 Ω . The resistance to be added to the field circuit to increase speed to 1000 rpm at an armature current of 80 A is _____ Ω. (Correct upto nearest integer)


Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) - Question 27

Emf equation is given by,

Let, Rt = total resistance =(250+R), where R is the additional resistance

GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) - Question 28

A three phase generator is rated at 110 MVA, 11 kV is connected through circuit breakers to a transformer. The generator is having direct axis sub-transient reactance, X''d = 19%, transient reactance, X'd = 26% and synchronous reactance = 130%. The generator is operating at no load and rated voltage when a three phase short circuit fault occurs between the breakers and the transformer. The magnitude of initial symmetrical rms (in kA) current in the breakers will be (Answer up to two decimal places)


Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) - Question 28

GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) - Question 29

The real part of the complex number

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) - Question 29

Given

∴ Real part of will be Re (z) = In2

GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) - Question 30

For a 1.8°, 2-phase bipolar stepper motor, the stepping rate is 100 steps/second. The rotational speed of the motor (in rpm) is (Answer up to the nearest integer)


Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 4 (22-01-23) - Question 30

Given 1.8° angle, 2 - Bipolar stepper motor and stepping rate is 100 step/second

So, Step required for one revolution =360/1.8 = 200 steps

∵ Time required for one revolution = 2 seconds

rev/sec = 0.5 rps

and

rev/min = 30 rpm

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