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EduRev Placement Test - Computer Science Engineering (CSE) MCQ


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30 Questions MCQ Test - EduRev Placement Test

EduRev Placement Test for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The EduRev Placement Test questions and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus.The EduRev Placement Test MCQs are made for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for EduRev Placement Test below.
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EduRev Placement Test - Question 1

Consider two Statements and a Question:

Statement-1: Priya is 4 ranks below Seema and is 31st from the bottom.
Statement-2: Ena is 2 ranks above Seema and is 37th from the bottom.

What is Seema’s rank from the top in the class of 40 students?
Which one of the following is correct in respect of the Statements and the Question?

Detailed Solution for EduRev Placement Test - Question 1

Given the total number of students is 40, we can determine Seema's rank using either statement:

From Statement-1: 

  • Priya is 31st from the bottom, so her rank from the top is 40 - 31 + 1 = 10.
  • Since Priya is 4 ranks below Seema, Seema's rank from the top is 10 − 4 = 6.

From Statement-2: 

  • Ena is 37th from the bottom, so her rank from the top is 40 − 37 + 1 = 4.
  • Ena is 2 ranks above Seema, so Seema's rank from the top is 4 + 2 = 6.

In both cases, Seema's rank from the top is 6. Hence, each statement alone is sufficient to answer the question.

EduRev Placement Test - Question 2

Seven books P, Q, R, S, T, U, and V are placed side by side. R, Q, and T have blue covers, and the other books have red covers. Only S and U are new books, and the rest are old. P, R, and S are law reports; the rest are Gazetteers. Books of old Gazetteers with blue covers are:

Detailed Solution for EduRev Placement Test - Question 2
  • Blue covers: R, Q, T
  • Old books: All except S and U (i.e., P, Q, R, T, V)
  • Gazetteers: All except P, R, S (i.e., Q, T, U, V)

Combining these:

  • Old Gazetteers with blue covers are Q and T.

Thus, option (C) Q and T is correct.

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EduRev Placement Test - Question 3

In the English alphabet, the first 4 letters are written in opposite order, and the next 4 letters are written in opposite order and so on; and at the end Y and Z are interchanged. Which will be the fourth letter to the right of the 13th letter?

Detailed Solution for EduRev Placement Test - Question 3

Original Alphabet Groups: ABCD EFGH IJKL MNOP QRST UVWX YZ

Reversed Groups as per the rule: DCBA HGFE LKJI PONM TSRQ XWVU ZY

Finding the 13th Letter: The sequence after reversal is: D, C, B, A, H, G, F, E, L, K, J, I, P, O, N, M, T, S, R, Q, X, W, V, U, Z, Y
The 13th letter is P.

Fourth Letter to the Right of P:
P is the 13th letter. Counting four letters to the right: O (14), N (15), M (16), T (17).
Hence, the fourth letter to the right of P is T.

EduRev Placement Test - Question 4

What is the value of X in the sequence 20, 10, 10, 15, 30, 75, X?

Detailed Solution for EduRev Placement Test - Question 4

Identifying the Pattern:

  • 20 × 0.5 = 10
  • 10 × 1 = 10
  • 10 × 1.5 = 15
  • 15 × 2 = 30
  • 30 × 2.5 = 75
  • 75 × 3 = 225

Thus, the next term X is 225.

EduRev Placement Test - Question 5

Find the next number in the sequence:

7, 11, 19, 35, 67, ?

Detailed Solution for EduRev Placement Test - Question 5

The pattern follows:
11 = 7 + 4
19 = 11 + 8
35 = 19 + 16
67 = 35 + 32
So, the next number is 67 + 64 = 131.

EduRev Placement Test - Question 6

In a certain code language ‘DEAR’ is coded as ‘7465’ and ‘LIFE’ is coded as ‘8394’. Then how will ‘IDEAL’ be coded in the same code language ?

Detailed Solution for EduRev Placement Test - Question 6

Mapping from the codes:

DEAR → 7465:

D → 7

E → 4

A → 6

R → 5

LIFE → 8394:

L → 8

I → 3

F → 9

E → 4

Code for "IDEAL":

I → 3

D → 7

E → 4

A → 6

L → 8

Final Code: 37468.

EduRev Placement Test - Question 7

Five articles K, L, P, R and T, are kept one above the other(not necessarily in the same order). K is just above T and just below R. L is just above P and just below T. Which article is at the second position from the bottom?

Detailed Solution for EduRev Placement Test - Question 7

K is just above T and just below R.

L is just above P and just below T 

So, L is placed 2nd from the bottom. 

Thus, the correct answer is L.

EduRev Placement Test - Question 8

A person bought 3 shirts. What is the total cost of the shirts?

Statements:
(1) The price of each shirt is the same.
(2) The total cost is 3 times the price of one shirt.

Detailed Solution for EduRev Placement Test - Question 8

Statement (2) directly tells us the total cost in terms of the price of one shirt. Statement (1) only confirms that all shirts have the same price, but it doesn't provide the actual cost.

EduRev Placement Test - Question 9

Find what number would come in place of the question mark(?).

Given a Series 2, 5, 12.5, ?, 78.125, 195.3125

Detailed Solution for EduRev Placement Test - Question 9

If you observe the pattern, then you can see 

2 × 2.5 = 5

5 × 2.5 = 12.5

12.5 × 2.5 = 31.25

31.25 × 2.5 =  78.125

78.125 × 2.5 = 195.3125

Hence, the correct answer is  31.25

EduRev Placement Test - Question 10

What is the average of the following set of numbers: 302, 152, 132, 122, 112?

Detailed Solution for EduRev Placement Test - Question 10

Add all the numbers in the set:
302+152+132+122+112 = 820.
Divide the sum (820) by the number of elements in the set (5):
820÷5 = 164.

EduRev Placement Test - Question 11

A train 240 meters long is moving at a speed of 72 km/h. How long will it take the train to pass a platform that is 360 meters long?

Detailed Solution for EduRev Placement Test - Question 11

The total distance to be covered by the train = length of train + length of platform = 240 m + 360 m = 600 m.
Speed of the train = 72 km/h 

(72 x 1000)/ 3600 = 20 m/s

Time = Distance/ speed = 600/ 20 = 30 seconds

EduRev Placement Test - Question 12

P and Q together can complete a work in 8 days, while Q alone can complete the same work in 12 days. In how many days can P alone complete the work?

Detailed Solution for EduRev Placement Test - Question 12

Work done by P and Q together in 1 day = 1/8

Work done by Q in 1 day = 1/12

So, work done by P in 1 day = 1/8 − 1/12 = 3 − 2 / 24 = 1/24

Thus, P can complete the work alone in 24 days.

EduRev Placement Test - Question 13

Three pipes A, B and C can fill a tank from empty to full in 30 minutes, 20 minutes, and IO minutes respectively. When the tank is empty, all the three pipes are opened. A, B and C discharge chemical solutions P, Q and R respectively. What is the proportion of the solution R in the liquid in the tank after 3 minutes?

Detailed Solution for EduRev Placement Test - Question 13

Part filled by (A + B + C) in 3 minutes

= 3(1/30 + 1/20 + 1/10) = 3 ×  11/60 = 11/20 Part  filled by C in 3 minutes = 3/10 

∴ Required ratio = 3/10 × 20/11 = 6/11

EduRev Placement Test - Question 14

A cistern has two taps attached to it. Tap B can empty the cistern in 45 minutes. But Tap A can fill the cistern in just 30 minutes. Rohit started both taps unknowingly but realized his mistake after 30 minutes. He immediately closed Tap B. Now after this, in how much time will the cistern be filled?

Detailed Solution for EduRev Placement Test - Question 14

EduRev Placement Test - Question 15

A merchant has 1000 kg of sugar part of which he sells at 8% profit and the rest at 18% profit. He gains 14% on the whole. The Quantity sold at 18% profit is ?

Detailed Solution for EduRev Placement Test - Question 15

Let x be the quantity sold at 18% profit. The rest, (1000−x), is sold at 8% profit. The overall profit is 14%.

Using the weighted average method: 

Simplifying: 

8000 - 8x + 18x = 14000

10x = 6000

X = 60

Thus, the quantity sold at 18% profit is 600 kg.

EduRev Placement Test - Question 16

In what ratio must water be mixed with milk costing Rs.12 per litre to obtain a mixture worth of Rs. 8 per litre?

Detailed Solution for EduRev Placement Test - Question 16

Let the ratio of water to milk be x : y

The cost of milk is Rs. 12 per litre, and water is free (cost = Rs. 0 per litre). The mixture is worth Rs. 8 per litre.

Using the allegation rule (a method used to calculate the ratio of two components when mixed to get a desired price):

Thus, the ratio of water to milk is 1 : 2.

Therefore, water must be mixed with milk in the ratio of 1 : 2.

EduRev Placement Test - Question 17

At present, the ratio between the ages of Haseena and Anushka is 4 : 3. After 6 years, Haseena's age will be 26 years. What is the present age of Anushka?

Detailed Solution for EduRev Placement Test - Question 17

Let the present ages of Haseena and Anushka be 4x and 3x respectively, as their age ratio is given as 4 : 3.

After 6 years, Haseena's age will be 26 years. So, we can set up the equation:

4x + 6 = 26
Solving for x:

4x = 26 − 6

4x = 20

 x = 5

Now, Anushka's present age is 3x:

3x = 3 × 5 = 15 years

Thus, Anushka's present age is 15 years.

EduRev Placement Test - Question 18

Two cards are drawn at random from a well-shuffled deck of 52 cards. What is the probability that both cards are spades?

Detailed Solution for EduRev Placement Test - Question 18

There are 13 spades in a deck. The probability of drawing the first spade is 13/52

After drawing one spade, there are 12 spades left and 51 cards in total, so the probability of drawing a second spade is 12/51.

The total probability is 13/52 x  12/51 = 1/17.

EduRev Placement Test - Question 19

At what rate of simple interest (SI) will a sum of Rs. 7000 amount to Rs. 7700 in 2 years?

Detailed Solution for EduRev Placement Test - Question 19

The rate of interest is 5% (Option D).

Explanation: The simple interest (SI) formula is: 

SI = (P x R x T)/ 100

Where:

  • P = 7000 (Principal)
  • A = 7700 (Amount)
  • T = 2 years

Step 1: Calculate SI:

SI = A − P = 7700 − 7000 = 700

Step 2: Substitute into the formula:

Thus, the rate is 5 %.

EduRev Placement Test - Question 20

Given two numbers x and y such that 

1. x3 + y3 = 9 

2. x + y = 3

Find the value of x+ y4

Detailed Solution for EduRev Placement Test - Question 20

x3+y3 = (x + y) × (x2 − xy + y2

Putting given values of x3+y3 and (x + y)

9 = 3 × ((x+y)2 − 3xy)

  = 3 × (9 − 3xy) 

  = 27 − 9xy

9xy = 18

xy = 2

x4 + y4 = (x2 + y2)2 - 2x2y2

   = (x2 + y2)2 - 2*4                [Putting value of xy]

   = ((x + y)2 - 2xy)2 - 2*4       [Putting values of (x+y) and xy]

   = (9 - 4)2 - 2*4 

   = 17

EduRev Placement Test - Question 21

What letter is next in this sequence?
O, T, T, F, F, S, S, E, ?

Detailed Solution for EduRev Placement Test - Question 21

They are all the first letters of the numbers spelt in order.
O – One
T – Two
T – Three
F – Four
F – Five
S – Six
S – Seven
E – Eight
N – Nine
So the answer is N

EduRev Placement Test - Question 22

In a row of 60 persons, Ganesh is 26th from left end. Find out his position from the right end.

Detailed Solution for EduRev Placement Test - Question 22

Short cut formula: The total number of person =  Position of Ganesh from the right ends + Position of Ganesh from the left ends – 1
Now, Position of Ganesh from the right ends = The total number of person – Position of Ganesh from the left ends + 1
= 60 – 26 + 1 = 35.
Hence, Ganesh is 35th from the right ends.
 

EduRev Placement Test - Question 23

A clock starts at noon. By 10 minutes past 5, the hour hand has turned through:

Detailed Solution for EduRev Placement Test - Question 23

Angle traced by hour hand in 12 hrs  =360
Angle traced by hour hand in 5 hrs 10 min. i.e.,

EduRev Placement Test - Question 24

A coin is tossed 3 times. Find out the number of possible outcomes.       

Detailed Solution for EduRev Placement Test - Question 24

For any multiple independent event, there are nm

total possible outcomes, where n is the number of outcomes per event, and m is the number of such events.

So for a coin, discounting the unlikely event of landing on its side, there are two possible outcomes per event, heads or tails. And it is stated that there are 3 such events. So nm=23=8

.

EduRev Placement Test - Question 25

A man rides his bicycle 10 km at an average speed of 12 km/hr and again travels 12 km at an average speed of 10 km/hr. What is his average speed for the entire trip approximately?

Detailed Solution for EduRev Placement Test - Question 25

Total Distance = 10 +12 = 22 km
Total time = 10/12 + 12/10 = 5/6 + 6/5 = 25/30 + 36/30 = 61/30 hours
Average speed = 22 /(61/30) = 660/61 = 10.8 km/ hour

EduRev Placement Test - Question 26

The sum of ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child?

Detailed Solution for EduRev Placement Test - Question 26

Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.
Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50
 5x = 20
x = 4.
Age of the youngest child = x = 4 years.

EduRev Placement Test - Question 27

One red flag, three white flags and two blue flags are arranged in a line such that,
A. no two adjacent flags are of the same colour
B. the flags at the two ends of the line are of different colours.
In how many different ways can the flags be arranged?

Detailed Solution for EduRev Placement Test - Question 27

The three white flags can be arranged in the following two ways:
__ W __ W __ W or W __ W __ W __
In the blanks, the 2 blue and one red flag can be arranged in 3 ways.
So, the total number of arrangements is 2*3 = 6

EduRev Placement Test - Question 28

If 20% of a = b, then b% of 20 is the same as:

Detailed Solution for EduRev Placement Test - Question 28

20% of a = b  => (20/100)a = b
b% of 20 =(b/100) x 20 = (20a/100) x (1/100) x (20) = 4a/100 = 4% of a.

EduRev Placement Test - Question 29

The number obtained by interchanging the two digits of a two-digit number is less than the original number by 18. The sum of the two digits of the number is 16. What is the original number?

Detailed Solution for EduRev Placement Test - Question 29

Let's assume the original two - digit number is represented by "AB," where A represents the tens digit and B represents the units digit.
According to the given in formation, we know that the number obtained by interchanging the two digits is less th the original number by 18.
This can be represented by the equation : (10A+B)−(10B+A)=18
Simplifying this equation, we get : 10A+B−10 B−A=18
9A−9B=18
A−B=2 (dividing both sides by 9 )
We also know that the sum of the two digits is 16 :
A+B=16
Now we have a system of equations :
A−B=2A+B=16​
Solving these equations simultaneously will give us the values of A and B. Adding the two equations, we get :
2A=18⇒A=9
Substituting the value of B back into one of the equations, we find: 9+B=16⇒B=7
Therefore, the original number is 97 .

EduRev Placement Test - Question 30

Arrange the words in the right order.

1. speak  
2. chance  
3. everyone  
4. got  
5. to  
6. the

Detailed Solution for EduRev Placement Test - Question 30

Everyone got the chance to speak

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