BITSAT Chemistry Test - 2 - JEE MCQ

→ Phenelzine contains hydrazine(2-phenylethylhydrazine)

→ Chloroxylenol contains phenol(4-Chloro-3,5-dimethylphenol)

→ Uracil is the pyrimidine base(2,4-Dihydroxypyrimidine)

→ Ranitidine contains furan ring

During exercise muscle need energy hence consume more oxygen and produce more CO₂ and lactic acid gets accumulated as well. According to bohr's effect oxygen binding affinity is inversely proportional to CO₂ concentration and acidity. Thus favours the dissociation​ or release of O₂.

Pressure increase solubility also increase in accordance with the Henry's law and option B is the closest to this. Hence B is correct.

H+  H⁺ + F^–
pK_w = pK_a + pKb
[For conjugate Acid-Base]
⇒ pK_a = 14 – 10.87 = 3.17
K_a = 6.76 × 10^–4

Concentration of solution =C=1M
Dissociation is α=0.01
After dissociation, the concentration of H⁺ ions will be Cα=1×0.01=10⁻²
pH=−log[H⁺]=−log(10⁻²) = +2

OF₂ Fluorine is most electronegative atom with oxidation number = - 1
x - 2 = 0
x = + 2
H₂O₂   2 + 2x = 0 ⇒ x = - 1 

• ClO₃^- : A very reactive inorganic anion.
• The term chlorate can also be used to describe any compound containing the chlorate ion, normally chlorate salts. 
• Example: Potassium chlorate, KClO₃

Based on Fajans' rule,
Smaller the size of cation, larger the size of anion, larger the charge,
d-f-Aelectrons present then larger the polarising power, larger the covalent nature and larger the lattice energy.

By Fajans’ rule,
Smaller the size of cation, larger the size of anion, larger the charge, then larger the polarising power, larger the covalent nature, means low melting point.
Smaller the ionic nature, means low melting point 


Hence, most stable is LiF.

At 100°C and 1 atmosphere pressure H₂O (l) ⇋ H₂O(g) is at equilibrium. For equilibrium

∆S_X→Z = ∆S_X→Y + ∆S_Y→Z(Entropy is a state function, so it is additive)
W_X→Y→Z = WX→Y (work done in _y→z is zero as the process is isochoric)

For O.S:

X + 0 + 2(-1) = 1

X = 3

Coordination number is the number of molecules linked to the central atom.

Hence B is the correct answer.

Structure (a) = structure (c) and, structure (b) = structure (d)

α-carbon is achiral, hence retention of configuration at β-carbon.

Both CH₃S^- and I^- are weak bases but strong nucleophiles.

All alcohols react (1°, 2° and 3°) with cerric nitrate and a colour change from yellow to red is observed.

c) It is 2-methyl-2-pentanol

Explanation:

• The reaction of the alcohol with cold, concentrated HCl resulting in immediate turbidity indicates the formation of a tert-butyl carbocation. This is a characteristic reaction for the alcohol with a tertiary alcohol, which reacts with HCl to form a carbocation that undergoes a nucleophilic substitution reaction.

• Additionally, the reaction of an ether with excess CH₃MgBr (Grignard reagent) followed by acid hydrolysis typically results in the formation of a tertiary alcohol if the ether is of the form R-O-R', where R' is a methyl group, indicating a tertiary alcohol.

Thus, 2-methyl-2-pentanol fits this description as it is a tertiary alcohol.

Diazonium salts react with phenols and naphthols to form azo dyes through a coupling reaction. This is a key process in organic chemistry for producing various coloured compounds.

• Diazonium salts: These are highly reactive compounds containing the diazonium group (R-N₂⁺).
• Coupling reaction: A reaction where a diazonium salt reacts with an aromatic compound, such as phenols or naphthols.
• Azo dyes: Coloured compounds formed as a result of the coupling reaction.

The major product formed is 3-nitropyridine due to the meta-directing nature of pyridine in electrophilic substitution reactions.

As mentioned in mechanism, reaction proceed via carbocation intermediate. Hence, alcohol forming most stable carbocation reacts most easily.

• In cyclopropanol (a and c), removal of OH⁻ leads to a carbocation on a highly strained 3-membered ring. Carbocations on such strained small rings are generally less stable because the ring strain is high, and the carbocation cannot delocalize effectively.

• In cyclopentenol (b and d), removal of OH⁻ generates a carbocation on a 5-membered ring. This ring is less strained, and the carbocation can be stabilized through hyperconjugation and potentially some resonance with the ring pi system if any double bonds are present (especially in compound b, which seems to have a double bond in the ring).

Structure b) shows a double bond in the ring (cyclopentene), so the carbocation formed can be resonance stabilized (allylic carbocation).

Conclusion:

Alcohol (b) formsthe most stable carbocation, hence most reactive.

ZnCI₂ is a Lewis acid, helps in the form ation of carbocation intermediate, hence catalyse the reaction.

Tetracycline is a bacteriostatic antibiotic. Bactericidal antibiotics are antibiotics which can kill bacteria and Bacteria-static are which can inhibit the growth of bacteria. Ofloxacin is bactericidal antibiotic. Ofloxacin is a fluoroquinolone carboxylic acid antibacterial showing bactericidal effects by inhibition of DNA gyrase.

Paracetamol is N-(4-hydroxyphenyl) ethanamide, which is a hydroxy group containing compound.

Phenacetin is N-(4-ethoxyphenyl) ethanamide, which is an amide and ethoxy group containing compound.

Aspirin is 2-acetoxybenzoic acid, which is an ester.

Antibiotics can be classified as bactericidal and bacteriostatic on the basis of the effect, it has on microbes. Bactericidal drugs have killing/destroying effect on microbes while, bacteriostatic have inhibiting effect on microbes. A few examples of the two types of antibiotics are as follows: Bactericidals are Penicillin, Aminoglycosides, Ofloxacin. Bacteriostatics are Erythromycin, Tetracycline, Chloramphenicol.

Chloramphenicol is a broad spectrum antibiotic. Norethindrone is an antifertility drug. Omeprazol is an antacid and Diphenhydramine is an antihistamine mainly used to treat allergies.

Tartrazine impart colour, it is artificial edible colour. It is used generally for yellow colour in food. It is stable compound because it contains 6 membered aromatic ring in which four atoms are nitrogen atoms, and it's chemical formula is C₂H₂N₄.

LSD and mescaline are psychedelic drugs.
These produce visual and auditory hallucinations.

Ranitidine is antacid; amoxicillin is an antibiotic while diphenhydramine is an antihistamine.
Antiseptics and disinfectants are also the chemicals which either kill or prevent the growth of microorganisms. Antiseptics are applied to the living tissues such as wounds, cuts, ulcers and diseased skin surfaces.  Hydrogen peroxide, iodoform and soframycin act as antiseptics.

A− Aspartame

B− Saccharine

C− Sucralose

D− Alitame

(i) A & D give positive test with ninhydrin because both have free carboxylic and amine groups.
(ii) C form precipitate with AgNO₃ in the Lassaigne extract of the sugar because it has chlorine atoms.
(iii) B & D give positive test with sodium nitroprusside because both have sulphur atoms