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DSSSB PGT Physics Mock Test - 1 - DSSSB TGT/PGT/PRT MCQ


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30 Questions MCQ Test DSSSB PGT Mock Test Series 2025 - DSSSB PGT Physics Mock Test - 1

DSSSB PGT Physics Mock Test - 1 for DSSSB TGT/PGT/PRT 2025 is part of DSSSB PGT Mock Test Series 2025 preparation. The DSSSB PGT Physics Mock Test - 1 questions and answers have been prepared according to the DSSSB TGT/PGT/PRT exam syllabus.The DSSSB PGT Physics Mock Test - 1 MCQs are made for DSSSB TGT/PGT/PRT 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for DSSSB PGT Physics Mock Test - 1 below.
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DSSSB PGT Physics Mock Test - 1 - Question 1

Light year is the unit of

Detailed Solution for DSSSB PGT Physics Mock Test - 1 - Question 1

The light-year is a unit of length used to express astronomical distances and measures about 9.46 trillion kilometres or 5.88 trillion miles. As defined by the International Astronomical Union, a light-year is the distance that light travels in vacuum in one Julian year. 

DSSSB PGT Physics Mock Test - 1 - Question 2

A ball whose kinetic energy is E is projected at an angle of 45° to the horizontal. The kinetic energy of the ball at the highest point of its flight will be:         

[AIEEE 2002]               

Detailed Solution for DSSSB PGT Physics Mock Test - 1 - Question 2

At the highest point of its flight, the vertical component of velocity is zero and the only horizontal component is left which is ux = u cosθ
Given θ = 450

 

 

DSSSB PGT Physics Mock Test - 1 - Question 3

Two forces are such that the sum of their magnitudes is 18 N and their resultant which has magnitude 12 N, is perpendicular to the smaller force. Then the magnitudes of the forces are

Detailed Solution for DSSSB PGT Physics Mock Test - 1 - Question 3

Solving Eqs. (i), (ii) and (iii), A = 5N, B = 13N

DSSSB PGT Physics Mock Test - 1 - Question 4

A bomb of mass 4 kg explodes in air into two pieces of masses 3 kg and 1 kg. The smaller mass goes at a speed of 90 m/s. The total energy imparted to two fragments is.

Detailed Solution for DSSSB PGT Physics Mock Test - 1 - Question 4

By conservation of momentum we get the speed of the bigger part let say, v = 1 x90 / 3
Hence we get v = 30
Thus the total KE of the system after collision is ½ (3 X 900 + 1 X 8100)
Thus KE = ½ (10800) = 5400
Now  if we apply WET to the system, as no external force has acted upon it, we get
W = ΔKE
= 5400 - 0
= 5.4 kJ

DSSSB PGT Physics Mock Test - 1 - Question 5

A square plate and a circular plate made up of same material are placed touching each other on a horizontal table. If the side length of square plate is equal to diameter of the circular plate, then the centre of mass of the combination will be  

Detailed Solution for DSSSB PGT Physics Mock Test - 1 - Question 5
Let m be the mass per unit area.

DSSSB PGT Physics Mock Test - 1 - Question 6

A person standing on a rotating platform with his hands lowered outstretches his arms. The angular momentum of the person

Detailed Solution for DSSSB PGT Physics Mock Test - 1 - Question 6

Yes because there is absence of any external force or torque so angular momentum will remain constant
here outstretching the hands means internal forces are working.. so moment of inertia increases in this case and to make angular momentum constant when angular velocity decreases.

DSSSB PGT Physics Mock Test - 1 - Question 7

The mass of an electron is  9 x 10-31 kg. It revolves around the nucleus of an atom in a circular orbit of radius 4.5 Å, with a speed of  8 x 105m/s. The angular momentum of electron is

Detailed Solution for DSSSB PGT Physics Mock Test - 1 - Question 7

M=9x10-31Kg,r=4.5x10-10
V=8x105m/s
L=mvr
  =9x10-31 x 4.5 x 10-10 x 8 x 10= 3.24 x 10-34 kgm2s-1

DSSSB PGT Physics Mock Test - 1 - Question 8

The gravitational force on a body of mass m at a distance r from the centre of the Earth for r < R, where R is the radius of Earth, is proportional to:

Detailed Solution for DSSSB PGT Physics Mock Test - 1 - Question 8

We know, the gravitational force 
,
This is valid when R is the centre to centre distance between the two masses M and m.
At a distance r < R, the mass of Earth cannot be taken as M.

The new mass (M'):
The mass of earth will be contained for a radius r. Let us assume that the mean density of the earth is ρ and that earth is a sphere with a radius equal to the distance r. We know, mass = density × volume

Therefore the gravitational force, F = 

Hence the gravitational force, F ∝ r

DSSSB PGT Physics Mock Test - 1 - Question 9

The earth attracts the moon with a gravitational force of 1020 N. Then the moon attracts the earth with the gravitational force of

Detailed Solution for DSSSB PGT Physics Mock Test - 1 - Question 9

According to Newton's Third Law of Motion, every action has an equal and opposite reaction. This law applies to the gravitational forces between two bodies as well.

The gravitational force with which the Earth attracts the Moon is equal to the gravitational force with which the Moon attracts the Earth. This is because the forces are action and reaction pairs, as described by Newton's Third Law.

Therefore, if the Earth attracts the Moon with a gravitational force of 1020 N, then the Moon attracts the Earth with the same gravitational force of 1020 N.

Hence, the correct answer is b. 1020 N.

DSSSB PGT Physics Mock Test - 1 - Question 10

Heat is supplied to the gas, but its internal energy does not increase. What is the process involved?

Detailed Solution for DSSSB PGT Physics Mock Test - 1 - Question 10

Solution:

  • The first law of thermodynamics states: dQ = dU + dW.
  • In an isothermal process, the temperature remains constant.
  • This means the change in internal energy (dU) is zero because internal energy is a function of temperature.
  • Thus, all the heat supplied (dQ) is used to do work (dW).
  • According to the second law of thermodynamics, not all heat can be converted to work, but in this ideal case, internal energy does not increase.
DSSSB PGT Physics Mock Test - 1 - Question 11

Which of the following are the extensive variables?

Detailed Solution for DSSSB PGT Physics Mock Test - 1 - Question 11

Extensive variable →H (enthalpy), E (Internal energy) and Mass. Since these variables depend on the amount of substance or volume or size of the system.

DSSSB PGT Physics Mock Test - 1 - Question 12

If the r.m.s speed of oxygen at NTP is x m/s. If the gas is heated at constant pressure till its volume is four fold, what will be its final temperature and r.m.s speed?

Detailed Solution for DSSSB PGT Physics Mock Test - 1 - Question 12


DSSSB PGT Physics Mock Test - 1 - Question 13

The path difference between two waves 
y1= A1 sin wt and y2= A2 cos (wt + f) will be 

Detailed Solution for DSSSB PGT Physics Mock Test - 1 - Question 13

y1 = A1 sin wt

y2 = A2 cos (wt + f)

Now, y2 can be rewritten as A2 sin (wt + f + π/2)

So, the phase difference is f + π/2

Path Difference = (λ/2π)(f + π/2)

Hence, the correct option is b.

DSSSB PGT Physics Mock Test - 1 - Question 14

The resultant amplitude in interference with two coherent source depends upon _

Detailed Solution for DSSSB PGT Physics Mock Test - 1 - Question 14

Two sources are said to be coherent if there always exists a constant phase difference between the waves emitted by these sources. But when the sources are coherent, then the resultant intensity of light at a point will remain constant and so interference fringes will remain stationary.

DSSSB PGT Physics Mock Test - 1 - Question 15

The necessary condition for phenomenon of interference to occur is

Detailed Solution for DSSSB PGT Physics Mock Test - 1 - Question 15

The necessary condition for phenomenon of interference to occur are:
1. There should be two coherent sources.
2. The frequency and amplitude of both the waves should be same.
3. The propagation of waves should be simultaneously and in same direction.
These are the conditions, no explanation.

DSSSB PGT Physics Mock Test - 1 - Question 16

Which one of the following statement regarding electrostatics is wrong ?

Detailed Solution for DSSSB PGT Physics Mock Test - 1 - Question 16

A stationary charge doesn't produce a magnetic field , it only produces an electric field.

DSSSB PGT Physics Mock Test - 1 - Question 17

When the distance between two charged particle is halved, the force between them becomes

Detailed Solution for DSSSB PGT Physics Mock Test - 1 - Question 17

Earlier force between two particles is 
F=kq1​q2​​/ r2
When distance is halved force becomes 
F′= kq1​q2/(r/2)2 ​​=4kq1​q2/r2​​=4F

DSSSB PGT Physics Mock Test - 1 - Question 18

What happens to the capacitance of a parallel plate capacitor when the area of the plates, as well as the distance between them, is halved?

Detailed Solution for DSSSB PGT Physics Mock Test - 1 - Question 18

We know that:
A capacitor consists of two plates of a conductor and a dielectric insulator between them:

Where
C = capacitance in farad
ϵ = Permittivity of dielectric
A = area of plate overlap in square meters
d = distance between plates in meters
If the area of the plates is halved i.e., A/2 and the distance between them is halved i.e., d/2, then new capacitance is:

DSSSB PGT Physics Mock Test - 1 - Question 19

For any charge configuration, equipotential surface through a point is _____to the electric field at that point.

Detailed Solution for DSSSB PGT Physics Mock Test - 1 - Question 19

Equipotential surfaces are surfaces in space where the electric potential is the same at every point. In other words, if you place a charge on an equipotential surface, it will not experience any force due to the electric field created by other charges in the system.

Now, consider a point on an equipotential surface. If the electric field at this point were not perpendicular to the surface, there would be a component of the electric field along the surface. This would mean that there is a potential difference along the surface, which contradicts the definition of an equipotential surface (where the potential is constant along the surface).

Therefore, for any charge configuration, the electric field at a point on an equipotential surface must be perpendicular to the surface. This can be understood intuitively by imagining that if there were a component of the electric field along the surface, charges on the surface would move to regions of higher or lower potential, violating the condition of an equipotential surface

DSSSB PGT Physics Mock Test - 1 - Question 20

The current i in the circuit (see Fig) is

Detailed Solution for DSSSB PGT Physics Mock Test - 1 - Question 20

BC and AC are in series

Now BA and DC are in parallel.

DSSSB PGT Physics Mock Test - 1 - Question 21

Which of the following statements about earth's magnetism is correct

Detailed Solution for DSSSB PGT Physics Mock Test - 1 - Question 21

According to recent researches the magnetic field of earth is considered due to a large bar magnet situated in earth's core.
It is considered that the north pole of this large magnet is situated at the geographical south of earth and vice versa and as the magnetic field due to a bar magnet is from north pole to south pole of the maget thus the earth's magnetic field is considered from geographical south to geographical north which are respectively north and south poles of the bar magnet.

DSSSB PGT Physics Mock Test - 1 - Question 22

In the magnetic meridian of a certain place, the horizontal component of the earth’s magnetic field is 0.26G and the dip angle is 60o. What is the magnetic field of the earth at this location

Detailed Solution for DSSSB PGT Physics Mock Test - 1 - Question 22

The earth's magnetic field is Be​ and its horizontal and vertical components are He​ and Hv​
cosθ= He​​/Be
∴cos60o= (​0.26×10−4​/ Be )T
⇒Be​=(​0.26×10−4)/ (½)​=0.52×10−4T=0.52G

DSSSB PGT Physics Mock Test - 1 - Question 23

electromagnetic induction i.e currents can be induced in coils (Select the best)

Detailed Solution for DSSSB PGT Physics Mock Test - 1 - Question 23

Explanation:for electromagnetic induction magnet and coil both may move but relative motion between must be present

DSSSB PGT Physics Mock Test - 1 - Question 24

Why is the iron core of a transformer made laminated instead of being in one solid piece?

Detailed Solution for DSSSB PGT Physics Mock Test - 1 - Question 24
  • The iron core of a transformer is made of Laminated silicon steel with special insulated coating to limit Eddy current loss.
  • Electrical steel, also called lamination steel is specialty steel tailored to produce certain magnetic properties, such as a small hysteresis area (small energy dissipation per cycle, or low core loss) and high permeability.
DSSSB PGT Physics Mock Test - 1 - Question 25

For a series LCR circuit the input impedance at resonance

Detailed Solution for DSSSB PGT Physics Mock Test - 1 - Question 25

Resonance occurs when XL = XC and the imaginary part of the transfer function is zero. At resonance the impedance of the circuit is equal to the resistance value as Z = R.

DSSSB PGT Physics Mock Test - 1 - Question 26

Ac and dc both can be measured by

Detailed Solution for DSSSB PGT Physics Mock Test - 1 - Question 26

Hotwire instruments are based on the heat Irms2​Rt and/or power Irms2​R producing property of current. Hence it can measure both ac and dc current as both produce heat when passed through a conductor.

DSSSB PGT Physics Mock Test - 1 - Question 27

Light rays from a point object

Detailed Solution for DSSSB PGT Physics Mock Test - 1 - Question 27

Light from each point on a luminous object travels outward in all directions in straight lines. Light travels at very high speeds, but is not instantaneously everywhere. Light from a point object travels indefinitely until it collides with matter in its path to be partially absorbed and reflected.

DSSSB PGT Physics Mock Test - 1 - Question 28

A lens of power + 2.0 D is placed in contact with another lens of power – 1.0 D. The combination will behave like

Detailed Solution for DSSSB PGT Physics Mock Test - 1 - Question 28

P=P1​+P2​=+2−1=+1 dioptre, lens behaves as convergent
F=1​/P=1/1​=1m=100cm

DSSSB PGT Physics Mock Test - 1 - Question 29

What percentage of the mass of an atom is concentrated in the nucleus?

Detailed Solution for DSSSB PGT Physics Mock Test - 1 - Question 29

More than 99.99% of the mass of any atom is concentrated in its nucleus. If the mass of protons and neutrons (which are in the nucleus of every atom) is approximately one atomic mass unit, then the relative mass of an electron is 0.0005 atomic mass units.

DSSSB PGT Physics Mock Test - 1 - Question 30

An electric dipole is placed along the X-axis at the origin O. A point P is at a distance of 20 cm from this origin such that OP makes an angle π/3 with the X axis. If electric field at P makes an angle θ with X-axis, the value of θ is

Detailed Solution for DSSSB PGT Physics Mock Test - 1 - Question 30




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