AIIMS CRE Electrical JE/AE Mock Test- 7 - NEET MCQ

Given, a + b + c = 1 Let observe the value of a, b, c

a = 1 / 3, b = 1 / 3, c = 1 / 3

a + b + c = 1

1 / 3 + 1 / 3 + 1 / 3 = 1

3 / 3 = 1

1 = 1

put the value of a, b, c (1 + a)(1 + b)(1 + c)

(1 + 1 / 3)(1 + 1 / 3)(1 + 1 / 3)

4 / 3 × 4 / 3 × 4 / 3

64 / 27 = 2.37

speed of B=60km/hr

In two hour A cover distance =2×40=80km relative speed of A and B=60−40=20km/hr the A and B meet at point M in hours =80/20=4 In 4 hours, B cover distance = 4 x 60 = 240km.

After interchanging signs, 12+8×25÷10−18

⇒12+8×25/10−18

⇒12+20−18

⇒ 14

So HCF of 1572 and 3799

So, 131 Is the number.

Voltage is a scalar quantity, although the complex representation of a sinusoidal voltage produces a complex scalar or phasor, which requires two real numbers for its representation, such as amplitude and phase angle.

All the given vary with change in temperature. Their mathematical relation with temperature is given as:
→ ηi² = A₀T³.e(^-EGO/kT)
→ μ= T^-m ; m=2.5 for electrons and 2.7 for holes
→ σ = σ₀ [1+α(T-T_o)]
→ E_G(T) = E_G0 - βT

One type of control system in which the output has no influence or effect on the control action of the input signal is called an Open-loop system.

V_th = 40V
For maximum power transfer from source to load , load impedance must be
Z_i=Z*_th
Z_L=10 - j20
P_max=V_th²/4R_th
P_max = 40²/4x10 =40W

For DC supply,

From equation (1) and (2)

On solving we will get finally,

Hence, the correct option is (B)

The Early effect, named after its discoverer James M. Early, is the variation in the effective width of the base in a bipolar junction transistor (BJT) due to a variation in the applied base-to-collector voltage.

Hence, the correct option is (C)

Hence, the correct option is (C)

Series reactors are high impedance electrical components that are used to limit current, mostly in cases of inductive motors or powerful floodlights. Series reactors and shunt reactors are commonly used in power systems. Series reactors are mainly used to limit the short-circuit current.

Hence, the correct option is (C)

Hence, the correct option is (D)

• Blown fuses

• Open-circuit in Auxiliary winding

• Open-circuit in the main winding

Hence, the correct option is (D)

The r.m.s. values of voltage and current phasors are:


Therefore, reactive power = 38.97 VAR, leading because reactive power is negative.

A 3.5 digit display is actually four segments, one half digit and 3 full digits. Displaying maximum capability it would read 1999. If we wanted to display 30kV on a 3.5 digit meter we would have to “throw out” the leading half digit as we can’t make use of it because it’s only a “1”. We are limited to using the three full digits, so the display would be 300. The decimal point is manually placed via a jumper, so the final display would be 30.0 and the “kV” term would be screened on the front panel overlay.
If we wanted to display 10kV on a 3.5 digit meter we can make use of the leading half digit. In this case we would have four digits of resolution with the meter displaying 1000. Placing the decimal point properly, the final meter reading would be 10.00 with the “kV” term screened on the front panel overlay.

The average value of the second term is zero. Therefore, answer is 6 V.

The parallel loads draw a total reactive power of 47 kVAR lagging. In order to raise the p.f. to unity, the capacitor should supply leading reactive power of 47 kVAR.

In an electrical installation an earthing system or grounding system connects specific parts of that installation with the Earth's conductive surface for safety and functional purposes. The choice of earthing system can affect the safety and electromagnetic compatibility of the installation. Earthing is used to protect you from an electric shock. It does this by providing a path (a protective conductor) for a fault current to flow to earth. It also causes the protective device (either a circuit-breaker or fuse) to switch off the electric current to the circuit that has the fault.