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Bihar STET Paper 1 Mathematics Mock Test - 3 - Bihar PGT/TGT/PRT MCQ


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30 Questions MCQ Test - Bihar STET Paper 1 Mathematics Mock Test - 3

Bihar STET Paper 1 Mathematics Mock Test - 3 for Bihar PGT/TGT/PRT 2025 is part of Bihar PGT/TGT/PRT preparation. The Bihar STET Paper 1 Mathematics Mock Test - 3 questions and answers have been prepared according to the Bihar PGT/TGT/PRT exam syllabus.The Bihar STET Paper 1 Mathematics Mock Test - 3 MCQs are made for Bihar PGT/TGT/PRT 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Bihar STET Paper 1 Mathematics Mock Test - 3 below.
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Bihar STET Paper 1 Mathematics Mock Test - 3 - Question 1

The radius of a circle if its perimeter and area are numerically equal is​

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 3 - Question 1

Perimeter of circle = 2πr
Area of circle= πr2
Perimeter = Area
2πr= πr2
2= πr2/r
πr gets cancelled
So r = 2 units

Bihar STET Paper 1 Mathematics Mock Test - 3 - Question 2

If the sum of the zeroes of the cubic polynomial 4x3−kx2−8x−12 is -3/4  then the value of ‘k’ is

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 3 - Question 2

Let α,β,γ are the zeroes of the given polynomial. Given: α+β+γ = (-3/4)

Bihar STET Paper 1 Mathematics Mock Test - 3 - Question 3

The 6th term from the end of the AP: 5, 2, -1 , -4 , . . . , -31 is

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 3 - Question 3

The given AP is 5, 2, -1, -4 ... ...., -31
d = 2 - 5 = -3, so d for the AP starting from the last term is 3.
The first term = l = -31
We know, a= a+(n−1)d
a6 from the end = −31+(5)3
a6 from the end = −16

Bihar STET Paper 1 Mathematics Mock Test - 3 - Question 4

One of the sides of a frequency polygon is

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 3 - Question 4

The x-axis is one of the sides of a frequency polygon. The x-axis represents the values of the variable being measured.

Bihar STET Paper 1 Mathematics Mock Test - 3 - Question 5

The value of (tan1° tan2° tan3°... tan89°) is

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 3 - Question 5

tan 1 . tan 2 . tan 3 ... tan 87 . tan 88 . tan 89 = LHS 
tan 1 . tan 2 . tan 3 ... tan (90 - 3 ) . tan ( 90 - 2 ) . tan ( 90 - 1)
tan 1 . tan 2  . tan 3 ... cot 3 . cot 2 . cot 1 

tan 1 . cot 1 . tan 2 . cot 2 . tan 3 . cot 3 ... tan 89 . cot 89 
1 x 1 x 1 x 1 x ... x 1 
As 1ⁿ = 1  = RHS 

Bihar STET Paper 1 Mathematics Mock Test - 3 - Question 6

The line x = 3 is

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 3 - Question 6
Line x=3 has special form - it is not from the same family of lines in the form y=mx+b.

Slope is not defined for a line x=3 because it represents vertical line.

Remember the definition of slope. In common words, it is the value that tells us how much is line increasing/decreasing as we move from left to right on the graph. That is why horizontal lines have zero slope - no increase nor decrease on horizontal line.

Now, imagine vertical line. In only 1 point it increases in infinity. Thus, we cannot use any real value of m to describe this behaviour.
Bihar STET Paper 1 Mathematics Mock Test - 3 - Question 7

In given AP 210 is …………. th term of: 2,6,10……..​

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 3 - Question 7

We have a=2, d=6-2=4
l=a+(n-1)d
210=2+(n-1)4
208/4=n-1
n=53rd term

Bihar STET Paper 1 Mathematics Mock Test - 3 - Question 8

The decimal expansion of number 

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 3 - Question 8

A number with terminal decimal expansions have the denominator  in the form,
2m 5where m & n ∈ W.
The number 
Which the denominator is in the form,
 with m = 2 , n = 3.
Hence, it has terminal decimal expansion.

Bihar STET Paper 1 Mathematics Mock Test - 3 - Question 9

Which one of the following statements is correct

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 3 - Question 9

Bihar STET Paper 1 Mathematics Mock Test - 3 - Question 10

The radius of a circle whose circumference is equal to the sum of the circumferences of the two circles of diameters 36 cm and 20 cm is​

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 3 - Question 10

Diameter of first circle = d1 = 36 cm
Diameter of second circle = d2 = 20 cm
∴ Circumference of first circle = πd1 = 36π cm
Circumference of second circle = πd2 = 20π cm
Now, we are given that,
Circumference of circle = Circumference of first circle + Circumference of second circle
πD = πd1 + πd2
⇒ πD = 36π + 20π
⇒ πD = 56π ⇒ D = 56
⇒ Radius = 56/2 = 28 cm

Bihar STET Paper 1 Mathematics Mock Test - 3 - Question 11

The first, second and last terms of an A.P. are a,b and 2a. The number of terms in the A.P. is :

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 3 - Question 11

A.P : a , b , . . . . . . . . . . . . . .2a

1st term= a1 = a

2nd term = a2= b

nth term = an = 2a

d = a2 - a1 = b-a

an = a1 + (n-1)d = a + (n-1)(b-a) = 2a

(n-1)(b-a) = a

(n-1) = a / (b-a)

n = a / (b-a) + 1 = b / ( b -a )

 

Bihar STET Paper 1 Mathematics Mock Test - 3 - Question 12

The value of  

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 3 - Question 12

Bihar STET Paper 1 Mathematics Mock Test - 3 - Question 13

The LCM of two numbers is 1200. Which of the following cannot be their HCF?

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 3 - Question 13

Bihar STET Paper 1 Mathematics Mock Test - 3 - Question 14

Two natural numbers whose difference is 66 and the least common multiple is 360, are:

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 3 - Question 14

Let the two numbers be x and x+66.

Since, the LCM is 360, there must be 5,2 and 3 as the prime factors of the two numbers.

So, one pair is 24 & 90, because 90−24=66.

Also, 24=2×2×2×3

90=2×3×3×5

∴ LCM=2×2×2×3×3×5=360.

So, the numbers are 24 and 90.

Bihar STET Paper 1 Mathematics Mock Test - 3 - Question 15

The mean of 1, 2, 3, 4 …n is given by

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 3 - Question 15

⇒   We have the sequence, 1,2,3.......n
⇒   This is an AP, with the initial term a=1 and the common difference d=1.
∴   The sum of n terms of an AP is given by,


→   Arithmetic mean of n numbers a1​,a2​,a3​,a4​,...an​ is given by the formula

Bihar STET Paper 1 Mathematics Mock Test - 3 - Question 16

If one of the zeroes of the quadratic polynomial (k - 1)x2 + kx + 1 is -3, then the value of k is:

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 3 - Question 16

p(x) = (k - 1)x2 + kx +1

One zero of polynomial is - 3 i.e. p(-3) = 0
⇒ (k - 1) (-3)2 + k(-3) + 1 = 0
⇒ 9k - 9 - 3k + 1 = 0
⇒ 6k - 8 = 0
⇒ k = 8/6 = 4/3

Bihar STET Paper 1 Mathematics Mock Test - 3 - Question 17

Read the following text and answer the following question on the basis of the same:

Authority wants to construct a slide in a city park for children. The slide was to be constructed for children below the age of 12 years. Authority prefers the top of the slide at a height of 4 m above the ground and inclined at an angle of 30° to the ground.

Q. In the given figure, if AB + BC = 25 cm and AC = 5 cm, then the value of BC is:

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 3 - Question 17

We have,

∠C = 90°

AB + BC = 25 cm and AC = 5 cm

Let BC be x cm, then AB = (25 – x) cm

By using Pythagoras theorem,

AB2 = BC2 + AC2

⇒ (25 – x2) = x2 + (5)2

⇒ 625 – 50x + x2 = x2 + 25

⇒ 50x = 600

⇒ x = 600 / 50 = 12

Hence, BC = 12 cm

Bihar STET Paper 1 Mathematics Mock Test - 3 - Question 18

If ‘sin α’ and ‘cos α’ are the roots of the equation ax2+bx+c = 0 a then b2 =

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 3 - Question 18


Bihar STET Paper 1 Mathematics Mock Test - 3 - Question 19

A park is in the form of a rectangle 120m by 90 m. At the centre of the park there is a circular lawn as shown in the figure. If the area of the park excluding the lawn is 2950 m2, then the radius of the circular lawn will be 

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 3 - Question 19

ANSWER :- b

Solution :- Area of rec. park=(120×90)m²=10800m²

Area of rec. park excluding lawn=2950m²

Area of circular lawn=(10800 - 2950)m²

=7850m²

Let the radius be = r

7850/3.14 = 3.14r²/3.14

→2500 = r²

→√2500 = √r²

→50 = r

→r = 50

Radius = 50m

Bihar STET Paper 1 Mathematics Mock Test - 3 - Question 20

One of the factors of (16y2−1)+(1−4y)2 is

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 3 - Question 20

Begin by noting that squaring (1 - 4y) gives (1 - 4y)² = (-1)² · (4y - 1)², which simplifies to (4y - 1)².

The expression then becomes (16y² - 1) + (4y - 1)².

Recognize that 16y² - 1 is a difference of two squares and factors as (4y - 1)(4y + 1).

Since (4y - 1) appears as a factor in both terms, it is one of the factors of the entire expression.

Bihar STET Paper 1 Mathematics Mock Test - 3 - Question 21

The UN organization that is related with education is

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 3 - Question 21

UNESCO is a United Nations' organization that uses education, culture and science as a medium to promote international collaboration and lead to peace and security in the world.

Bihar STET Paper 1 Mathematics Mock Test - 3 - Question 22

According to the NEP (2020)-

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 3 - Question 22

Indian education structure and management were guided by New Education Policy, of 1986 for a long time (almost 34 years). In the meantime, a lot of changes have taken place globally as well as a debate has also emerged in India about a ‘Bharat-centric’ policy on education.

  • In order to look into those, a new committee was set up under the chairmanship of Dr. K. Kasturirangan in June 2017. After reviewing the suggestions, the committee finalized the policy under the name National Education Policy, 2020 on July 29, 2020. 

Key Points

Major recommendations of the policy were -

  • The aim of equity and inclusion is now at the heart of the new NEP so the classroom should be inclusive.
  • Ensuring universal access at all levels of schooling from pre-primary school to Grade 12.
  • Ensuring quality early childhood care and education for all children between 3-6 years.
  • New Curricular and Pedagogical Structure (5+3+3+4)including foundational, preparatory, middle, and secondary.
  • Establishing National Mission on Foundational Literacy and Numeracy.
  • Emphasis on promoting multilingualism and Indian languages. 
  • Exposure to vocational education in school and higher education system.
  • Focus on Formative and Diagnostic Assessment.
  • Setting up multidisciplinary education and research universities(MERUs).
  • Setting up of National Research Foundation(NRF).
  • Multidisciplinary approach and focus on creative and divergent thinking.
  • Experiential learning using previous knowledge and experiences.
  • Teacher Education - 4-year integrated stage-specific, subject-specific Bachelor of Education.

Hence, it is concluded that all the above options are correct.

Bihar STET Paper 1 Mathematics Mock Test - 3 - Question 23

Which of the following is a significant cause for the failure of a teacher?

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 3 - Question 23

Excessive strictness is a negative trait that can lead to resistance in students. The teacher must strive to create an atmosphere where the students can learn without fearing of being ridiculed or belittled. They need an environment which is safe to learn by their mistakes.

Bihar STET Paper 1 Mathematics Mock Test - 3 - Question 24

Mr. Rathore uses a lot of audio-visual aids while teaching. The main reason for doing so is

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 3 - Question 24

Mr. Rathore uses a lot of audio-visual aids while teaching. The main reason for doing so is to take care of the requirements of all the children. Audio-visual aids make the learning permanent. They stimulate both aural and visual senses of children. Some children understand better on observation i.e. visual, whereas other students understand better on aural stimulation. Thus, requirements of all the students are taken care of.

Bihar STET Paper 1 Mathematics Mock Test - 3 - Question 25

Assertion (A): A teacher records the pace of development of the students in his class, and finds that the pace of development is not equal for all the students.
Reason (R):  Development varies from person to person because it follows the principle of individual differences.

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 3 - Question 25

In psychology, individual differences refer to the extent and kind of variations or similarities among people on some of the important psychological aspects such as intelligence, personality, interest, and aptitude.

Bihar STET Paper 1 Mathematics Mock Test - 3 - Question 26
Which classes are included in the preparatory stage as per the new education policy 2020?
Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 3 - Question 26

National Education Policy 2020 is India’s First 21st Century Education Policy. Which makes many relevant changes in the education system from elementary education to Higher education.

Key PointsAccording to NEP 2020:

  • ​A "5+3+3+4" curriculum framework is planned as part of the 2020 education reform.
  • Based on age divisions, NEP 2020 has divided schooling into several phases.
  • The policy prioritizes three years of preschool and twelve years of formal education.

Thus, classes 3rd to 5th are​ included in the preparatory stage as per the new education policy 2020

Bihar STET Paper 1 Mathematics Mock Test - 3 - Question 27

Theory of multiple intelligence was given by  

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 3 - Question 27

Theory of multiple intelligence was given by Howard Gardner and he proposed eight different intelligences to determine human potential.

Bihar STET Paper 1 Mathematics Mock Test - 3 - Question 28

Which one of the following is a form of Sternberg's triarchic theory of intelligence?  

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 3 - Question 28

In the triarchic theory, three types of intelligence proposed by Robert Sternberg are: Analytical, Creative and Practical.

Bihar STET Paper 1 Mathematics Mock Test - 3 - Question 29

Which of the following is/are the non-governmental organisation(s) dedicated to wildlife conservation?

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 3 - Question 29

World Wildlife Fund for Nature, INDIA is a non-governmental organisation working in the field of the wilderness preservation, and the reduction of human impact on the environment.
The others are governmental organisations.

Bihar STET Paper 1 Mathematics Mock Test - 3 - Question 30

Choose the alternative which is an odd word/number/letter pair out of the given alternatives.

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 3 - Question 30

Trapezoid, Rhombus, and Parallelogram are the 2 dimensional figure.

While;

Prism is a 3-dimensional figure.

Hence, "Prism" is the correct answer.

Important Points

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