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Bihar PGT/TGT/PRT Exam  >  Bihar PGT/TGT/PRT Tests  >  Bihar STET Mock Test Series 2024  >  Bihar STET Paper 1 Mathematics Mock Test - 4 - Bihar PGT/TGT/PRT MCQ

Bihar STET Paper 1 Mathematics Mock Test - 4 - Bihar PGT/TGT/PRT MCQ


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30 Questions MCQ Test Bihar STET Mock Test Series 2024 - Bihar STET Paper 1 Mathematics Mock Test - 4

Bihar STET Paper 1 Mathematics Mock Test - 4 for Bihar PGT/TGT/PRT 2024 is part of Bihar STET Mock Test Series 2024 preparation. The Bihar STET Paper 1 Mathematics Mock Test - 4 questions and answers have been prepared according to the Bihar PGT/TGT/PRT exam syllabus.The Bihar STET Paper 1 Mathematics Mock Test - 4 MCQs are made for Bihar PGT/TGT/PRT 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Bihar STET Paper 1 Mathematics Mock Test - 4 below.
Solutions of Bihar STET Paper 1 Mathematics Mock Test - 4 questions in English are available as part of our Bihar STET Mock Test Series 2024 for Bihar PGT/TGT/PRT & Bihar STET Paper 1 Mathematics Mock Test - 4 solutions in Hindi for Bihar STET Mock Test Series 2024 course. Download more important topics, notes, lectures and mock test series for Bihar PGT/TGT/PRT Exam by signing up for free. Attempt Bihar STET Paper 1 Mathematics Mock Test - 4 | 150 questions in 150 minutes | Mock test for Bihar PGT/TGT/PRT preparation | Free important questions MCQ to study Bihar STET Mock Test Series 2024 for Bihar PGT/TGT/PRT Exam | Download free PDF with solutions
Bihar STET Paper 1 Mathematics Mock Test - 4 - Question 1
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A polynomial of degree three is called ……

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 4 - Question 1

A cubic polynomial is a polynomial of the form . A cubic polynomial is a polynomial of degree 3. A univariate cubic polynomial has the form . An equation involving a cubic polynomial is called a cubic equation. A closed-form solution known as the cubic formula exists for the solutions of an arbitrary cubic equation.

Bihar STET Paper 1 Mathematics Mock Test - 4 - Question 2
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Aarti selects a card from a pack of well shuffled 52 playing cards. She needs an ace to win the game. The probability of Aarti losing the game is​

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 4 - Question 2

P(E) = number of expected trials / total number of trials
A standard deck of cards has 52 cards.
Number of expected trials = 4 x 12 = 48 cards
Total number of trials = 52
Therefore, P(E) = 48/52
= 12/13

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Bihar STET Paper 1 Mathematics Mock Test - 4 - Question 3
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A river is 60m wide. A tree of unknown height is on one bank. The angle of elevation of the top of the tree from the point exactly opposite to the foot of the tree, on the other bank, is 30°. The height of the tree is

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 4 - Question 3

Let the river BC be the width of 60 m

and angle of elevation = 30°
To find: Height of the tree AC

Therefore, the height of the tree is 20 √3m.

Bihar STET Paper 1 Mathematics Mock Test - 4 - Question 4
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√2 is a polynomial of degree
Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 4 - Question 4

The highest power of the variable is known as the degree of the polynomial.

√2x^0 = √2
hence the degree of the polynomial is zero.

Bihar STET Paper 1 Mathematics Mock Test - 4 - Question 5
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The multiplicative inverse of zero is
Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 4 - Question 5

Some rules associated with Multiplicative Inverse are discussed in following ways :- 
Rule 1 = If product of two Fractional Numbers is equal to 1, then each of the Fractional Numbers is the Multiplicative Inverse of other. 
Rule 2 = If the product of a Fractional Number and a Whole Number is equal to 1, then each is the Multiplicative Inverse of other. 
Rule 3 = Multiplicative Inverse of 1 is also 1. 
Rule 4 = Multiplicative Inverse of 0 (zero) does not exists 

Bihar STET Paper 1 Mathematics Mock Test - 4 - Question 6
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Every positive even integer is of the form ____ for some integer ‘q’.
Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 4 - Question 6

Let a be any positive integer and b = 2
Then by applying Euclid’s Division
Lemma, we have, a = 2q + r where 0 ⩽ r < 2 r = 0 or 1
Therefore, a = 2q or 2q+1 
Therefore, it is clear that a = 2q i.e., 
a is an even integer in the form of 2q

Bihar STET Paper 1 Mathematics Mock Test - 4 - Question 7
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The largest number which divides 70 and 125, leaving remainders 5 and 8, respectively, is
Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 4 - Question 7

Since 5 and 8 are the remainders of 70 and 125, respectively. Thus after subtracting these remainders from the numbers, we have the numbers
65 = (70 − 5), 117 = (125 − 8) which is divisible by the required number.
Now required number = H.C.F of (65,117)

Bihar STET Paper 1 Mathematics Mock Test - 4 - Question 8
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If  sec θ =  then the value of the 
Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 4 - Question 8

We have, 
Dividing by cosθ

Substituting the value of tan θ
we receive the answer.

Bihar STET Paper 1 Mathematics Mock Test - 4 - Question 9
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If the diameter of a cylinder is 28 cm and its height is 20 cm, then total surface area (in cm2) is :
Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 4 - Question 9

Given a cylinder with

Radius = 28 / 2 = 14 cm

Height = 20 cm

ii.) Total surface area = 2πr ( r + h )

= 2 x 22 / 7 x 14cm ( 14 + 20 )cm

= 2991.99cm2
=2992cm2
(b) 2992cm2 is the correct option.

Bihar STET Paper 1 Mathematics Mock Test - 4 - Question 10
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Direction: Child labour refers to any work or activity that deprives children of their childhood. It is a violation of children's rights. This can harm them mentally or physically. It also exposes them to hazardous situations or stop them from going to school. Naman got data on number of child labours (in million) in different country that is given below.

Q. Which country has the highest child labour?
Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 4 - Question 10
According to data, India has the highest child labour i.e. 20 million.
Bihar STET Paper 1 Mathematics Mock Test - 4 - Question 11
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Using the ratio of complementary angles, the value of   is
Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 4 - Question 11

Explanation:

Ratio of Complementary Angles:

- Complementary angles are two angles that add up to 90 degrees.
- The ratio of complementary angles is the ratio of the measures of the two angles that add up to 90 degrees.

Given:
Let the two complementary angles be x and y.

Therefore:
x + y = 90

Ratio of Complementary Angles:
The ratio of the two angles can be represented as:
x:y

Using the given information:
x + y = 90
x = 90 - y

Substitute x in the ratio:
(90 - y) : y

Simplify the ratio:
90 : y

Therefore:
The ratio of the two complementary angles is 90 : y.

Conclusion:
Since the ratio of complementary angles is 90 : y, the value of y is 1.

Answer:
C: 1

Bihar STET Paper 1 Mathematics Mock Test - 4 - Question 12
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The decimal expansion of 21/24 will terminate after
Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 4 - Question 12

 
Here, in the denominator of the given fraction the highest power of prime factor 2 is 3, therefore, the decimal expansion of the rational numberwill terminate after 3 decimal places. 

Bihar STET Paper 1 Mathematics Mock Test - 4 - Question 13
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If tan θ = √3, the sec θ =
Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 4 - Question 13

Bihar STET Paper 1 Mathematics Mock Test - 4 - Question 14
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The difference of a rational and an irrational number is always
Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 4 - Question 14

The difference of a rational and an irrational number is always an irrational number.

Bihar STET Paper 1 Mathematics Mock Test - 4 - Question 15
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Given that two of the zeros of the cubic polynomial ax3 + bx2 + cx + d are 0, the value of c is
Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 4 - Question 15

Explanation:

Given Information:
- Two zeros of the cubic polynomial are 0.
- Therefore, the cubic polynomial can be written as ax^3 + bx^2 + cx + d = a(x - 0)(x - 0)(x - k) = ax^3 - akx^2 = ax^3.

Finding the value of c:
- Since the coefficient of the linear term in the polynomial is c, and two of the zeros are given to be 0, the sum of the zeros is 0 + 0 + k = -b/a.
- As k represents the remaining zero, this implies that k = -b/a.
- Since the sum of the zeros of a cubic polynomial is -b/a, the value of c cannot be determined from the given information.
- Therefore, the correct answer is c.​​​​

Bihar STET Paper 1 Mathematics Mock Test - 4 - Question 16
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If cos (40° + A) = sin 30°, the value of A is:​
Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 4 - Question 16

cos(θ)=sin(90-θ)
so 40+A+30=90
A=20

Bihar STET Paper 1 Mathematics Mock Test - 4 - Question 17
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If the circumference of a circle and the perimeter of a square are equal, then
Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 4 - Question 17

Let the radius of the circle be r and side of the square be a.
Then, according to question,
2πr = 4a

Now, ratio of their areas,

Therefore, Area of the circle > Area of the square 

Bihar STET Paper 1 Mathematics Mock Test - 4 - Question 18
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If (x-1) is a factor of ax – a, then find the value of a​
Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 4 - Question 18

ANSWER :- d

Solution :- f(x) = ax - a……………………..(1)

x - 1 = 0

x = 1

Putting in eq(1)

(1)x - 1 => x - 1

 

For eg :- if we put x = 100

Putting in eq(1)

(100)x - 100 => x - 100

So, all the values of a

Bihar STET Paper 1 Mathematics Mock Test - 4 - Question 19
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If a marble of radius 2.1 cm is put into a cylindrical cup full of water of radius 5 cm and height 6 cm, then how much water flows out of the cylindricall cup?
Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 4 - Question 19

Given, a marble of radius 2.1 cm is put into a cylindrical cup full of water of radius 5 cm and height 6 cm.

We have to find the quantity of water that flows out of the cylindrical cup.

We know that when the marble is put inside the cylindrical cup full of water the volume of water displaced is equal to the volume of the marble.

So, volume of water that flows out = volume of the marble

Volume of sphere = (4/3)πr3

Given, radius = 2.1 cm

So, volume of marble = (4/3)(22/7)(2.1)3

= 38.808 cm³

Therefore, the volume of the water that flows out is 38.8 cm³

Bihar STET Paper 1 Mathematics Mock Test - 4 - Question 20
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Two coins are tossed simultaneously. The probability of getting atmost one head is
Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 4 - Question 20

Two coin tossed
Total sample space = {HH, HT, TH, TT}
Sample space for getting atmost one head = {TT, TH, HT}
P(s) = 3/4 


​    

Bihar STET Paper 1 Mathematics Mock Test - 4 - Question 21
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Read the following text and answer the following questions on the basis of the same:

A small scale industry produces a certain boxes of candles in a day. Number of boxes prepared by each worked on a particular day was 2 more than thrice the number of workers working in the industry. The number of boxes produced in a particular day was 85.

Q. Number of workers working in the industry:
Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 4 - Question 21
Let the workers are x, Number of boxes prepared by the workers

= 2 + 3x

According to the question,

x(2 + 3x) = 85

⇒ 3x2 + 2x – 85 = 0

⇒ 3x2 + 17x – 15x – 85 = 0

⇒ x(3x + 17) – 5(3x + 17) = 0 ⇒

⇒ (3x + 17)(x – 5) = 0

⇒ x = 5

Bihar STET Paper 1 Mathematics Mock Test - 4 - Question 22
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Directions : In the following questions, A statement of Assertion (A) is followed by a statement of Reason (R). Mark the correct choice as.

Assertion (A): The Volume and Surface Area of a sphere are related to each other by radius.

Reason (R): Relation between Surface Area S and Volume V is S3 = 36πV2.
Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 4 - Question 22
Volume of sphere =

⇒

⇒

⇒

Also, S = 4πr2

⇒

⇒ which proves that assertion is correct.

Therefore, Both A and R are true and R is the correct explanation for A.

Bihar STET Paper 1 Mathematics Mock Test - 4 - Question 23
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Learning of an individual starts
Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 4 - Question 23

The stage of the embryo which nearly resembles a human being is called a fetus. Learning starts at fetal stage when a child starts reacting to different stimuli, as the sense organs are developed by this time.
The fetal nervous system starts developing very early in pregnancy. The main subdivisions of the brain are, in a basic form, visible at five gestational weeks. At about gestational weeks 25-29, the fetus is even able to hear internal (e.g. from the maternal gastrointestinal system) and external sounds. So, obviously the fetus gets a vague idea from the external environment through its senses, far before birth. Some studies even demonstrate that fetal heart rate patterns change distinctively, depending on whether the unborn child is exposed to the maternal voice or another female voice.

Bihar STET Paper 1 Mathematics Mock Test - 4 - Question 24
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At the primary level, National Education Policy 2020 proposes __________ as the medium of instruction across the nation.
Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 4 - Question 24

National Education Policy 2020  is the first education policy of the 21st century and aims to address the many growing developmental imperatives of our country.

  • This Policy proposes the revision and revamping of all aspects of the education structure, including its regulation and governance, to create a new system that is aligned with the aspirational goals of the 21st century.

Key Points

  • National Education Policy 2020 proposes that children in primary grades should be taught in their Mother tongue/Home language. 
  • This policy promotes multilingualism as multilingual education stresses using a student's mother tongue, or native language, to teach students and to make learning effective. 
  • Classrooms that use multilingual education use various strategies to help students learn in their native languages. 
  • Multilingualism enhances creativity, divergent thinking, and appreciation of local languages.

​Hence, we can conclude that at the primary level, National Education Policy 2020 proposes Mother tongue/Home language as the medium of instruction across the nation.

Bihar STET Paper 1 Mathematics Mock Test - 4 - Question 25
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In the teaching-learning process, a teacher who inculcates the principles of naturalism in her teaching ability will not utilise which of the following methods?
Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 4 - Question 25

As the teacher is following the principles of naturalism, she will not utilise project method. This is because project method is advocated by pragmatist and is focused mainly on child-in-society concept. The methods of teaching as per the naturalist include heuristic method, play-way method, observations and experiments.

Bihar STET Paper 1 Mathematics Mock Test - 4 - Question 26
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What is the purpose of question-answer technique in teaching?
Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 4 - Question 26

The main purpose of teaching is to increase interest of all the students in the subject. The question-answer technique leads to motivation of students and increasing their self-confidence. This ensures active participation of all the students, while promoting thinking and originality.

Bihar STET Paper 1 Mathematics Mock Test - 4 - Question 27
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The instructions provided by the teacher must be based on a child's
Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 4 - Question 27

The instructions of a teacher must be based on the child's abilities, aptitude and interest. His ability to grasp and apply things, his natural ability to justify learning and his interest to learn a particular thing could decide the teaching strategies, as the education these days has become more child-centered. The teacher must be aware of the child's abilities, aptitude, and interest, which is possible only through proper evaluation.

Bihar STET Paper 1 Mathematics Mock Test - 4 - Question 28
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With whom has the Government of India signed a loan agreement to strengthen the Fintech eco system in India?
Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 4 - Question 28

Government of India and ADB have signed a $23 million loan agreement to strengthen the fintech ecosystem in India. Under this, an International Fintech Institute (IFI) will be established to strengthen fintech education, boost start-up success rate and promote fintech research and innovation.

Bihar STET Paper 1 Mathematics Mock Test - 4 - Question 29
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The state having the highest rainfall by North-East monsoon is_______________.
Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 4 - Question 29

The correct answer is Option(3).i.e.Tamil Nadu.

Key Points:

  • The state has the highest rainfall by North-East monsoon in Tamil Nadu. 
  • Nort-East Monsoon: 
    • The north-east monsoon, generally known as a monsoon of winter which blows from the land towards the sea and south-west monsoon is just the opposite, known as a monsoon of summer which blows from sea to land.
    • The North-East monsoon usually occurs within October to March, although it may change every year. 

 North-east monsoons are called as retreating monsoons. 

Bihar STET Paper 1 Mathematics Mock Test - 4 - Question 30
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If a(17) exceeds it’s a(10) by 7. The d is:
Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 4 - Question 30

for a given AP, the Nth term is:
a(n) = a + (n-1) x d
a(17) = a + (17−1) x d
a(17) = a + 16 x d
a(10) = a+9(d)
a(17) – a(10) = 7
(a + 16 x d) − (a + 9 x d) = 7
7 x d = 7
d = 1

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