Electronics and Communication Engineering (ECE) Exam  >  Electronics and Communication Engineering (ECE) Tests  >  GATE ECE (Electronics) Mock Test Series 2025  >  Test: Two Port Network - Electronics and Communication Engineering (ECE) MCQ

Test: Two Port Network - Electronics and Communication Engineering (ECE) MCQ


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15 Questions MCQ Test GATE ECE (Electronics) Mock Test Series 2025 - Test: Two Port Network

Test: Two Port Network for Electronics and Communication Engineering (ECE) 2024 is part of GATE ECE (Electronics) Mock Test Series 2025 preparation. The Test: Two Port Network questions and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus.The Test: Two Port Network MCQs are made for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Two Port Network below.
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Test: Two Port Network - Question 1

[T] = ?

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Detailed Solution for Test: Two Port Network - Question 1

Let I3 be the clockwise loop current in center loop
 V2 = 4(I2 + I3) ⇒ I3 = 0.25V2 - I2
⇒ I1 = 0.35V2 - I2  .........(i)
V1 = 4I1 - 0.2V1 + V2
1.2V1 = 4(0.35V2 - I2) + V2 = 2.4V2 - 4I2
⇒ V1 = 2V2 - 3.33I2 .........(ii)

Test: Two Port Network - Question 2

[H] = ?

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Detailed Solution for Test: Two Port Network - Question 2

 

 ..........(i)

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Test: Two Port Network - Question 3

[Y] = ?

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Detailed Solution for Test: Two Port Network - Question 3

I1 = (V1 - V2) Yab + V1Yab 

⇒ I1 = V1(Ya + Yab) - V2Yab .....(i)

I2 = (V2 - V1)Yab + V2Yb = -V1Yab + V2(Yb + Yab) .....(ii)

Test: Two Port Network - Question 4

The y-parameters of a 2-port network are 

A resistor of 1 ohm is connected across as shown in fig. The new y –parameter would be

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Detailed Solution for Test: Two Port Network - Question 4

y-parameter of 1Ω resistor network are

New y-parameter

Test: Two Port Network - Question 5

For the 2-port of fig. 

  

The value of vo/vs is 

Detailed Solution for Test: Two Port Network - Question 5


  V1 = 600I1 + 100I2 , V2 = 100I1 + 200I2
Vs = 60I1 + V1 = 660I1 + 100I2 , V2 = Vo = -300I2

Test: Two Port Network - Question 6

The T-parameters of a 2-port network are 

If such two 2-port network are cascaded, the z –parameter for the cascaded network is

Detailed Solution for Test: Two Port Network - Question 6

 ​

   .......(i)
 ........(ii)

Test: Two Port Network - Question 7

[y] = ?

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Detailed Solution for Test: Two Port Network - Question 7



Test: Two Port Network - Question 8

Which among the following is regarded as short circuit forward transfer admittance?

Test: Two Port Network - Question 9

h21 = ?

Detailed Solution for Test: Two Port Network - Question 9

Test: Two Port Network - Question 10

In the circuit shown in fig. P.1.10.34, when the voltage V1 is 10 V, the current I is 1 A. If the applied voltage at port-2 is 100 V, the short circuit current flowing through at port 1 will be

Detailed Solution for Test: Two Port Network - Question 10


Interchaning the port  

Test: Two Port Network - Question 11

For a 2-port symmetrical bilateral network, iftransmission parameters A = 3 and B = 1Ω , the value ofparameter C is

Detailed Solution for Test: Two Port Network - Question 11

For symmetrical network A = D = 3

For bilateral AD - BC = 1, 9 - C = 1,C = 8 S

Test: Two Port Network - Question 12

A network has 7 nodes and 5 independent loops. The number of branches in the network is

Test: Two Port Network - Question 13

The circuit shown in fig. is reciprocal if a is

Detailed Solution for Test: Two Port Network - Question 13

V1 = 0.5V1 + I1 + 2(I1 + I2) + aI1
⇒ V1 = (6 + 2a)I1 + 4I2 ......(i)
V2 = 2(I1 + I2) + aI1 ⇒ V2 = (2 + a)I1 + 2I2 ......(ii) 
For reciprocal network
z12 = z21, 4 = 2 + a ⇒ a = 2

Test: Two Port Network - Question 14

Zin = ?

Detailed Solution for Test: Two Port Network - Question 14

I1 = 4 x 103V1 -0.1 x 10-3V2
I2 = 50 X 10-3V1 + 10-3V2 ,V2 = -103I2

- 10-3V2 = 50 x 10-3V1 + 10-3V2, V2 = -25V

Test: Two Port Network - Question 15

v1 ,v2 = ?

Detailed Solution for Test: Two Port Network - Question 15

I1 = 10 x 10-3V1 -5 x 10-3V2

100 = 25I1 + V1 
100 - V1 = 0.25V1 - 0.25V2 ⇒ 800 = 10V1 - V2   ....(i)
I2 = 50 x 10-3V1 + 20 x 10-3V2, V2 = -100I2
V2 = -5V1 -V2 ⇒ 3V2 + 5V1 = 0  ....(ii)
From (i) and (ii) V1 = 68.6 V, V2 = -114.3 V.

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