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BITSAT Chemistry Test - 2


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40 Questions MCQ Test BITSAT Mock Tests Series & Past Year Papers | BITSAT Chemistry Test - 2

BITSAT Chemistry Test - 2 for JEE 2022 is part of BITSAT Mock Tests Series & Past Year Papers preparation. The BITSAT Chemistry Test - 2 questions and answers have been prepared according to the JEE exam syllabus.The BITSAT Chemistry Test - 2 MCQs are made for JEE 2022 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for BITSAT Chemistry Test - 2 below.
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BITSAT Chemistry Test - 2 - Question 1

A compound X with molecular formula C₃H₈O can be oxidized to a compound Y with the molecular formula C₃H₆O₂. X is most likely to be a

Detailed Solution for BITSAT Chemistry Test - 2 - Question 1


Since, on oxidation, same number of carbon atoms are obtained in, hence, X compound is a primary alcohol.

BITSAT Chemistry Test - 2 - Question 2

Which of the following reagents cannot be used to distinguish between hexanal and 2-hexanone?

BITSAT Chemistry Test - 2 - Question 3

Elimination of bromine from 2- bromobutane results in the formation of

Detailed Solution for BITSAT Chemistry Test - 2 - Question 3
Predominantly 2-butene will be formed on elimination of bromine from 2- bromobutane. This is due to Saytzeff's rule. 

Certain haloalkanes can undergo elimination in two different ways giving a mixture of two products. In such reactions, the preferred product is the more highly substituted alkene (i.e. the alkene having lesser number of hydrogens on the doubly bonded carbon atoms). This generalisation is known as Saytzeff’s rule.

BITSAT Chemistry Test - 2 - Question 4

Hund's rule states that

Detailed Solution for BITSAT Chemistry Test - 2 - Question 4
Hund's rule states that:
  1. Every orbital in a sublevel is singly occupied before any orbital is doubly occupied.
  2. All of the electrons in singly occupied orbitals have the same spin (to maximize total spin).
When assigning electrons to orbitals, an electron first seeks to fill all the orbitals with similar energy (also referred to as degenerate orbitals) before pairing with another electron in a half-filled orbital. Atoms at ground states tend to have as many unpaired electrons as possible. 
BITSAT Chemistry Test - 2 - Question 5

The volume of water to be added to 100 cm3 of 0.5N H2SO4 to get decinormal concentration is

Detailed Solution for BITSAT Chemistry Test - 2 - Question 5

BITSAT Chemistry Test - 2 - Question 6

'The atomic orbitals are progressively filled in the order of increasing energy'. This statement is known as

BITSAT Chemistry Test - 2 - Question 7

The order of decreasing stability of the carbanions (CH₃)₃C-(I) ; (CH₃)₂CH-(II) ; CH₃CH₂-(III) ; C₆H₅CH₂-(IV) is

BITSAT Chemistry Test - 2 - Question 8

The sugar that is characteristic of milk is

Detailed Solution for BITSAT Chemistry Test - 2 - Question 8 Milk contains several different carbohydrate including lactose, glucose, galactose, and other oligosaccharides. The lactose gives milk its sweet taste and contributes approximately 40% of whole cow's milk's calories. Lactose is a disaccharide composite of two simple sugars, glucose and galactose.
BITSAT Chemistry Test - 2 - Question 9

The most reactive nucleophile among the following is

Detailed Solution for BITSAT Chemistry Test - 2 - Question 9

Although due to +I effect of methyl groups, (CH3)2 CHO and (CH3)3 CO are stronger bases but due to steric hindrance both are weaker nucleophiles than CH3O
Further due to resonance, C6H5O

is the weakest nucleophile
CH3O is most reactive (stronger) nucleophile

BITSAT Chemistry Test - 2 - Question 10

RNA is different from DNA because RNA contains

Detailed Solution for BITSAT Chemistry Test - 2 - Question 10 In dna deoxyribose sugar is present and ATGC NITROGEN BASES While in rna ribose sugar is present nd AUGC NITROGEN bases
BITSAT Chemistry Test - 2 - Question 11

Which of the following cannot reduce Fehling solution?

Detailed Solution for BITSAT Chemistry Test - 2 - Question 11 CH3COOH (acetic acid) cannot reduce Fehling solution while HCOOH, HCHO and  CH3CHO reduce Fehling solution due to the presence of CHO group.
BITSAT Chemistry Test - 2 - Question 12

60 J of heat flows out from 600 g of water at 30oC into surroundings at 25oC.The net entropy change in universe is approximately

BITSAT Chemistry Test - 2 - Question 13

Just before attaining equilibrium by a reversible reaction, it is found that

Detailed Solution for BITSAT Chemistry Test - 2 - Question 13


 At the initial stage of the reaction, the forward reaction will be much faster. As the reaction progresses, the concentration of A and B will fall while those of C and D will rise, until gradually the inequality between the rates of the opposing reactions cancel out.

At this point, the state of chemical equilibrium have been attained - the reaction will proceed in either direction at exactly the same rate.

Once equilibrium condition has been attained, there is no change in the concentrations of the substances in the reaction mixture because then, products of each reaction (forward and backward) are being used up as fast as they are being formed simultaneously.

BITSAT Chemistry Test - 2 - Question 14

N2O is isoelectronic with CO2 and N 3 , which is the structure of N2O?

Detailed Solution for BITSAT Chemistry Test - 2 - Question 14

BITSAT Chemistry Test - 2 - Question 15

Alizarin belongs to the class of

Detailed Solution for BITSAT Chemistry Test - 2 - Question 15
A mordant is any substance which can be fixed to the fibre and which can be dyed later on mostly hydroxide or basic salts of chromium aluminium and iron are used as mordant. A dye which imparts different colours in the presence of different mordant is referred to as a mordant dye. For ex. alizarin is a mordant dye when mordanted with aluminium salt solution. It imparts rose red colour to fabric but the same fabric is dyed blue when it is mordanted with barium salt and it dyes violet is mordant with Ferric salt.

BITSAT Chemistry Test - 2 - Question 16

Mark the correct statement. In a reversible reaction

BITSAT Chemistry Test - 2 - Question 17

For the square planar complex [M(a) (b) (c) (d)] (where M = central metal and a,b,c and d are monodentate ligands), the number of possible geometrical isomers are

Detailed Solution for BITSAT Chemistry Test - 2 - Question 17 Fix 1 as among abcd say a and then take others trans to a ac ab ad only 3 possibility
BITSAT Chemistry Test - 2 - Question 18

Plants and living beings are the examples of

BITSAT Chemistry Test - 2 - Question 19

The lightest metal is

Detailed Solution for BITSAT Chemistry Test - 2 - Question 19

Lithium is lightest among all the metals with density 0.534 g/cm3.

BITSAT Chemistry Test - 2 - Question 20

Which of the following gas is evolved on heating ammonium dichromate?

BITSAT Chemistry Test - 2 - Question 21

Which of the following belongs to the actinide series?

BITSAT Chemistry Test - 2 - Question 22

For standard reduction potentials of three metals A, B and C are + 0.5 V, -3.0 V and -1.2 v respectively. The reducing powers of these metals are

Detailed Solution for BITSAT Chemistry Test - 2 - Question 22
More negative the standard potential, least the tendency of the cation to be reduced. The corresponding atom has larger tendency for oxidation and hence larger reducing power. Hence , Reducing powers of these metals are in order:  B > C > A.


BITSAT Chemistry Test - 2 - Question 23

If the solubility of PbCl₂ at 25oC is 6.3 x 10⁻3 mole/litre, its solubility product at that temperature is

BITSAT Chemistry Test - 2 - Question 24

Which of the following will not displace hydrogen?

Detailed Solution for BITSAT Chemistry Test - 2 - Question 24
A common chemical reaction is the displacement of hydrogen from water or acids. This reaction is a good illustration of the relative reactivity of metals and the use of the activity series. For example, 
• K. Ca. and Na displace hydrogen from cold water, steam (FI20), and acids. 
• Mg, Al, Zn, and Fe displace hydrogen from steam and acids. 
• Ni, Sn, and Pb displace hydrogen only from acids. 
• Cu, Ag, Hg. and Au do not displace hydrogen. 
BITSAT Chemistry Test - 2 - Question 25

When n-propyl iodide is heated with alcoholic KOH,one of the products is

BITSAT Chemistry Test - 2 - Question 26

In the reaction

BITSAT Chemistry Test - 2 - Question 27

Treatment of ammonia with excess of ethyl chloride with yield

Detailed Solution for BITSAT Chemistry Test - 2 - Question 27  
BITSAT Chemistry Test - 2 - Question 28

What are the products formed when ammonia reacts with excess chlorine?

Detailed Solution for BITSAT Chemistry Test - 2 - Question 28 This is the reaction that occurs when ammonia reacts with excess chlorine:
 NH3 +3Cl2 --> NCl3 +3HCl
BITSAT Chemistry Test - 2 - Question 29

The dihedral angle HCH in staggered conformation of C₂H₆ is

BITSAT Chemistry Test - 2 - Question 30

Which of the following types of forces bind together the carbon atoms in diamond?

BITSAT Chemistry Test - 2 - Question 31

Amongst elements of Group 15, the property which increases down the Group is

Detailed Solution for BITSAT Chemistry Test - 2 - Question 31
As we go down the group, the bond energy of hydrides reduces (due to increasing atomic size as we go down the group). So they can be more easily broken to release nascent hydrogen (Nascent hydrogen is referred to the hydrogen which has just evolved post some reaction, and has not yet formed its molecule. This is not the same as hydrogen) , which is the cause of reducing nature. So reducing ability increases down the group in gaseous state.

BITSAT Chemistry Test - 2 - Question 32

Borax is not used

BITSAT Chemistry Test - 2 - Question 33

Of the following which is a step growth polymer

BITSAT Chemistry Test - 2 - Question 34

BCl₃ is planar molecule because in this molecule boron is

BITSAT Chemistry Test - 2 - Question 35

A burning strip of magnesium is introduced into a jar containing a gas. After some time the walls of the container is coated with carbon. The gas in the container is

Detailed Solution for BITSAT Chemistry Test - 2 - Question 35 When magnesium get burnt it form magnesium oxide .When that magnesium ocide reacts with CO2 the reaction takes place and we find white precipitate in the container of MG2O3 and carbon fix on the wall.of container
BITSAT Chemistry Test - 2 - Question 36

Which of the following carbonates decomposes readily at low temperatures?

BITSAT Chemistry Test - 2 - Question 37

A sample of O₂ gas collected over water at 23oC at a barometric pressure of 751mm Hg (vapour pressure of water at 23oC is 21mm Hg). The partial pressure of O₂ gas in the sample collected is

Detailed Solution for BITSAT Chemistry Test - 2 - Question 37
Using the Dalton's law 
PT = Poxygen +Pwater 
At 23.0 o C the vapor pressure of water is 21mmHg
751mmHg = Poxygen + 21 mmHg
Poxygen = 751 mmHg - 21 mmHg
Poxygen =730 mmHg

Convert the partial pressur of oxygen in to atmosphere
(730 mmHg) (1 atm / 760 mmHg) = 0.96 atm
BITSAT Chemistry Test - 2 - Question 38

Which of the following has highest osmotic pressure ?

Detailed Solution for BITSAT Chemistry Test - 2 - Question 38

NaCl is an electrolyte which dissociates to give ions.
N a C l → N a + + C l −
∴ concentration of ions in the solution = 2 M. Whereas glucose, sucrose and urea are non-electrolytes. Thus, NaCl has maximum concentration and highest osmotic pressure.

BITSAT Chemistry Test - 2 - Question 39

How much quick lime can be obtained from 25 gm of CaCO₃ ?

BITSAT Chemistry Test - 2 - Question 40

An example of an associated colloid is

Detailed Solution for BITSAT Chemistry Test - 2 - Question 40
Associated colloids are those colloids which behave as normal strong electrolytes at low concentrations but exhibit colloidal properties at higher concentrations due to the formation of aggregated particles. The aggregated particles thus formed are called micelles. 
The associated colloids are usually formed by surfactants (surface active agents) like soaps and synthetic detergents. These agents form micelles when present in solution at a concentration greater than critical micellization concentration (CMC). 

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