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Bihar STET Paper 2 Physics Mock Test - 8 - Bihar PGT/TGT/PRT MCQ


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30 Questions MCQ Test Bihar STET Mock Test Series 2024 - Bihar STET Paper 2 Physics Mock Test - 8

Bihar STET Paper 2 Physics Mock Test - 8 for Bihar PGT/TGT/PRT 2024 is part of Bihar STET Mock Test Series 2024 preparation. The Bihar STET Paper 2 Physics Mock Test - 8 questions and answers have been prepared according to the Bihar PGT/TGT/PRT exam syllabus.The Bihar STET Paper 2 Physics Mock Test - 8 MCQs are made for Bihar PGT/TGT/PRT 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Bihar STET Paper 2 Physics Mock Test - 8 below.
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Bihar STET Paper 2 Physics Mock Test - 8 - Question 1

Physical quantities are:

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 8 - Question 1
  • A physical quantity is a physical property of a phenomenon, body, or substance, that can be quantified by measurement.
  • A physical quantity can be expressed as the combination of a magnitude expressed by a number – usually a real number – and a unit.
  • All these given above can be expressed as explained so these are physical quantity.
Bihar STET Paper 2 Physics Mock Test - 8 - Question 2

A point source of light is placed in front of a plane mirror.

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 8 - Question 2

Plane mirror always forms a virtual image of the real object for all the rays emitted by the object. So, when a point source of light is placed in front of a  plane mirror, all the reflected rays meet at a point when produced backward.
Option A is correct.

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Bihar STET Paper 2 Physics Mock Test - 8 - Question 3

A particle is projected upward from the surface of earth (radius = R) with a speed equal to the orbital speed of a satellite near the earth’s surface. The height to which it would rise is

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 8 - Question 3

  (orbital speed υ0 of a satellite)

Near the earth’s surface is equal to 1/√2
times the escape velocity of a particle on earth’s surface) Now from conservation of mechanical energy: Decrease in kinetic energy = increase in potential energy

Bihar STET Paper 2 Physics Mock Test - 8 - Question 4

When is the work done by a conservative force equal to zero?

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 8 - Question 4

The work done by a conservative force is equal to zero when the force is applied perpendicular to the displacement. In this case, the force acts against the direction of motion, resulting in negative work done. As conservative forces are path-independent, the negative work done cancels out the positive work done in other parts of the path, resulting in a net work of zero.

*Multiple options can be correct
Bihar STET Paper 2 Physics Mock Test - 8 - Question 5

In a thin rectangular metallic strip a constant current I flows along the positive x-direction, as shown in the figure. The length, width and thickness of the strip are l, w and d, respectively.A uniform magnetic field  is applied on the strip along the positive y-direction. Due to this, the charge carriers experience a net deflection along the z-direction. This results in accumulation of charge carriers on the surface PQRS and appearance of equal and opposite charges on the face opposite to PQRS. A potential difference along the z-direction is thus developed. Charge accumulation continues until the magnetic force is balanced by the electric force. The current is assumed to be uniformly distributed on the cross-section of the strip and carried by electrons.

Q.7. Consider two different metallic strips (1 and 2) of same dimensions (length l, width w and thickness d) with carrier densities n1 and n2, respectively. Strip 1 is placed in magnetic field B1 and strip 2 is placed in magnetic field B2, both along positive y-directions. Then V1 and V2 are the potential differences developed between K and M in strips 1 and 2, respectively. Assuming that the current I is the same for both the strips, the correct option(s) is(are)

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 8 - Question 5

Here

A and C are the correct options.

Bihar STET Paper 2 Physics Mock Test - 8 - Question 6

Value of gas constant, R for one mole of a gas is independent of the

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 8 - Question 6

We know that PV=nRT also PM=dRT
So in the equation The value of R depends on P , V , n , T , d , M
except atomicity 
 so the ans is A

Bihar STET Paper 2 Physics Mock Test - 8 - Question 7

which of the following features of atomic structure determine whether an element is diamagnetic or paramagnetic

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 8 - Question 7

Spin and Orbital angular momentum arise due to the presence of unpaired electrons. If there are unpaired electrons, these momenta will be there otherwise not.

Bihar STET Paper 2 Physics Mock Test - 8 - Question 8

A boy playing on the roof of a 10 m high building throws a ball with a speed of 10 m/s at an angle of 30° with the horizontal. How far from the throwing point will the ball be at the height of 10 m from the ground? [g = 10 m/s2, sin 30° = 1/2, cos 30° = √3/2]   

[AIEEE 2003]

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 8 - Question 8

We have to simply calculate the range of the projectile.
► R = u2sin2θ/g
► R = (10)2 * sin (2 * 30º) / 10 
► R = 10 * (√3/2) = 8.66 m 

Bihar STET Paper 2 Physics Mock Test - 8 - Question 9

Angular momentum of the particle rotating with a central force is constant due to

[AIEEE 2007]

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 8 - Question 9

By law of conservation of angular momentum, in the absence of external torque angular momentum is conserved.
For angular momentum to be constant
τ = 0
Central force: zero torque

Bihar STET Paper 2 Physics Mock Test - 8 - Question 10

 If momentum (P), area (A) and time (T) are taken to be fundamental quantities, then energy has the dimensional formula 

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 8 - Question 10

[E] = [F][d]
= [P/T][A]½ 
[E] = P1A½T-1

Bihar STET Paper 2 Physics Mock Test - 8 - Question 11

In the  circuit P≠R , the reading of the galvanometer is same with switch S open or closed. Then

 

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 8 - Question 11

Since the opening or closing the switch does not affect the current through G, it means that in both the cases there is no current passing through S. Thus potential at A is equal to potential at B and it is the case of balanced wheatstone bridge..

IP = IQ and IR = IG

Bihar STET Paper 2 Physics Mock Test - 8 - Question 12

Capacitor preferred when there is a high frequency in the circuits is ______

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 8 - Question 12

Mica capacitors are preferred for high frequency circuits because they have low ohmic losses and less reactance.

Bihar STET Paper 2 Physics Mock Test - 8 - Question 13

Two moles of an ideal gas (γ=1.4) expands slowly and adiabatically from a pressure of 5.00 atm and a volume of 12.0 L to a final volume of 30.0 L. What is the final pressure of the gas?

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 8 - Question 13

Bihar STET Paper 2 Physics Mock Test - 8 - Question 14

Which of the following is not an application of eddy currents?

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 8 - Question 14

Although eddy currents are undesirable, still they find applications in the following devices:

  • Induction furnaces
  • Electromagnetic damping
  • Electric brakes
  • Speedometers
  • Induction motor
  • Electromagnetic shielding
  • Energy meters
Bihar STET Paper 2 Physics Mock Test - 8 - Question 15

The only component that dissipates energy in ac circuit is:

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 8 - Question 15

The only component that dissipates energy in ac circuit is the resistor because  Pure Inductive and pure capacitive circuits have no power loss.

Bihar STET Paper 2 Physics Mock Test - 8 - Question 16

The density of mercury is 13600 kg m-3. Its value of CGS system will be :

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 8 - Question 16

We know that density of Hg = 13600 kg/m.m.m
= 13600 x 1000 g / 100cm x 100cm x 100cm
= 13.6 g/cm.cm.cm

Bihar STET Paper 2 Physics Mock Test - 8 - Question 17

Two particles of equal masses have velocities    First particle has an acceleration    while the acceleration of the other particle is zero. The centre of mass of the two particles moves in a path of  

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 8 - Question 17



Bihar STET Paper 2 Physics Mock Test - 8 - Question 18

Two equal positive charges q1 = q2 = 2.0 μC. are located at x = 0, y = 0.3 and x = 0 and y = -0.3 m respectively. What are the magnitude and direction of the total electric force (expressed in Newton and degrees counter clockwise w.r.t  x - axis) that q1 and q2 exert on a third charge Q = 4.0 μC  at x =0.4 and y = 0 m

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 8 - Question 18

Side AP =  = 0.5m Electric Field due to charge at A on point P = Elecric Field due to charge at B on 

point P 

Where So force due to this field on charge P

F = qE =  4 x 10-6 x 115.2 x 103 F = 0.46N

Since this force in the direction of positive x axis so angle  = 0o

Bihar STET Paper 2 Physics Mock Test - 8 - Question 19

If a machine is lubricated with oil

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 8 - Question 19

When a machine is lubricated with oil friction decreases. Hence the mechanical efficiency of the machine increases.

Bihar STET Paper 2 Physics Mock Test - 8 - Question 20

When is the angle of dip at a place equal to 45o?

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 8 - Question 20

Yes, the angle of dip at a place is equal to 45o, when the vertical and horizontal components of earth’s magnetic field are equal. In this case ➔ δ=45o

So, BV=BH.

Bihar STET Paper 2 Physics Mock Test - 8 - Question 21

The temperature range upto which Newton’s law of cooling holds good

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 8 - Question 21

Newton’s law of cooling is to be used at temperatures around room temperature.

Bihar STET Paper 2 Physics Mock Test - 8 - Question 22

The amplitude of the magnetic field part of a harmonic electromagnetic wave in vacuum is B0= 510 nT. Amplitude of the electric field part of the wave is

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 8 - Question 22

Magnetic field part of a harmonic electromagnetic wave in vacuum
,B0​=510×10−9T
Speed of light,
C=3×108m/s
E=cBo​=153N/C

Bihar STET Paper 2 Physics Mock Test - 8 - Question 23
Which of the following can be considered as an activity based method to teach the concept of probability in middle school?
Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 8 - Question 23

By physically conducting experiments and recording outcomes, students actively participate in the learning process, making it more meaningful and memorable.

Key Points

  • Through this hands-on approach, students develop a concrete understanding of probability concepts like sample space, equally likely outcomes, and relative frequency.
  • They observe patterns and begin to grasp the concept of probability intuitively.
  • This activity also encourages critical thinking as students analyze the data they collect and draw conclusions about the likelihood of different outcomes.
  • Moreover, the activity promotes teamwork and communication skills as students discuss their findings and observations with their peers.
  • It creates an interactive and dynamic learning environment, fostering curiosity and a deeper appreciation for mathematics.

Hence, it can be concluded that Asking students to throw a dice or flip a coin and note down the number of times each possibility occurs is the best approach.

Bihar STET Paper 2 Physics Mock Test - 8 - Question 24

The basis of the project or an activity-based method is going from:

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 8 - Question 24

The teaching method is a way to put theory into practice. It generally describes the pedagogy of children, general principles, and management strategies that are to be used through the whole teaching-learning process. It helps to ease the learning pace of students.

Key Points

The project method or activity-based method is based on learning by doing.

  • These methods make learning realistic and experimental.
  • It aims to make students think independently and is a target-driven activity based on the challenge, fostering success and efficient cooperation.
  • These methods follows the maxims of teaching like known to unknow, seen to unseen, simple to complex, concrete to abstract.
  • Learning by doing and experiencing the consequences of one's own actions. 
  • To enhance the skills and understanding of the learners as they gain knowledge by engaging with the contents and experiences.

Important Point

The whole knowledge travels from known to unknown, concrete to abstract, simple to complex, and from seen to unseen. The same principle is applied in classroom teaching and is the very aim of education at the highest level.

From concrete to abstract:

  • The abstract is confusing, difficult to understand, and subjective. The acquisition of new knowledge may become a simpler task when it is supported with concrete examples, objects, and events.

Hence we can say that the basis of the project or an activity-based method is going from concrete to abstract.

Bihar STET Paper 2 Physics Mock Test - 8 - Question 25

What is the most effective way to discipline a mischievous student?

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 8 - Question 25

Students feel humiliated being criticised by a teacher in front of their peers. So, handling discipline issues without an audience allows for better, more genuine exchanges, since the student responses will not be witnessed by classmates.

Bihar STET Paper 2 Physics Mock Test - 8 - Question 26

The primary duty of the teacher is to

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 8 - Question 26

Teachers play the most crucial role in moulding the behaviour of learners. This shaping of behaviour is achieved through planning and dedication.

The Primary duties of a teacher include:

  • to achieve all-round development of students by guiding the students in their learning process.
  • to provide motivation for learning.
  • to stimulate learners in order to realize their optimum potential.
  • to plan the teaching and learning process to suit the needs of the students.
  • to promote learning by providing a conducive environment.
  • to encourage learners to become active learners.

Although imparting knowledge and values into the students are important duties of a teacher. However all round development of students is the most important and vital duty of a teacher.

Thus, the primary duty of the teacher is to help in all round development of the students.

Bihar STET Paper 2 Physics Mock Test - 8 - Question 27

If the teacher realises that most of the students in her class are weak in studies, she should

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 8 - Question 27

She should keep her pace of teaching slow, while paying extra attention towards the weaker students. It will be beneficial to both weak and intelligent students, and will not cause lack of interest in bright students too.

Bihar STET Paper 2 Physics Mock Test - 8 - Question 28
The chief objective of teaching is
Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 8 - Question 28

Teaching refers to the actions of someone who is trying to assist others to reach their fullest potential in all aspects of development. Teaching would result when the teacher indulges in any activity with the intention that pupils would learn something as a consequence of it. It is the processes meant for bringing about changes in the cognitive structure (structure of knowledge in one’s mind i.e. thinking power) in those who are being taught.

Objectives of Teaching:

  • Developing self-confidence in students.
  • Provide opportunity where the student constructs their knowledge on their own.
  • Addressing the diverse needs of all students.
  • Use various innovative teaching method to encourage them to discover new knowledge. For example, the project method of teaching.
  • Improving life long learning skills in students.
  • Fostering potential of students to grow and bloom.
  • Transmission of new knowledge of facts, concepts, theories, laws, principles

Key Points

  • In the case of classroom instructions, the teacher is concerned about bringing changes in the behaviour of learners and we call that specific objective as behavioural objective. Behavioural objectives are the objectives written in behavioural terms.
  • It explains the change in the state of the behaviour of an individual on completion of a learning activity. So, Stimulate curiosity of students to discover knowledge is one of the chief objectives of Teaching.
Bihar STET Paper 2 Physics Mock Test - 8 - Question 29

Gagan Shakti 2024 exercise, recently conducted by Indian Air Force at which place?

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 8 - Question 29

The Indian Air Force (IAF) is set to conduct ‘Gagan Shakti-2024’, the nation’s largest air military exercise, involving all Air Force stations. Held every five years, it will commence on April 1, 2024, at Pokhran’s field firing range. Approximately 10,000 airmen will participate, with maneuvers spanning the Western and Northern fronts. The Indian Army is aiding logistical support, ensuring synergy across sectors for operational rail mobilization.

Bihar STET Paper 2 Physics Mock Test - 8 - Question 30

How many persons are seated between S and V?

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 8 - Question 30

Q, R, S, T, U, and V are seated in a straight line facing North.

i) S is second to the right of T.

ii) T is second to the right of Q.

iii) R is to the immediate left of Q

iv) R is to the immediate left of Q and is second to the left of V.

Thus we can see there are two persons seating between S and V.

Hence, the correct answer is "Two".

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