Bihar STET Paper 2 Chemistry Mock Test - 3 - Bihar PGT/TGT/PRT MCQ

as oxygen is more electronegative than Cl,Br and I. So they have positive oxidation state.

Crystalline compounds are those in which particles/molecules are arranged in proper order as in ice particles/water molecules are arranged in a cage-like ordered manner so this ordered structure is called a crystalline compound.

Ligand which can ligate through two different atoms is called ambidentate ligand. NO₂^- ion can coordinate either through nitrogen or through oxygen to a central metal atom/ion.

Hence, ligand show linkage isomerism, e.g. the complex [Co(NH₃)₅(NO₂)]CI₂ which is obtained as the red form, in which the nitrite ligand is bound through oxygen (—ONO) and as the yellow form, in which the nitrite ligand is bound through nitrogen (— NO₂). 

On moving down a group since the number of valence electrons remains the same, all elements exhibit same valence.

The angular momentum (mvr) of electron in nth orbit is equal to nh/2π
For the electron in 5th orbit

If FeCl₃ is added to excess of hot water, a positively charged sol of hydrated ferric oxide is formed due to adsorption of Fe³⁺ ions.
Ferric hydroxide is a negative sol,FeCl₃ electrolyte will coagulate the most.

The correct answer is Option A.
n-Heptane is non-polar and ethanol is polar. Hence the mixture formed by these two liquids is non-ideal. The stronger forces of attraction between n-heptane-n-heptane and ethanol-ethanol are replaced by weaker forces of attraction between n-heptane-ethanol in the solution. Therefore the escaping tendency of the liquid molecules into the vapour phase increases. This will increase the vapour pressure more than expected from Raoult's law. This is a positive deviation. 
Hence, the correct option is B

∆p×∆x = h/4π
Or ∆v = h/4π∆xm      (since p = mv)
=6.6×10^-34Js/4×3.14×25×10^-3kg ×10^-5 
by solving this your answer is 2.1×10^-28

As per IUPAC nomenclature, 0 – nil, 1 – un, 2 – bi, 3 – tri, 4 – quad, 5 – pent, 6 – hex, 7 – sept, 8 – oct and 9 – enn. Here it’s 109 so 1 – un, 0 – nil and 9 – enn, combining them its unnilennium (adding “-ium” after it).

Answer:

Given

Density of water (ρ) = 1g/cm³

Molar mass of water (M) = 18 g/mol

∴ Molar volume (Vm) = M/ρ

Vm = 18 cm³/mol

∴ Volume of 1 molecule of water = V_m/N_A

Where N_A is Avogadro number

Volume of 1 molecule of water = 18/(6.022 × 10²³)

Volume of 1 molecule of water = 2.989 × 10^-23 ≈ 3 × 10^-23.

BeCl₂ + LiAlH⁴ give 2BeH₂ + LiCl and AlCl₃
However, other elements of group 2 combine with hydrogen upon heating to form MH₂

By Fajans’ rule,
Smaller the size of cation, larger the size of anion, larger the charge, then larger the polarising power, larger the covalent nature, means low melting point.
Smaller the ionic nature, means low melting point 


Hence, most stable is LiF.

Squaring on both sides 



⇒
⇒
⇒
=> 10 bar approximately

Hydrides are classified into three major groups, depending on what elements the hydrogen bonds to. The three major groups are covalent, ionic, and metallic hydrides. Formally, hydride is known as the negative ion of a hydrogen, H-, also called a hydride ion.

w₁| = 20.0 g

m₁ = 11x 12 + 8 x 1 + 2 x 16 = 172 g mol^-1  w₂ = 50.0 g 

The correct answer is option C
1,4-Dimethylcyclohexane consists of two diastereomeric stereoisomers, although, according to the n2 rule, four stereoisomers should be expected due to the fact that 1,4-dimethylcyclohexane contains two asymmetric carbons.

KCI is an ionic compound. Force of attraction (F) between K+


Greater the value of D, smaller the value of F, hence larger the solubility.
Note D for CH₃OCH₃ is least out of given solvents, thus solubility is minimum.

The greenhouse effect is where heat energy is trapped by the atmosphere

Free radical bromination occur. Preferably at highest degree carbon where most stable free radical is formed.

Δ_rH=Δ_rH_(product)-ΔrH_(reactant)
=3×-393+81+3×110-9.7
=-777.7kJ
ΔH = ΔU+Δn_gRT
AS Δn_g = 0, ΔH = ΔU
So, ΔU = -777.7 kJ

The reaction is as follow:-
Ca(HCO₃)₂(s)⇌CaO(s) + 2CO₂ (g) + H₂O(g)
At 25° C H₂O goes in liquid state
Kp = (PCaO)1×(PCO₂)₂
(PCa(HCO₃)₂)
Since, Ca(HCO₃)₂, CaO and H₂O are not in gaseous state, so their partial pressure is taken 1.
Putting all values, we have
36 = (PCO₂)₂ 
Or PCO₂ = 6 atm

In non-polar molecular solids, molecules are held by weak dispersion forces or London forces.

Additional Information:

• Non-polar molecules are composed of atoms that have a similar value of electronegativity.
• H₂, Cl₂ and I₂ are some of the typical examples.
• In non-polar Molecular solids, the comprised atoms or molecules are held together by weak dispersion forces or London forces.
• They are soft and non-conductors of electricity.
• They have low melting points and usually exist in a liquid or gaseous state at room temperature and pressure.

Mr. Rathore uses a lot of audio-visual aids while teaching. The main reason for doing so is to take care of the requirements of all the children. Audio-visual aids make the learning permanent. They stimulate both aural and visual senses of children. Some children understand better on observation i.e. visual, whereas other students understand better on aural stimulation. Thus, requirements of all the students are taken care of.

The term used interchangeably with 'Motivation' is 'Need'. 
Motivation is a term that means the motive behind something. It means a person wants something, has a desire for something, wants to avoid something, and wants to escape from something. Having a desire for something is related to need. When we need something, then only a desire creates to have that thing.
Thus, this is the correct answer.

The correct answer is Odisha.

Key Points

• The Tropic of Cancer is an imaginary line north from the Equator at an angle of 23.50 degrees.
• Tropic of Cancer passes through 16 countries, 3 continents, and 6 water bodies.
• It passes through 8 Indian states.
  

Additional Information

IIT Bombay is ranked 45th globally in engineering according to the QS World University Rankings 2024, highlighting its excellence in the field and its leading position in South Asia.

Almost 70% of Botswana territory comprises the Kalahari Desert.