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12 Min Test: Coding - Decoding - 2 - Bank Exams MCQ


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15 Questions MCQ Test Reasoning Aptitude for Competitive Examinations - 12 Min Test: Coding - Decoding - 2

12 Min Test: Coding - Decoding - 2 for Bank Exams 2025 is part of Reasoning Aptitude for Competitive Examinations preparation. The 12 Min Test: Coding - Decoding - 2 questions and answers have been prepared according to the Bank Exams exam syllabus.The 12 Min Test: Coding - Decoding - 2 MCQs are made for Bank Exams 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for 12 Min Test: Coding - Decoding - 2 below.
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12 Min Test: Coding - Decoding - 2 - Question 1

In a certain code language 'LIEUTENANT' is written as 1232212021411420,then how 'MANGO' can be written in that code language?

Detailed Solution for 12 Min Test: Coding - Decoding - 2 - Question 1

Code for Consonant is it's place value, and code for vowels are given below
A ⇒ 1,
E ⇒ 2,
I ⇒ 3,
O ⇒ 4,
U ⇒ 5

Therefor
M ⇒ 13,
A ⇒ 1,
N ⇒ 14,
G ⇒ 7,
O ⇒ 4

So the code for MANGO is 1311474

12 Min Test: Coding - Decoding - 2 - Question 2

In a certain code, 'CALANDER' is written as 'CLANAEDR'. How is 'CIRCULAR' written in that code?

Detailed Solution for 12 Min Test: Coding - Decoding - 2 - Question 2

For question it is clear that, the second and third letters, fourth and fifth letters, sixth and seventh letters of the word mutually interchange positions to form the code.
So
C ⇒ C
I ⇘ R
R ⇗ I
C ⇘ U
U ⇗ C
L ⇘ A
A ⇗ L
R ⇒ R
so the code for CIRCULAR is CRIUCALR

12 Min Test: Coding - Decoding - 2 - Question 3

In a certain code language, GRAPE is written as 27354 and FOUR is written as 1687 . How is GROUP written is that code ?

Detailed Solution for 12 Min Test: Coding - Decoding - 2 - Question 3

GRAPE = 2 7 3 5 4
FOUR = 1 6 8 7
So, G = 2, R = 7, A = 3, P = 5, E = 4,
F = 1, O = 6, U = 8,
R = 7
GROUP = 2 7 6 8 5

12 Min Test: Coding - Decoding - 2 - Question 4

If 1 + 4 = 9, 2 + 8 = 18, 3 + 6 = 15 then 7 + 8 = ?

Detailed Solution for 12 Min Test: Coding - Decoding - 2 - Question 4

The given logic is as follows,
Sum of the digits + second digit = Answer.
i.e., 1 +4 = 5 + 4 = 9
2 + 8 = 10 + 8 = 18
Similarly, 7 + 8 = 15 + 8 = 23.

12 Min Test: Coding - Decoding - 2 - Question 5

If A = 1, ACT = 24, then FAT = ?

Detailed Solution for 12 Min Test: Coding - Decoding - 2 - Question 5

Each letter represents its position in the alphabet (A=1, B=2, ..., Z=26). Here’s how the calculations for the words are done:

  • ACT:
    • A = 1
    • C = 3
    • T = 20

    Therefore, ACT = A + C + T = 1 + 3 + 20 = 24.

  • FAT:
    • F = 6
    • A = 1
    • T = 20

    Thus, FAT = F + A + T = 6 + 1 + 20 = 27.

12 Min Test: Coding - Decoding - 2 - Question 6

Using the following code and key decode the given coded word :

Code : L X P Z J Y Q M N B
key : b a e s p r h i g t
Coded word : ZBYXMNQB

Detailed Solution for 12 Min Test: Coding - Decoding - 2 - Question 6

To decode the word, each letter in the code is replaced by the corresponding letter from the key based on their positions.

  • Z (position 4) → s
  • B (position 10) → t
  • Y (position 6) → r
  • X (position 2) → a
  • M (position 8) → i
  • N (position 9) → g
  • Q (position 7) → h
  • B (position 10) → t

Combining these letters gives the word 'straight'.

The correct answer is option C: straight.

12 Min Test: Coding - Decoding - 2 - Question 7

In a certain code PATHOLOGIST is written as PIUBQKSRHFN. How is CONTROVERSY written in that code?

Detailed Solution for 12 Min Test: Coding - Decoding - 2 - Question 7

Five letters of the word PATHOLOGIST are reversed first and then coded as one place forward. Similarly, the last five letters of the word are reversed then coded as one place backward. Middle letter is coded as one place backward.
Hence, CONTROVERSY will be written as SUOPDNXRQDU.

12 Min Test: Coding - Decoding - 2 - Question 8

The following small letters are coded by capital letters in a certain way :
s u m l a d
R A P M S O

Now, which small letters can be decoded from the letters given below :
M A P S R O

Detailed Solution for 12 Min Test: Coding - Decoding - 2 - Question 8

According to given question,
R = s
A = u
P = m
M = l
S = a
O = d
Replace the each capital from given relationship for M A P S R O, We will get
M → l
A → u
P → m
S → a
R → s
O → d

12 Min Test: Coding - Decoding - 2 - Question 9

Unscramble the following letters to frame a meaningful word and find out the correct numerical sequence of the letters.
E → 1
S → 2
R → 3
T → 4
A → 5
R → 6
U → 7
N → 8
A → 9
T → 10

Detailed Solution for 12 Min Test: Coding - Decoding - 2 - Question 9

The below pattern is given in the question,
E → 1
S → 2
R → 3
T → 4
A → 5
R → 6
U → 7
N → 8
A → 9
T → 10
Try all option one by one and formed a word by arranging them.
After arranging the option (b), we get the meaningful word -
R → 3
E → 1
S → 2
T → 4
A → 5
U → 7
R → 6
A → 9
N → 8
T → 10
Hence , the required answer will be Restaurant.

12 Min Test: Coding - Decoding - 2 - Question 10

In a certin code the following numbers are coded in a certain way by assigning signs:
1 → %
2 → x
3 → -
4 → +
5 → >
6 → <
7 → ∧
8 → ∨
9 → $
Which number can be decoded from the following?
> $ x ∨ %

Detailed Solution for 12 Min Test: Coding - Decoding - 2 - Question 10

According to given question,
1 → % , 2 → x , 3 → - , 4 → + , 5 → > , 6 → < , 7 → ∧ , 8 → ∨ , 9 → $ ,
Replace the each capital from given relationship for > $ x ∨ % , We will get
5 → >
9 → $
2 → x
8 → ∨
1 → %
Hence , the required answer will be 59281.

12 Min Test: Coding - Decoding - 2 - Question 11

In a code language, the following alphabets are coded in a particular way:
A → @
C → #
D → $
E → %
M → ^
S → &
N → *
R → α
Q → β
V → γ
L → δ
Which word can be decoded from the following?
^ @ α γ % δ

Detailed Solution for 12 Min Test: Coding - Decoding - 2 - Question 11

According to given question,
A → @ , C → # , D → $ , E → % , M → ^ , S → & , N → * , R → α , Q → β , V → γ , L → δ
Replace the each capital from given relationship for ^ @ α γ % δ, We will get
^ → M
@ → A
α → R
β → V
% → E
δ → L
Hence , the required answer will be MARVEL.

12 Min Test: Coding - Decoding - 2 - Question 12

Direction: Given below are letters A to Z. Under each capital letter a small letter is written which is to used as a code for the capital letters.

Select the equivalent capital letters for the following:
hjwlcm

Detailed Solution for 12 Min Test: Coding - Decoding - 2 - Question 12

As per the given table in the question, After replacing the each capital from given relationship for hjwlcm, We will get
h → W
j → S
w → Q
l → D
c → V
m → H
Hence , the required answer will be WSQDVH.

12 Min Test: Coding - Decoding - 2 - Question 13

Direction: Below are given letter A to Z. Under each capital letter a small letter is written which is to be used as a code for the capital letter:
In each of the following questions, a group of six capital letters is given and its code equivalent is given in one of the columns (1), (2), (3) and (4). Study the group of letters given in each question and with the help of code given above, choose the code equivalent from among (1), (2), (3) and (4) as your answer.
(A) julsqr, mkzbxn , hijmub, vishwa, ocdkzq, zocbak
(B) lzcndo, mzkbxn, ucjlbo, mkzbxn, amwrnd, hmfxco
(C) cxtndo, cvafog, amwnrd, hilmbu, vithwa, ocqzkd
(D) vithaw, mzkbnx, odcazq, napkin, amwrny, hijump

ELBJSR

Detailed Solution for 12 Min Test: Coding - Decoding - 2 - Question 13

As per the above given table, We can replace the each capital from given relationship for ELBJSR , We will get
E → a
L → m
B → w
J → r
S → n
R → d
Hence , the required answer will be amwrnd.

12 Min Test: Coding - Decoding - 2 - Question 14

Direction: Below are given letter A to Z. Under each capital letter a small letter is written which is to be used as a code for the capital letter:
In each of the following questions, a group of six capital letters is given and its code equivalent is given in one of the columns (1), (2), (3) and (4). Study the group of letters given in each question and with the help of code given above, choose the code equivalent from among (1), (2), (3) and (4) as your answer.
(A) julsqr, mkzbxn , hijmub, vishwa, ocdkzq, zocbak
(B) lzcndo, mzkbxn, ucjlbo, mkzbxn, amwrnd, hmfxco
(C) cxtndo, cvafog, amwnrd, hilmbu, vithwa, ocqzkd
(D) vithaw, mzkbnx, odcazq, napkin, amwrny, hijump

XACGLY

Detailed Solution for 12 Min Test: Coding - Decoding - 2 - Question 14

As per the above given table, We can replace the each capital from given relationship for XACGLY , We will get
X → h
A → i
G → j
C → u
L → m
Y → p
Hence , the required answer will be hijump.

12 Min Test: Coding - Decoding - 2 - Question 15

Direction: Below are given letter A to Z. Under each capital letter a small letter is written which is to be used as a code for the capital letter:
In each of the following questions, a group of six capital letters is given and its code equivalent is given in one of the columns (1), (2), (3) and (4). Study the group of letters given in each question and with the help of code given above, choose the code equivalent from among (1), (2), (3) and (4) as your answer.
(A) julsqr, mkzbxn , hijmub, vishwa, ocdkzq, zocbak
(B) lzcndo, mzkbxn, ucjlbo, mkzbxn, amwrnd, hmfxco
(C) cxtndo, cvafog, amwnrd, hilmbu, vithwa, ocqzkd
(D) vithaw, mzkbnx, odcazq, napkin, amwrny, hijump

LKFZOS

Detailed Solution for 12 Min Test: Coding - Decoding - 2 - Question 15

As per the above given table, We can replace the each capital from given relationship for LKFZOS , We will get
L → m
K → z
F → k
Z → b
O → x
S → n
Hence , the required answer will be mzkbxn.

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