For a transistor circuit, VCE when Vin = 0V (in volts).
When Vin = 0V, the transistor is in cut-off (acts like an open switch) and VCE =VCC = 10V.
The correct answer is: 10
For a BJT, the current amplification factor ∝ = 0.9 . This transistor is connected in common emitter configurations. When the base current changes by 0.4 mA, the change in collector current will be (in mA).
The correct answer is: 3.6
A power amplifier gives 150 W output of or an input of 1.5W. The gain in dB is :
= 40 dB
The correct answer is: 40
What is the current gain for a common-base configuration where IE = 4.2 mA and IC = 4.0 mA?
Ie = 4.2ma (Given)
Ic = 4.0ma (Given)
The question follows the common base configuration in the circuit configuration of a bipolar transistor, where the emitter is the input electrode, collector is the output electrode and the base is reference electrode for both input and the output.
Current gain = Ic / Ie =I(out)/I(in)
where, IC=Output Current and IE = Input Current
= 4 / 4.2
Therefore, the current gain for a common-base configuration is 0.95
Figure shows a common emitter amplifier with β = 100. What is the maximum peak to peak input signal (in mV) for which distortion free output may be obtained Assume VBE = 0 rE = 20 Ω
But for maximum peak to peak input signal
The correct answer is: 80
In the following circuit, Tr1 and Tr2 are identical transistors having VBE = 0.7V. The current passing through the transistor Tr2 is (in mA).
5=100x1 + 0.7
The correct answer is: 43
If the transistor amplifier has a gain of 20dB, then the ratio of output to input power is :
The ratio of output to input power is known as power amplification.
The logarithm of the power amplification is represented in bel.
he correct answer is: 100
A common emitter amplifier has voltage gain of 50, an input impedance of 1000Ω and an output impedance of 200Ω. The power gain of the amplifier will be (in dB).
Power gain = Voltage gain x current gain
The correct answer is: 250
The input signal given to a common emitter amplifier having a voltage gain of 20 is Vin = 20 cos (5t + 20°). The corresponding output signal has an amplitude equal to ?
The correct answer is: 400
The feedback ratio of an amplifier, which an amplification of a negative feedback, changes the voltage gain the voltage gain from - 250 to - 100 is (give magnitude only).
The correct answer is: 0.006