JEE Exam  >  JEE Tests  >  BITSAT Chemistry Test - 9 - JEE MCQ

BITSAT Chemistry Test - 9 - JEE MCQ


Test Description

30 Questions MCQ Test - BITSAT Chemistry Test - 9

BITSAT Chemistry Test - 9 for JEE 2024 is part of JEE preparation. The BITSAT Chemistry Test - 9 questions and answers have been prepared according to the JEE exam syllabus.The BITSAT Chemistry Test - 9 MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for BITSAT Chemistry Test - 9 below.
Solutions of BITSAT Chemistry Test - 9 questions in English are available as part of our course for JEE & BITSAT Chemistry Test - 9 solutions in Hindi for JEE course. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free. Attempt BITSAT Chemistry Test - 9 | 30 questions in 40 minutes | Mock test for JEE preparation | Free important questions MCQ to study for JEE Exam | Download free PDF with solutions
BITSAT Chemistry Test - 9 - Question 1

Which of the following has zero dipole moment?

Detailed Solution for BITSAT Chemistry Test - 9 - Question 1

CH4 has a regular tetrahedral geometry, so it has zero dipole moment. Again all the C-H bonds are identical. PH3 has pyramidal geometry while NH4+ is polar due to presence of +ve charge.

BITSAT Chemistry Test - 9 - Question 2

Lyophilic colloids are stable due to

Detailed Solution for BITSAT Chemistry Test - 9 - Question 2

Lyophilic sols are more stable due to the fact that lyophilic colloids are extensively solvated, which means the colloidal particles are covered by a layer of dispersion medium.

1 Crore+ students have signed up on EduRev. Have you? Download the App
BITSAT Chemistry Test - 9 - Question 3

The hybridisation of carbon in diamond, graphite and acetylene is in the order of

Detailed Solution for BITSAT Chemistry Test - 9 - Question 3

In diamond, each carbon is bonded covalently to four other carbon atoms by sp3 hybridisation. In graphite, each carbon atoms is linked to three other carbon atom by sp2 hybridisation. In acetylene, there is sp hybridisation.

BITSAT Chemistry Test - 9 - Question 4

Ozone is prepared by passing silent electric discharge through oxygen. In this reaction

Detailed Solution for BITSAT Chemistry Test - 9 - Question 4

Some of the oxygen molecules dissociate when silent electric discharge is passed. Then atomic oxygen combines with oxygen molecules.

Energy is absorbed in this reaction.

BITSAT Chemistry Test - 9 - Question 5

Which of the following compounds do not belong to lipids?

Detailed Solution for BITSAT Chemistry Test - 9 - Question 5

Lipids are constituents of plants and tissues. They include fats, oils, carbohydrates, phospholipids, wax, steroids etc. and mainly made up of carbon, hydrogen and oxygen.These are ester class of compounds, while amino acids do not belong to lipids.

BITSAT Chemistry Test - 9 - Question 6

Aspirin is obtained by the reaction of salicylic acid with

Detailed Solution for BITSAT Chemistry Test - 9 - Question 6

BITSAT Chemistry Test - 9 - Question 7

The correct order of the increasing ionic character is

Detailed Solution for BITSAT Chemistry Test - 9 - Question 7

The electropositive character of alkaline earth metal increases down the group, therefore, larger alkaline earth metals are able to form ions more easily. So the ionic character of chlorides of these metals increases down the group.
i.e.,BaCI2 < MgCL2 < CaCI2 < BeCI2 (Ionic character)

BITSAT Chemistry Test - 9 - Question 8

A sudden large jump between the values of second and third ionization energies of an element would be associated with which of the following electronic configuration?

Detailed Solution for BITSAT Chemistry Test - 9 - Question 8

A sudden large jump between the values of 2nd and 3rd ionisation energies of an element indicates, that the element has two-electrons in its valence shell. Then the possible electronic configuration may be-----> 1s2, 2s2, 2p6, 3s2

BITSAT Chemistry Test - 9 - Question 9

The oxidation of toluene to benzaldehyde by chromyl chloride is called

Detailed Solution for BITSAT Chemistry Test - 9 - Question 9

Etard reaction -Chromium chloride dissolved in CCL4 is made to react with toluene and product formed is decomposed with water.

BITSAT Chemistry Test - 9 - Question 10

 If acetyl chloride is reduced in the presence of BaS04 and Pd, then

Detailed Solution for BITSAT Chemistry Test - 9 - Question 10


When H2 gas is passed through a solution of acetyl chloride in xylene in presence of Pd and BaS04 poisoned by sulphur acetaldehyde is formed. This reaction is called as Rosenmund’s reduction reaction.

BITSAT Chemistry Test - 9 - Question 11

The best route for the preparation of BeF2 is

Detailed Solution for BITSAT Chemistry Test - 9 - Question 11

It cannot be prepared by the direct reaction of Be and F2 because of high ionisation and atomisation enthalpy of Be.
Be cannot replace Li.
So, the best route is the thermal decomposition of  (NH4)2BeF4
Thermal decomposition of (NH4)2BeF4
(NH4)2[BeF4]→2NH4F+BeF2

BITSAT Chemistry Test - 9 - Question 12

A piece of magnesium was heated in the atmosphere of nitrogen. The compound formed after cooling and treating with water is

Detailed Solution for BITSAT Chemistry Test - 9 - Question 12

3Mg + N2 →Mg3N2
Mg3N2 + 6H2O→3Mg(OH)2 + 2NH3

BITSAT Chemistry Test - 9 - Question 13

The right order of the solubility of sulphates of alkaline earth metals in water is

Detailed Solution for BITSAT Chemistry Test - 9 - Question 13

Be < Mg < Ca < Sr < Ba. The size of the ion is very big (approx. 3Å). Therefore, as the size of the cation increases, their hydration energies decrease more rapidly than their lattice energies. Consequently, the solubilities of sulphates decrease down the group.

BITSAT Chemistry Test - 9 - Question 14

What is the chemical formula of gypsum?

Detailed Solution for BITSAT Chemistry Test - 9 - Question 14

The chemical formula of Plaster of Paris is While the chemical formula of gypsum is CaSO4.2H2O

BITSAT Chemistry Test - 9 - Question 15

Which of the following has largest ionic radius?

Detailed Solution for BITSAT Chemistry Test - 9 - Question 15

In the periodic table, the elements are arranged in increasing order of their atomic numbers.
As we move from top to bottom in the periodic table, the atomic number of the elements increases.
By this definition, the atomic number increases in the order Li+ < Na+ < K< Cs+.
As we move from top to bottom in the periodic table, the ionic radius of elements keeps on increasing. This is because as one electron is removed from the valence shell of the atom, the effective nuclear charge on the valence shell decreases. Thus, ionic radius increases.
Therefore, the ionic radius of Cs+ is the largest.

BITSAT Chemistry Test - 9 - Question 16

Which one of the following liberates oxygen on reacting with H2O?

Detailed Solution for BITSAT Chemistry Test - 9 - Question 16

When H2O reacts with KO2, it liberates oxygen.
2KO2+H2O→2KOH+H2O2+ 1/2 O2
Whereas, others do not liberate oxygen when react with H2O.
NaOH gets dissolved in water.
BeO does not react with water due to its covalent nature.
Li2O dissolves in water to make lithium hydroxide.

BITSAT Chemistry Test - 9 - Question 17

A white precipitate is formed when gas A bubbled through slaked lime solution and the precipitate dissolves on prolonged bubbling of gas A. White precipitate reappears on heating the solution with evolution of gas B. Find the gases A and B.

Detailed Solution for BITSAT Chemistry Test - 9 - Question 17

BITSAT Chemistry Test - 9 - Question 18

Which alkali metal gives the least wavelength of light emitted in a flame?

Detailed Solution for BITSAT Chemistry Test - 9 - Question 18

Most alkali metals glow with a characteristic colour when placed in a flame.
The energy of the flame causes excitation of the outermost electron, which on return to its ground state releases energy, which falls in the visible region.
The frequency of the light emitted is observed to increase with respect to:

The energy released will be increasing from Li+ to Cs+
As the size of Cs is large, it requires the least amount of energy to excite the electrons. Hence, it releases high energy radiation because the colour emitted is complementary to colour absorbed.
Since energy released is high, the wavelength of light emitted in the flame will be least for caesium.
The colours so exhibited by the flames will be: lithium shows crimson red, sodium is a golden yellow, potassium is pale violet, rubidium is a red-violet and caesium emits blue.

BITSAT Chemistry Test - 9 - Question 19

Property of the alkaline earth metals that increases with their atomic number.

Detailed Solution for BITSAT Chemistry Test - 9 - Question 19

The solubility of an ionic compound depends on two factors :
(a) Lattice energy, and (b) Hydration energy

In case of alkaline metal hydroxides, the lattice energy decreases as we move down the group. This decrease is more than the decrease in the hydration energy down the group.

BITSAT Chemistry Test - 9 - Question 20

Sodium is heated in air at 300oC  to form X. It absorbs CO2 and forms Na2CO3 and Y. Which of the following is Y?

Detailed Solution for BITSAT Chemistry Test - 9 - Question 20

When sodium is heated in air at 300°C, it forms sodium peroxide (Na2O2).

This sodium peroxide reacts with CO2 to give Na2 CO3 and O2.

BITSAT Chemistry Test - 9 - Question 21

Two vessels connected by a valve of negligible volume. One container (I) has 2.8 g of N2 at temperature T1(K). The other container (II) is completely evacuated. The container (I) is heated to T2(K) while container (II) is maintained at T2 / 3 (K). Volume of vessel (I) is half that of vessel (II). If the valve is opened then what is the weight ratio of N2 in both vessel (WI / WII)?

Detailed Solution for BITSAT Chemistry Test - 9 - Question 21

BITSAT Chemistry Test - 9 - Question 22

According to Graham's law, at a given temperature the ratio of the rates of diffusion of gases A and B is given by (where, p and M are pressures and molecular weights of gases A and B respectively)

Detailed Solution for BITSAT Chemistry Test - 9 - Question 22

According to Graham's law of diffusion, rate of diffusion of the gas is inversely proportional to the square root of the molecular mass.

Relative rates of diffusion if two gases.

PA and PB are partial pressures at which they are diffusing.

BITSAT Chemistry Test - 9 - Question 23

Which one of the following represents the graph between

(p=vapour pressure of a liquid, T=absolute temperature)

Detailed Solution for BITSAT Chemistry Test - 9 - Question 23

According to Clausius-Clapeyron, if a graph is plotted between a straight line is obtained with negative slope.

BITSAT Chemistry Test - 9 - Question 24

The correct form of van der Waals' equation at low pressures is:

Detailed Solution for BITSAT Chemistry Test - 9 - Question 24

Van der Waals' equation (for one mole):

at low pressure Vm will be high in comparison to the volume of molecules as the molecules will be quite apart to each other and thus empty space is large.
 'b' can be neglected 

BITSAT Chemistry Test - 9 - Question 25

Which of the following relation is correct for one mole of an ideal gas,?

Detailed Solution for BITSAT Chemistry Test - 9 - Question 25

PV = RT

This can also be derived from Euler's chain rule in Mathematics.

BITSAT Chemistry Test - 9 - Question 26

4.0 g of argon has pressure P at temperature T K in a vessel. On keeping the sample at 50° higher temperature, 0.8 g gas was given out to maintain the pressure P. The original temperature was

Detailed Solution for BITSAT Chemistry Test - 9 - Question 26

At constant P and V,
n1T1=n2T2
4T1=3.2(T1+50)
On solving,
T1=200K

BITSAT Chemistry Test - 9 - Question 27

In which of the following mixtures, Dalton's law of partial pressure is not applicable? (Assume room temperature)

Detailed Solution for BITSAT Chemistry Test - 9 - Question 27

Dalton's law of partial pressure is not applicable to gases which react chemically and produce different number of moles of products than the reactants. Some gases which do not obey this law are
SO2+Cl2, CO+Cl2, NO+O2, NH3+HCl and H2 + Cl2

BITSAT Chemistry Test - 9 - Question 28

If 200 cm3 of gas at 1 atm is compressed to 50 cm3 at constant temperature, what will be the resultant pressure?

Detailed Solution for BITSAT Chemistry Test - 9 - Question 28

Given, V1=200 cm3, P1=1 atm
V2=50 cm3, P2=?
Boyle's law states that the pressure exerted by a gas is inversely proportional to its volume at a constant temperature. According to Boyle's law,
P1V1=P2V2
1×200=P2×50

BITSAT Chemistry Test - 9 - Question 29

Decomposition of A in a rigid closed vessel takes place as A(g) → 3B(g), which follows 1st order kinetics. Reaction is started with an equimolar mixture of a gas A and an inert gas X. The initial pressure was 4 atm and at the end of 20 min, the total pressure is 6 atm. The time required for 75% reaction of A will be

Detailed Solution for BITSAT Chemistry Test - 9 - Question 29

A → 3B
At t = 0, 2 atm
At t = 20; 2 - x + 3x
2 - x + 3x + 2 = 6 ⇒ x = 1
Applying k = we get
t75% = 40 min

BITSAT Chemistry Test - 9 - Question 30

Which of the following conditions show the polluted environment?

a. pH of rain water = 5.6
b. Eutrophication
c. Biochemical oxygen demand = 10 ppm
d. Amount of carbon dioxide in the atmosphere = 0.03%

Detailed Solution for BITSAT Chemistry Test - 9 - Question 30

Clean water has BOD value less than 5 ppm. The BOD value more than 5 ppm indicates the polluted water. The excessive growth of algae and aquatic plants due to the presence of plant nutrients is called eutrophication. The decomposition of these aquatic plants utilises the dissolved oxygen, which proves fatal for aquatic animals.

Information about BITSAT Chemistry Test - 9 Page
In this test you can find the Exam questions for BITSAT Chemistry Test - 9 solved & explained in the simplest way possible. Besides giving Questions and answers for BITSAT Chemistry Test - 9, EduRev gives you an ample number of Online tests for practice

Top Courses for JEE

Download as PDF

Top Courses for JEE