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Chemistry - 2019 Past Year Paper

60 Questions MCQ Test IIT JAM Chemistry Past Year Papers | Chemistry - 2019 Past Year Paper

Description

This mock test of Chemistry - 2019 Past Year Paper for IIT JAM helps you for every IIT JAM entrance exam. This contains 60 Multiple Choice Questions for IIT JAM Chemistry - 2019 Past Year Paper (mcq) to study with solutions a complete question bank. The solved questions answers in this Chemistry - 2019 Past Year Paper quiz give you a good mix of easy questions and tough questions. IIT JAM students definitely take this Chemistry - 2019 Past Year Paper exercise for a better result in the exam. You can find other Chemistry - 2019 Past Year Paper extra questions, long questions & short questions for IIT JAM on EduRev as well by searching above.

QUESTION: 1

For a reaction of the type A + B → Products, the unit of the rate constant is mol L^–1 s^–1. The overall order of the reaction is ______.

A.
0
B.
1
C.
2
D.
3

Solution:

Unit of k = (mole/L)^1-n s^-1
On Substituting, n=0
⇒ The unit of k = mol L^–1 s^–1
i.e. same as given.

Thus, the given reaction is a zero-order reaction or the overall order of the reaction is 0.

QUESTION: 2

The thermodynamic criterion for spontaneity of a process in a system under constant volume and temperature and in the absence of any work other than expansion work (if any) is:

A.
Change in entropy is positive.
B.
Change in enthalpy is negative.
C.
Change in Helmholtz free energy is negative.
D.
Change in Gibbs free energy is negative.

Solution:

QUESTION: 3

The number of vibrational mode(s) of a carbon dioxide molecule that can be detected using infrared spectroscopy is ______.

A.
1
B.
2
C.
3
D.
4

Solution:

CO₂ molecule is linear so its vibrational degree of freedom is (3n - 5)
= (3 * 3 - 5) = 4
1 is symmetrical stretching means IR inactive and 3 is (symmetrical +bending) means IR active.
Hence, the number of vibrational mode(s) of a carbon dioxide molecule that can be detected using infrared spectroscopy is 3.

QUESTION: 4

For three non-coplanar vectors a, b and c, the expression a ∙ (b × c) can be written as:

A.
(a × b) ∙ c
B.
(a × b) ∙ (a × c)
C.
(a ∙ b) × (a ∙ c)
D.
(a ∙ b) × c

Solution:

(b×c) =b. (c×a) =-c.(a×b)=(a×b).c

So, (A) is the correct option.

QUESTION: 5

The correct trend in the bond order is:

Solution:

Bond order for the following:
(i) O₂⁻ = 1.5
(ii) O₂⁺ = 2.5
(iii) O₂^2- = 1

∴ The correct trend will be:

QUESTION: 6

The correct option for the metal ion present in the active site of myoglobin, hemocyanin, and vitamin B12, respectively, are:

A.
Iron, Iron, and Zinc
B.
Molybdenum, Iron, and Copper
C.
Iron, Copper, and Cobalt
D.
Molybdenum, Copper, and Cobalt

Solution:

QUESTION: 7

The correct order of wavelength (λ_max) of the halide to metal charge-transfer band of [Co(NH₃)₅Cl]²⁺ (I), [Co(NH₃)5Br]²⁺ (II) and [Co(NH₃)₅I]²⁺ (III), is

A.
III < II < I
B.
I < II < III
C.
II < III < I
D.
I < III < II

Solution:

Down the group, Electronegativity decreases from Cl to I.
So, in III less energy is required for the electron in Iodine to transfer, than that of Chlorine.
As energy decreases, wavelength(λ_max) increases from Cl to I.

QUESTION: 8

The correct option for the major products of the following reaction is

Solution:

This is the reaction named by favorskii rearrangement in which base abstracts the proton from left carbon of carbonyl group and withdraws the leaving group Cl by rearrangement and makes ester.

QUESTION: 9

The major product formed in the following reaction is

Solution:

QUESTION: 10

The complementary strand for the following single strand of DNA is:

Solution:

In DNA, Adenine (A) pairs with Thymine (T) and Guanine (G) pairs with Cytosine (C).
Hence, on replication of DNA in M phase, complementary nucleotides for each base pair will be added as follows:
(i) A - T
(ii) T - A
(iii) G - C
(iv) C - G
Since replication occurs in 5'-3' direction, so the complementary strand will be formed in 3'-5' direction.
Hence the sequence of complementary strand formed upon replication will be:

QUESTION: 11

The function f(x) x e-x² has a minimum at

A.
x = √2
B.
x = −√2
C.
D.

Solution:

QUESTION: 12

The correct option for the number of bending modes of vibration in each of H₂O, CS₂ and SO₂ molecules, respectively, is

A.
1, 2 and 2
B.
2, 2 and 1
C.
2, 1, and 2
D.
1, 2 and 1

Solution:

QUESTION: 13

The total number of degrees of freedom of an HBr molecule that is constrained to translate along a straight line but does not have any constraints for its rotation and vibration is:

A.
6
B.
5
C.
4
D.
3

Solution:

The total degree of freedom of a molecule is 3N where N refers to its atomicity.
Ideally, it should be 6 (∵ HBr is a diatomic linear molecule).
But it is constrained to move along a straight line (i.e. assuming that it can move only along one axis).
Therefore, the total translational degree of freedom would be 1.
Hence, overall it would be 4.

QUESTION: 14

According to the kinetic theory of gases, the ratio of the root mean square velocity of molecular oxygen and molecular hydrogen at 300 K is:

A.
1: 1
B.
1: 2√2
C.
1: 4
D.
1: 16

Solution:

Vrms_oxygen/Vrms_hydrogen = √M_hydrogen/√M_oxygen
∵ Vrms is inversely proportional to the molar mass

Vrms_oxygen/Vrms_hydrogen = √1/√16 = 1/4

QUESTION: 15

The half-life of the chemical reaction, A → Product, for initial reactant concentrations of 0.1 and 0.4 mol L^–1 are 200 and 50 s, respectively. The order of the reaction is:

A.
0
B.
1
C.
2
D.
3

Solution:

QUESTION: 16

The ratio of the nearest neighbor atomic distances in body-centered cubic (bcc) and facecentered cubic (fcc) crystals with the same unit cell edge length is

Solution:

In BCC, the nearest atom from one corner is at the body center, at a distance of √(3a/2).
In FCC, the nearest atom from one corner is at the face center at a distance of √(2a/2).
The ratio would be √(3/2).

QUESTION: 17

The correct trend in the rate of substitution of Cl- by pyridine in the following complexes is

A.
III < II < I < IV
B.
II < III < I < IV
C.
I < II < III < IV
D.
III < II < IV < I

Solution:

QUESTION: 18

In the qualitative inorganic analysis of metal ions, the ion which precipitates as sulfide in the presence of H₂S in warm dilute HCl is:

A.
Cr³⁺
B.
Al³⁺
C.
Co²⁺
D.
Bi³⁺

Solution:

Group II → Bi³⁺
Group III A → Al³⁺, Cr³⁺
Group III B → Co²⁺
Second group cations are precipitated as sulphides because of their low solubility products whereas sulphides of other metals remain in solution because of their high solubility products.
HCl acts as a source of H⁺ which decrease the concentration of S²⁻ ion that exceeds only the solubility products of the metal sulphide of the II^nd group.

QUESTION: 19

The correct statement regarding the observed magnetic properties of NO, O₂, B₂, and C₂ in their ground state is:

A.
NO, B₂, and C₂ are paramagnetic.
B.
B₂, O₂and NO are paramagnetic.
C.
O₂, C₂ and NO are paramagnetic.
D.
O₂, B₂ and C₂ are paramagnetic.

Solution:

In B_2, there are two unpaired electrons in the π bonding orbital.
In O₂, there are also two π electrons in antibonding orbitals.
In NO, there is one unpaired electron in π* antibonding orbital
Since the paramagnetic nature is based on the presence of unpaired electrons.
Thus, B₂, O_2,and NO are paramagnetic.

QUESTION: 20

The observed magnetic moments of octahedral Mn³⁺, Fe³⁺ and Co³⁺ complexes are 4.95, 6.06 and 0.00 BM, respectively. The correct option for the electronic configuration of Mn³⁺, Fe³⁺ and Co³⁺ metal ions in these complexes, respectively, is

Solution:

QUESTION: 21

Among the following compounds, the one having the lowest boiling point is

A.
SnCl₄
B.
GeCl₄
C.
SiCl₄
D.
CCl₄

Solution:

QUESTION: 22

The correct option having one complex from each of the following pairs which is more reactive towards the oxidative addition reaction by hydrogen molecule is
Pair 1: IrCl(PMe₃)₃ (I) and IrCl(CO)(PMe₃)₂ (II)
Pair 2: IrCl(CO)(PPh₃)₂ (III) and IrCl₃(PPh₃) (IV)

A.
(I) and (III)
B.
(I) and (IV)
C.
(II) and (III)
D.
(II) and (IV)

Solution:

QUESTION: 23

Among the following, the correct statement is

A.
The density follows the order, Cs > Rb > Li > Na.
B.
The solubility in water follows the order, Cs₂CO₃ > K₂CO₃ > Na₂CO₃ > Li₂CO₃.
C.
The first ionization potential follows the order, Li > K > Na > Cs.
D.
The melting point follows the order, MgCl₂ > BeCl₂ > CaCl₂ > SrCl₂.

Solution:

QUESTION: 24

The major product of the following reaction is:

Solution:

QUESTION: 25

In ¹H NMR spectrum of the given molecule, the correct order of chemical shifts of the labelled protons (H^X, H^Y, H^Z) is

A.
H^Z > H^X > H^Y
B.
H^Z > H^Y > H^X
C.
H^X > H^Y > H^Z
D.
H^Y > H^X > H^Z

Solution:

QUESTION: 26

In the following reaction of (D)-Glucose, a product P is formed.
Among the following compounds, the one which will give the same product (P) under identical reaction conditions is

Solution:

QUESTION: 27

The major product of the following reaction is

Solution:

QUESTION: 28

The correct option for the product(s) of the following reaction is

Solution:

QUESTION: 29

The increasing order of acidity of the given molecules in aqueous media is:

A.
IV < I < II < III
B.
II < I < IV < III
C.
II < IV < I < III
D.
IV < II < I < III

Solution:

QUESTION: 30

The compound formed upon subjecting an aliphatic amine to Lassaigne’s test is

A.
NaNH₂
B.
NaNO₂
C.
NaCN
D.
NaN₃

Solution:

*Multiple options can be correct

QUESTION: 31

The eigenvalue(s) of the matrix is/are:

A.
–1
B.
1
C.
2
D.
3

Solution:

Product of Eigenvalues = det A
Sum of Eigenvalues = trace A

Let a,b be the Eigenvalues of A.
Therefore,
a+b = 2
a.b = -3
On solving the two equations,
We get -1 and 3

*Multiple options can be correct

QUESTION: 32

The unit of the constant ‘a’ in van der Waals equation of state of a real gas can be expressed as

A.
m⁶ Pa mol^-2
B.
m⁶ J mol^-2
C.
m³ Pa mol^-2
D.
m³ J mol^-2

Solution:

*Multiple options can be correct

QUESTION: 33

Among the following, microwave active molecule(s) is/are:

A.
trans-dichloroethene
B.
1,2-dinitrobenzene
C.
3-methylphenol
D.
para-aminophenol

Solution:

Microwave active molecules are those molecules that have permanent dipoles.
If we look at the structure of trans-dichloro-ethene, it has dipole moment 0 due to Cl attached opposite side.
Whereas all others are polar draw the structures.

*Multiple options can be correct

QUESTION: 34

The true statement(s) regarding the brown ring test carried out in the laboratory for the detection of NO₃- is/are

A.
Brown ring is due to the formation of the iron nitrosyl complex.
B.
Concentrated nitric acid is used for the test.
C.
The complex formed in the reaction is [Fe(CN)5NO]^2-.
D.
The brown colored complex is paramagnetic in nature.

Solution:

Complex formed is [Fe(H₂O)₅NO]SO₄.
Concentrated Sulphuric acid is used.
Brown ring is formed at the junction of two layers.
Brown coloured complex is paramagnetic.

*Multiple options can be correct

QUESTION: 35

The true statement(s) regarding the carbonic anhydrase enzyme is/are

A.
It is involved in peptide bond cleavage.
B.
Redox inactive Zn²⁺ ion is involved in the catalytic activity of this enzyme.
C.
Activated M-OH₂ (M = metal ion) acts as the nucleophile in the enzyme.
D.
The metal ion is coordinated to the side chain of histidine residues.

Solution:

*Multiple options can be correct

QUESTION: 36

The correct statement(s) about NO₂, NO₂⁺ and CO₂ is /are:

A.
Both NO₂ and CO₂ are paramagnetic.
B.
NO₂ is paramagnetic and NO₂⁺ is diamagnetic
C.
Both CO₂ and NO₂⁺ have linear geometry.
D.
CO₂ and NO₂⁺ are isoelectronic.

Solution:

NO₂⁺→ sp hybridization, linear, no unpaired electrons, Diamagnetic.
NO₂→ sp² hybridization, V-shape, one unpaired electron, Paramagnetic.
CO₂→ sp hybridization, linear, no unpaired electrons, Diamagnetic.
CO₂and NO₂⁺ have 22 e^- each, therefore they are isoelectronic.

*Multiple options can be correct

QUESTION: 37

The compound(s) formed as intermediate(s) in the following reaction sequence is/are

Solution:

*Multiple options can be correct

QUESTION: 38

The correct statement(s) among the following is/are

A.
Secondary structure of a polypeptide describes the number and type of amino acid residues.
B.
Uracil is a pyrimidine nucleobase.
C.
Natural fatty acids have odd number of carbon atoms.
D.
Reaction of (D)-glucose with Ca(OH)₂ gives a product mixture containing (D)-fructose, (D)-mannose, and (D)-glucose.

Solution:

*Multiple options can be correct

QUESTION: 39

The diastereomeric pair(s) among the following option(s) is/are

Solution:

*Multiple options can be correct

QUESTION: 40

The reaction(s) that result(s) in the formation of aromatic species is/are